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Verilogprogramming~10 mins

Case statement for multiplexing in Verilog - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to assign output based on select signal using a case statement.

Verilog
always @(*) begin
  case(sel)
    2'b00: out = in0;
    2'b01: out = in1;
    2'b10: out = in2;
    default: out = [1];
  endcase
end
Drag options to blanks, or click blank then click option'
A1'b0
Bin3
C1'b1
Dsel
Attempts:
3 left
💡 Hint
Common Mistakes
Using an undefined signal in the default case.
Forgetting the default case causing latches.
2fill in blank
medium

Complete the case statement to select the correct input based on 2-bit select signal.

Verilog
always @(*) begin
  case([1])
    2'b00: out = in0;
    2'b01: out = in1;
    2'b10: out = in2;
    2'b11: out = in3;
  endcase
end
Drag options to blanks, or click blank then click option'
Aclk
Bout
Cin0
Dsel
Attempts:
3 left
💡 Hint
Common Mistakes
Using output or input signals as the case expression.
Using clock signal instead of select signal.
3fill in blank
hard

Fix the error in the case statement to correctly assign output based on select signal.

Verilog
always @(*) begin
  case(sel)
    2'b00: out = in0;
    2'b01: out = in1;
    2'b10: out = in2;
    2'b11: out = in3;
    default: out = [1];
  endcase
end
Drag options to blanks, or click blank then click option'
A1'b0
Bsel
C1'bx
Din4
Attempts:
3 left
💡 Hint
Common Mistakes
Assigning an undefined input in default case.
Using select signal as default output.
4fill in blank
hard

Fill both blanks to complete the case statement for a 4-to-1 multiplexer.

Verilog
always @(*) begin
  case([1])
    2'b00: out = in0;
    2'b01: out = in1;
    2'b10: out = in2;
    2'b11: out = in3;
    default: out = [2];
  endcase
end
Drag options to blanks, or click blank then click option'
Asel
B1'b0
C1'b1
Din4
Attempts:
3 left
💡 Hint
Common Mistakes
Using input signals or constants as case expression.
Assigning undefined signals in default case.
5fill in blank
hard

Fill all three blanks to complete the case statement for a 4-input multiplexer with default output zero.

Verilog
always @(*) begin
  case([1])
    2'b00: out = [2];
    2'b01: out = [3];
    2'b10: out = in2;
    2'b11: out = in3;
    default: out = 1'b0;
  endcase
end
Drag options to blanks, or click blank then click option'
Asel
Bin0
Cin1
Din4
Attempts:
3 left
💡 Hint
Common Mistakes
Mixing input signals in wrong case branches.
Using wrong variable as case expression.

Practice

(1/5)
1.

What is the main purpose of using a case statement in Verilog for multiplexing?

easy
A. To declare variables for storage
B. To create a loop that repeats operations
C. To define timing delays in the circuit
D. To select one input from many based on a selector signal

Solution

  1. Step 1: Understand multiplexing concept

    Multiplexing means choosing one input out of many based on a selector signal.
  2. Step 2: Role of case statement

    The case statement in Verilog is used to pick one input depending on the selector value.
  3. Final Answer:

    To select one input from many based on a selector signal -> Option D
  4. Quick Check:

    Multiplexer selection = case statement use [OK]
Hint: Case picks input based on selector signal [OK]
Common Mistakes:
  • Confusing case with loops
  • Using case for variable declaration
  • Thinking case defines timing
2.

Which of the following is the correct syntax to start a case statement for a 2-bit selector sel in Verilog?

?
easy
A. case(sel) begin
B. case sel {
C. case(sel)
D. switch(sel) {

Solution

  1. Step 1: Recall Verilog case syntax

    The correct syntax to start a case statement is case(expression) without extra keywords or braces.
  2. Step 2: Check options

    case(sel) matches the correct syntax exactly: case(sel).
  3. Final Answer:

    case(sel) -> Option C
  4. Quick Check:

    Verilog case syntax = case(expression) [OK]
Hint: Use parentheses around selector in case [OK]
Common Mistakes:
  • Adding 'begin' after case
  • Using braces {} like other languages
  • Using 'switch' instead of 'case'
3.

