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Combined Standard Deviation (Two Data Sets)

Introduction

சில நேரங்களில், இரண்டு தனித்தனி observation groups ஒன்றாக இணைக்கப்படும் போது, அவற்றின் combined standard deviation ஐ கண்டறிய வேண்டும். combined SD என்பது ஒவ்வொரு group இன் size, mean மற்றும் variance ஆகியவற்றை பயன்படுத்துகிறது - இது group உள்ளேயான spread மற்றும் group means இடையிலான மாற்றத்தையும் கணக்கில் எடுத்துக்கொள்கிறது.

class scores, batch measurements, அல்லது இரண்டு subgroups இன் sample results ஒன்றாக சேர்க்கப்படும் problems இல் இந்த pattern மிகவும் முக்கியமானது.

Pattern: Combined Standard Deviation (Two Data Sets)

Pattern

Key concept: Combined variance = (ஒவ்வொரு group இன் variance + group mean மற்றும் combined mean இடையிலான squared difference) ஆகியவற்றின் weighted sum ÷ total size. SD = combined variance இன் square root.

Group 1 க்கு size n₁, mean x̄₁, SD σ₁ உள்ளது.
Group 2 க்கு size n₂, mean x̄₂, SD σ₂ உள்ளது.

Combined mean:
x̄ = (n₁ × x̄₁ + n₂ × x̄₂) ÷ (n₁ + n₂)

Combined variance formula:
σ² = [ n₁ × (σ₁² + (x̄₁ - x̄)²) + n₂ × (σ₂² + (x̄₂ - x̄)²) ] ÷ (n₁ + n₂)
Combined standard deviation:
σ = √σ²

Step-by-Step Example

Question

Class A: n₁ = 10 students, mean = 50, SD = 4.
Class B: n₂ = 15 students, mean = 55, SD = 5.
அனைத்து 25 students க்கும் combined mean மற்றும் combined standard deviation ஐ கண்டறியுங்கள்.

Solution

  1. Step 1: combined mean x̄ ஐ கணக்கிடுங்கள்

    x̄ = (n₁ × x̄₁ + n₂ × x̄₂) ÷ (n₁ + n₂)
    = (10 × 50 + 15 × 55) ÷ 25
    = (500 + 825) ÷ 25 = 1,325 ÷ 25 = 53.

  2. Step 2: group means மற்றும் combined mean இடையிலான squared deviations ஐ கணக்கிடுங்கள்

    (x̄₁ - x̄) = 50 - 53 = -3 → (x̄₁ - x̄)² = 9.
    (x̄₂ - x̄) = 55 - 53 = 2 → (x̄₂ - x̄)² = 4.

  3. Step 3: ஒவ்வொரு group க்கும் n × (σ² + (x̄ - x̄)²) ஐ உருவாக்குங்கள்

    Group A க்கு: n₁ × (σ₁² + (x̄₁ - x̄)²) = 10 × (4² + 9) = 10 × (16 + 9) = 10 × 25 = 250.
    Group B க்கு: n₂ × (σ₂² + (x̄₂ - x̄)²) = 15 × (5² + 4) = 15 × (25 + 4) = 15 × 29 = 435.

  4. Step 4: கூட்டி total size மூலம் வகுத்து combined variance ஐ பெறுங்கள்

    Total = 250 + 435 = 685.
    Combined variance σ² = 685 ÷ (10 + 15) = 685 ÷ 25 = 27.4.

  5. Step 5: combined SD க்கு square root எடுக்குங்கள்

    Combined SD σ = √27.4 ≈ 5.24.

  6. Final Answer:

    Combined Mean = 53
    Combined SD ≈ 5.24

  7. Quick Check:

    Combined mean (53) என்பது 50 மற்றும் 55 இடையில் உள்ளது - Class B க்கு அருகில் (students அதிகம்).
    Combined SD (≈5.24) என்பது 4 மற்றும் 5 இடையில் உள்ளது - mean difference காரணமாக சிறிது அதிகம் ✅

Quick Variations

1. Group sizes சமமாக இருந்தால் (n₁ = n₂), combined mean = means இன் simple average.

2. Group means சமமாக இருந்தால் (x̄₁ = x̄₂), combined variance = [n₁σ₁² + n₂σ₂²] ÷ (n₁ + n₂) ஆக எளிதாகும்.

3. இரண்டு group களை விட அதிகமான groups இருந்தால், எல்லா groups க்கும் nᵢ(σᵢ² + (x̄ᵢ - x̄)²) ஐ கூட்டி, total N மூலம் வகுக்கவும்.

Trick to Always Use

  • Step 1: எப்போதும் முதலில் combined mean ஐ கணக்கிடுங்கள் - அது formula இல் தேவையானது.
  • Step 2: ஒவ்வொரு bracket இலும் இரண்டு பகுதிகள் உள்ளன என்பதை நினைவில் கொள்ளுங்கள்: within-group variance மற்றும் between-group difference.
  • Step 3: பெரிய groups (n அதிகம்) combined SD மீது அதிக தாக்கம் செலுத்தும்.

Summary

Summary

Combined Standard Deviation (Two Data Sets) pattern இல்:

  • Combined Mean: (n₁x̄₁ + n₂x̄₂) ÷ (n₁ + n₂)
  • Combined Variance: [ n₁(σ₁² + (x̄₁ - x̄)²) + n₂(σ₂² + (x̄₂ - x̄)²) ] ÷ (n₁ + n₂)
  • Combined SD = √(Combined Variance)
  • இந்த formula, within-group spread மற்றும் between-group mean differences இரண்டையும் கணக்கில் எடுத்துக்கொள்கிறது.

