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VHDLprogramming~10 mins

Shift operators in VHDL - Step-by-Step Execution

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Concept Flow - Shift operators
Input Vector
Select Shift Type
Shift Left
Shift Bits by N Positions
Output Shifted Vector
The input vector is shifted left or right by a specified number of positions, producing a new shifted vector as output.
Execution Sample
VHDL
signal data_in : std_logic_vector(7 downto 0) := "10110011";
signal data_out : std_logic_vector(7 downto 0);

-- Shift left by 2
 data_out <= data_in sll 2;
This code shifts the 8-bit vector data_in left by 2 positions and stores the result in data_out.
Execution Table
StepOperationInput VectorShift AmountResult VectorExplanation
1Initial value10110011N/A10110011Starting vector before shift
2Shift left by 210110011211001100Bits shifted left 2 places, zeros fill right
3Shift right by 310110011300010110Bits shifted right 3 places, zeros fill left
4Shift left by 010110011010110011Shift by zero leaves vector unchanged
5Shift right by 810110011800000000Shift by full length results in all zeros
💡 All shifts complete; output vectors show shifted results with zeros filling vacated bits.
Variable Tracker
VariableStartAfter Shift Left 2After Shift Right 3After Shift Left 0After Shift Right 8
data_in1011001110110011101100111011001110110011
data_outundefined11001100000101101011001100000000
Key Moments - 3 Insights
Why do zeros fill in the bits when shifting?
In VHDL shift operators, when bits move out of the vector range, zeros fill the empty positions to keep the vector size constant, as shown in execution_table rows 2 and 3.
What happens if the shift amount is zero?
If the shift amount is zero, the vector remains unchanged, as seen in execution_table row 4 where the output equals the input.
Why does shifting right by the vector length produce all zeros?
Shifting right by the full vector length moves all bits out, leaving only zeros, demonstrated in execution_table row 5.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table, what is data_out after shifting left by 2?
A00010110
B11001100
C10110011
D00000000
💡 Hint
Check execution_table row 2 under Result Vector.
At which step does shifting right produce '00010110'?
AStep 3
BStep 2
CStep 4
DStep 5
💡 Hint
Look at execution_table row 3 for the Result Vector.
If we shift left by 8 on an 8-bit vector, what would data_out be?
AOriginal vector unchanged
BVector shifted left by 1
CAll zeros
DVector shifted right by 8
💡 Hint
Refer to the pattern in execution_table row 5 for full-length shifts.
Concept Snapshot
Shift operators in VHDL move bits left (sll) or right (srl).
Bits shifted out are lost; zeros fill the empty positions.
Syntax: result <= input_vector sll n; or srl n;
Shift amount n must be integer.
Shifting by zero leaves vector unchanged.
Shifting by vector length results in all zeros.
Full Transcript
This visual execution trace shows how VHDL shift operators work on an 8-bit vector. The vector is shifted left or right by a given number of positions. When bits move out of the vector, zeros fill the empty spots to keep the size the same. For example, shifting left by 2 moves bits two places left and adds zeros on the right. Shifting right by 3 moves bits three places right and adds zeros on the left. Shifting by zero does not change the vector. Shifting by the full vector length results in all zeros. The variable tracker shows how data_in stays the same while data_out changes after each shift. Key moments clarify why zeros fill in and what happens with zero or full-length shifts. The quiz questions help check understanding by referencing the execution steps and results.