Given the following Verilog code, what is the value of out when sel = 2'b10?

module mux_example(input [1:0] sel, input a, b, c, d, output reg out);
  always @(*) begin
    case(sel)
      2'b00: out = a;
      2'b01: out = b;
      2'b10: out = c;
      default: out = d;
    endcase
  end
endmodule
medium
A. Value of input b
B. Value of input c
C. Value of input a
D. Value of input d

Solution

  1. Step 1: Identify selector value

    The selector sel is 2'b10, which matches the third case.
  2. Step 2: Match case to output

    For 2'b10, the output out is assigned the value of input c.
  3. Final Answer:

    Value of input c -> Option B
  4. Quick Check:

    sel=2'b10 selects c [OK]
Hint: Match selector bits to case labels [OK]
Common Mistakes:
  • Choosing default instead of matching case
  • Mixing up input variables
  • Ignoring binary selector format
4.

Identify the error in this Verilog case statement used for multiplexing:

always @(*) begin
  case(sel)
    2'b00: out = a;
    2'b01: out = b;
    2'b10: out = c;
  endcase
end
medium
A. Missing default case for unmatched selector values
B. Incorrect use of always block sensitivity list
C. Wrong assignment operator used
D. Selector signal sel is not declared

Solution

  1. Step 1: Check case completeness

    The case statement covers 2'b00, 2'b01, and 2'b10 but misses 2'b11.
  2. Step 2: Importance of default case

    Without a default case, the output out may hold previous value or be undefined for unmatched selectors.
  3. Final Answer:

    Missing default case for unmatched selector values -> Option A
  4. Quick Check:

    Always include default in case [OK]
Hint: Always add default case in multiplexers [OK]
Common Mistakes:
  • Forgetting default case
  • Using wrong sensitivity list (@posedge instead of @(*) )
  • Using '=' instead of '<=' in combinational logic
5.

You want to design a 4-to-1 multiplexer using a case statement in Verilog. Which of the following code snippets correctly implements this with inputs a, b, c, d, selector sel, and output out?

?
hard
A. always @(*) begin case(sel) 2'b00: out = a; 2'b01: out = b; 2'b10: out = c; 2'b11: out = d; default: out = 1'b0; endcase end
B. always @(sel) begin case(sel) 2'b00: out = a; 2'b01: out = b; 2'b10: out = c; default: out = d; endcase end
C. always @(*) begin if(sel == 2'b00) out = a; else if(sel == 2'b01) out = b; else if(sel == 2'b10) out = c; else out = d; end
D. always @(*) begin case(sel) 0: out = a; 1: out = b; 2: out = c; 3: out = d; endcase end

Solution

  1. Step 1: Check sensitivity list

    always @(*) begin case(sel) 2'b00: out = a; 2'b01: out = b; 2'b10: out = c; 2'b11: out = d; default: out = 1'b0; endcase end uses always @(*), which is correct for combinational logic multiplexers.
  2. Step 2: Verify case labels and default

    always @(*) begin case(sel) 2'b00: out = a; 2'b01: out = b; 2'b10: out = c; 2'b11: out = d; default: out = 1'b0; endcase end covers all 4 selector values (2'b00 to 2'b11) and includes a default case to avoid latches.
  3. Step 3: Compare other options

    always @(sel) begin case(sel) 2'b00: out = a; 2'b01: out = b; 2'b10: out = c; default: out = d; endcase end misses 2'b11 case explicitly and uses always @(sel) which is less recommended. always @(*) begin if(sel == 2'b00) out = a; else if(sel == 2'b01) out = b; else if(sel == 2'b10) out = c; else out = d; end uses if-else, not case. always @(*) begin case(sel) 0: out = a; 1: out = b; 2: out = c; 3: out = d; endcase end uses decimal labels without binary format and misses default.
  4. Final Answer:

    Option A code snippet -> Option A
  5. Quick Check:

    Complete case with default and always @(*) = always @(*) begin case(sel) 2'b00: out = a; 2'b01: out = b; 2'b10: out = c; 2'b11: out = d; default: out = 1'b0; endcase end [OK]
Hint: Use always @(*) and include default case [OK]
Common Mistakes:
  • Omitting default case
  • Using incomplete case labels
  • Wrong sensitivity list
  • Mixing if-else with case question
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