Practice

(1/5)
1. Class A has 20 students with Mean = 60 and SD = 4. Class B has 30 students with Mean = 65 and SD = 5. Find the combined Mean of both classes.
easy
A. 63.0
B. 62.5
C. 64.0
D. 61.5

Solution

  1. Step 1: Identify values

    n₁ = 20, x̄₁ = 60; n₂ = 30, x̄₂ = 65.

  2. Step 2: Apply combined mean formula

    x̄ = (n₁×x̄₁ + n₂×x̄₂) ÷ (n₁ + n₂) = (20×60 + 30×65) ÷ 50 = (1,200 + 1,950) ÷ 50 = 3,150 ÷ 50 = 63.0.

  3. Final Answer:

    Combined Mean = 63.0 → Option A.

  4. Quick Check:

    63 lies between 60 and 65 and is closer to 65 (larger group) - consistent ✅

Hint: Use weighted average: larger group pulls the combined mean toward its mean.
Common Mistakes: Taking simple average of the two means instead of weighting by group sizes.
2. Two groups have means 40 and 50 with equal sizes of 10 each. Find the combined mean.
easy
A. 44
B. 45
C. 48
D. 46

Solution

  1. Step 1: Note equal sizes

    When group sizes are equal, combined mean = (mean₁ + mean₂) ÷ 2.

  2. Step 2: Compute

    (40 + 50) ÷ 2 = 45.

  3. Final Answer:

    Combined Mean = 45 → Option B.

  4. Quick Check:

    45 is midway between 40 and 50 ✅

Hint: If group sizes equal, take simple average of means.
Common Mistakes: Applying weights when sizes are equal (unnecessary).
3. Group A: n₁ = 10, Mean = 70, SD = 3; Group B: n₂ = 20, Mean = 75, SD = 4. Find the combined Mean.
easy
A. 72.5
B. 74.0
C. 73.33
D. 76.0

Solution

  1. Step 1: Apply weighted mean formula

    x̄ = (n₁×x̄₁ + n₂×x̄₂) ÷ (n₁ + n₂) = (10×70 + 20×75) ÷ 30.

  2. Step 2: Compute

    (700 + 1,500) ÷ 30 = 2,200 ÷ 30 = 73.33 (rounded to 2 decimals).

  3. Final Answer:

    Combined Mean ≈ 73.33 → Option C.

  4. Quick Check:

    Value lies between 70 and 75 and is closer to 75 (larger group) ✅

Hint: Larger group’s mean has greater influence on combined mean.
Common Mistakes: Using simple average instead of weighted average.
4. Class X: n₁ = 12, Mean = 50, SD = 3. Class Y: n₂ = 18, Mean = 55, SD = 4. Find the combined Standard Deviation (rounded to 2 decimals).
medium
A. 3.80
B. 4.00
C. 4.50
D. 4.38

Solution

  1. Step 1: Compute combined mean

    x̄ = (12×50 + 18×55) ÷ 30 = (600 + 990) ÷ 30 = 1,590 ÷ 30 = 53.

  2. Step 2: Compute group contributions

    For X: σ₁² = 3² = 9; (x̄₁ - x̄)² = (50 - 53)² = 9 → term = 12×(9 + 9) = 12×18 = 216.
    For Y: σ₂² = 4² = 16; (x̄₂ - x̄)² = (55 - 53)² = 4 → term = 18×(16 + 4) = 18×20 = 360.

  3. Step 3: Combined variance and SD

    Sum = 216 + 360 = 576. Combined variance = 576 ÷ 30 = 19.2. Combined SD = √19.2 ≈ 4.38.

  4. Final Answer:

    Combined SD ≈ 4.38 → Option D.

  5. Quick Check:

    Combined SD ≈ 4.38 lies between 4 and 5 and is increased by the between-group difference - reasonable ✅

Hint: Include both within-group variance and squared mean differences when combining.
Common Mistakes: Ignoring the between-group term (x̄ᵢ - x̄)².
5. Two departments have the following data: Dept A: n₁ = 25, Mean = 80, SD = 5; Dept B: n₂ = 15, Mean = 70, SD = 4. Find the combined SD (rounded to 2 decimals).
medium
A. 6.72
B. 5.25
C. 6.00
D. 5.50

Solution

  1. Step 1: Combined mean

    x̄ = (25×80 + 15×70) ÷ 40 = (2,000 + 1,050) ÷ 40 = 3,050 ÷ 40 = 76.25.

  2. Step 2: Compute group contributions

    Dept A: σ₁² = 25; (x̄₁ - x̄)² = (80 - 76.25)² = 3.75² = 14.0625 → term = 25×(25 + 14.0625) = 25×39.0625 = 976.5625.
    Dept B: σ₂² = 16; (x̄₂ - x̄)² = (70 - 76.25)² = (-6.25)² = 39.0625 → term = 15×(16 + 39.0625) = 15×55.0625 = 825.9375.

  3. Step 3: Combined variance and SD

    Sum = 976.5625 + 825.9375 = 1,802.5. Combined variance = 1,802.5 ÷ 40 = 45.0625. Combined SD = √45.0625 ≈ 6.72.

  4. Final Answer:

    Combined SD ≈ 6.72 → Option A.

  5. Quick Check:

    Result is closer to the larger group’s SD but increased due to mean difference - makes sense ✅

Hint: Compute weighted sum of (variance + squared mean-difference) then divide by total N and square-root.
Common Mistakes: Forgetting to multiply each group's term by its size before summing.

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