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C Sharp (C#)programming~3 mins

Why Switch expressions with patterns in C Sharp (C#)? - Purpose & Use Cases

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The Big Idea

What if you could replace long, messy if-else chains with a neat, powerful one-liner that understands your data?

The Scenario

Imagine you have a list of different shapes, and you want to find their areas. Without patterns, you write many if-else statements checking each shape type and calculating the area separately.

The Problem

This manual way is long, hard to read, and easy to make mistakes. Adding new shapes means adding more if-else blocks, making the code messy and confusing.

The Solution

Switch expressions with patterns let you match shapes by type and properties in a clean, concise way. You write all cases in one place, making the code easier to read and extend.

Before vs After
✗ Before
if (shape is Circle) { area = Math.PI * ((Circle)shape).Radius * ((Circle)shape).Radius; } else if (shape is Rectangle) { area = ((Rectangle)shape).Width * ((Rectangle)shape).Height; } else { area = 0; }
✓ After
area = shape switch { Circle c => Math.PI * c.Radius * c.Radius, Rectangle r => r.Width * r.Height, _ => 0 };
What It Enables

You can write clearer, shorter code that handles many cases smoothly and is easy to update.

Real Life Example

In a drawing app, you can quickly calculate areas or colors of different shapes using switch expressions with patterns, making the app faster to develop and maintain.

Key Takeaways

Manual if-else chains are long and error-prone.

Switch expressions with patterns simplify matching by type and properties.

Code becomes cleaner, easier to read, and extend.

Practice

(1/5)
1. What does a switch expression with patterns in C# primarily help you do?
easy
A. Create loops that run a fixed number of times
B. Declare variables with dynamic types
C. Match values and types cleanly without long if-else chains
D. Handle exceptions in asynchronous code

Solution

  1. Step 1: Understand switch expressions

    Switch expressions allow matching on values or types in a concise way.
  2. Step 2: Compare with if-else chains

    They replace long if-else chains with clearer, more readable code.
  3. Final Answer:

    Match values and types cleanly without long if-else chains -> Option C
  4. Quick Check:

    Switch expressions = clean matching [OK]
Hint: Switch expressions simplify matching values and types [OK]
Common Mistakes:
  • Confusing switch expressions with loops
  • Thinking switch expressions handle exceptions
  • Believing switch expressions declare variables
2. Which of the following is the correct syntax for a switch expression with a type pattern in C#?
easy
A. var result = obj switch { int i => i * 2, string s => s.Length, _ => 0 };
B. var result = switch obj { int i => i * 2, string s => s.Length, _ => 0 };
C. var result = obj { int i => i * 2, string s => s.Length, _ => 0 } switch;
D. var result = obj switch (int i => i * 2, string s => s.Length, _ => 0);

Solution

  1. Step 1: Identify correct switch expression syntax

    The switch expression syntax is: variable switch { pattern => result, ... }.
  2. Step 2: Match options to syntax

    var result = obj switch { int i => i * 2, string s => s.Length, _ => 0 }; matches this syntax exactly with type patterns and a discard pattern.
  3. Final Answer:

    var result = obj switch { int i => i * 2, string s => s.Length, _ => 0 }; -> Option A
  4. Quick Check:

    Correct switch expression syntax = var result = obj switch { int i => i * 2, string s => s.Length, _ => 0 }; [OK]
Hint: Remember: variable switch { patterns } is correct syntax [OK]
Common Mistakes:
  • Placing switch before the variable
  • Using parentheses instead of braces
  • Misplacing the switch keyword
3. What is the output of the following C# code?
object value = 5;
string result = value switch
{
  int i when i > 0 => "Positive integer",
  int i when i < 0 => "Negative integer",
  string s => "String",
  _ => "Unknown"
};
Console.WriteLine(result);
medium
A. Negative integer
B. Positive integer
C. String
D. Unknown

Solution

  1. Step 1: Analyze the switch expression input

    The variable 'value' is an object holding the integer 5.
  2. Step 2: Match patterns in order

    First pattern matches int i when i > 0, which is true for 5, so result is "Positive integer".
  3. Final Answer:

    Positive integer -> Option B
  4. Quick Check:

    5 > 0 matches first pattern [OK]
Hint: Check pattern order and conditions carefully [OK]
Common Mistakes:
  • Ignoring the 'when' condition
  • Assuming string pattern matches first
  • Choosing default case incorrectly
4. Identify the error in this switch expression code snippet:
object obj = "hello";
var output = obj switch
{
  int i => i.ToString(),
  string s => s.ToUpper(),
  default => "none"
};
medium
A. Patterns must be in parentheses
B. Missing semicolon after switch expression
C. Cannot switch on object type
D. Using 'default' instead of '_' for discard pattern

Solution

  1. Step 1: Check switch expression patterns

    In C# switch expressions, the discard pattern uses '_' not 'default'.
  2. Step 2: Identify the incorrect pattern usage

    The code uses 'default' which causes a syntax error; it should be '_'.
  3. Final Answer:

    Using 'default' instead of '_' for discard pattern -> Option D
  4. Quick Check:

    Discard pattern = '_' not 'default' [OK]
Hint: Use '_' for default case in switch expressions [OK]
Common Mistakes:
  • Using 'default' keyword in switch expressions
  • Confusing switch statements with switch expressions
  • Forgetting to end statements with semicolon
5. Given a list of objects, write a switch expression that returns:
- "Number" if the object is an int or double
- "Text" if the object is a non-empty string
- "Empty" if the object is an empty string
- "Other" for anything else

Which of the following switch expressions correctly implements this logic?
hard
A. obj switch { int _ or double _ => "Number", string s when s.Length == 0 => "Empty", string s when s.Length > 0 => "Text", _ => "Other" }
B. obj switch { int or double => "Number", string s when s == "" => "Empty", string s when s != "" => "Text", _ => "Other" }
C. obj switch { int or double => "Number", string s when s.Length > 0 => "Text", string s when s.Length == 0 => "Empty", _ => "Other" }
D. obj switch { int or double => "Number", string s when s != "" => "Text", string s when s == "" => "Empty", _ => "Other" }

Solution

  1. Step 1: Understand type patterns and conditions

    We must match int or double first, then string with length checks for empty/non-empty.
  2. Step 2: Check order and conditions

    obj switch { int _ or double _ => "Number", string s when s.Length == 0 => "Empty", string s when s.Length > 0 => "Text", _ => "Other" } correctly checks int or double, then string with Length == 0 for "Empty", then Length > 0 for "Text", then default.
  3. Final Answer:

    obj switch { int _ or double _ => "Number", string s when s.Length == 0 => "Empty", string s when s.Length > 0 => "Text", _ => "Other" } -> Option A
  4. Quick Check:

    Order and conditions matter in switch patterns [OK]
Hint: Order patterns from specific to general, check string length for empty [OK]
Common Mistakes:
  • Using 'or' incorrectly without parentheses
  • Checking string emptiness with == "" instead of Length
  • Placing empty string check after non-empty
Recommended

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