mux4to1 with inputs and output as specifiedcase statement inside an always block to implement the multiplexing logicin0, in1, in2, in3sel to select which input to outputout that reflects the selected inputmux4to1 with inputs and output as specifiedcase statement inside an always block to implement the multiplexing logicin0, in1, in2, in3sel to select which input to outputout that reflects the selected inputmux4to1 with four 4-bit inputs called in0, in1, in2, in3, a 2-bit input called sel, and a 4-bit output called out. Declare out as reg.Remember to declare out as reg because it will be assigned inside an always block.
mux4to1 module, add an always block that is sensitive to changes in sel, in0, in1, in2, and in3.The always block should react to changes in the selector and all inputs.
always block, write a case statement on sel that assigns out to in0 when sel is 0, in1 when sel is 1, in2 when sel is 2, and in3 when sel is 3. Include a default case that assigns out to 4'b0000.Use binary values for sel cases and assign out accordingly.
test_mux4to1 that instantiates mux4to1. Assign in0 = 4'b0001, in1 = 4'b0010, in2 = 4'b0100, in3 = 4'b1000. Change sel from 0 to 3 in steps, and use $display to print sel and out. Run the testbench to show the output.Assign the inputs with the given values, change sel step by step, wait a little with #10, and print the values using $display.
What is the main purpose of using a case statement in Verilog for multiplexing?
case statement in Verilog is used to pick one input depending on the selector value.Which of the following is the correct syntax to start a case statement for a 2-bit selector sel in Verilog?
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case(expression) without extra keywords or braces.case(sel).Given the following Verilog code, what is the value of out when sel = 2'b10?
module mux_example(input [1:0] sel, input a, b, c, d, output reg out);
always @(*) begin
case(sel)
2'b00: out = a;
2'b01: out = b;
2'b10: out = c;
default: out = d;
endcase
end
endmodulesel is 2'b10, which matches the third case.2'b10, the output out is assigned the value of input c.Identify the error in this Verilog case statement used for multiplexing:
always @(*) begin
case(sel)
2'b00: out = a;
2'b01: out = b;
2'b10: out = c;
endcase
enddefault case, the output out may hold previous value or be undefined for unmatched selectors.You want to design a 4-to-1 multiplexer using a case statement in Verilog. Which of the following code snippets correctly implements this with inputs a, b, c, d, selector sel, and output out?
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always @(*), which is correct for combinational logic multiplexers.always @(sel) which is less recommended. always @(*) begin
if(sel == 2'b00) out = a;
else if(sel == 2'b01) out = b;
else if(sel == 2'b10) out = c;
else out = d;
end uses if-else, not case. always @(*) begin
case(sel)
0: out = a;
1: out = b;
2: out = c;
3: out = d;
endcase
end uses decimal labels without binary format and misses default.Pass the test and this pattern moves unknown