Expression-bodied lambdas in C Sharp (C#)

Introduction

Expression-bodied lambdas let you write short functions in a simple, clean way using just one expression.

When you want to write a quick function that returns a value without many lines.

When you need to pass a small function as an argument to another method.

When you want to make your code easier to read by avoiding extra braces and return statements.

Syntax

C Sharp (C#)

(parameters) => expression

The expression after the arrow is the value returned automatically.

No need for curly braces or explicit return keyword for single expressions.

Examples

A lambda that takes one parameter x and returns x squared.

C Sharp (C#)

x => x * x

A lambda that takes two parameters and returns their sum.

C Sharp (C#)

(a, b) => a + b

A lambda with no parameters that returns the current date and time.

C Sharp (C#)

() => DateTime.Now

Sample Program

This program shows three expression-bodied lambdas: one to square a number, one to add two numbers, and one to return a greeting message.

C Sharp (C#)

using System;

class Program
{
    static void Main()
    {
        Func<int, int> square = x => x * x;
        Func<int, int, int> add = (a, b) => a + b;
        Func<string> greet = () => "Hello!";

        Console.WriteLine(square(5));
        Console.WriteLine(add(3, 4));
        Console.WriteLine(greet());
    }
}

Important Notes

Expression-bodied lambdas are great for simple logic but use regular lambdas with braces for multiple statements.

They help keep your code short and easy to read.

Summary

Expression-bodied lambdas use a single expression after the arrow to return a value.

They simplify writing short functions without braces or return statements.

Useful for quick, readable code especially when passing functions as arguments.

Practice

1. What is the main purpose of using an expression-bodied lambda in C#?

easy

A. To write a short function with a single expression without braces or return keyword

B. To declare a variable with a complex type

C. To create a class with multiple methods

D. To handle exceptions in a concise way

Solution

1. Step 1: Understand expression-bodied lambda syntax

   Expression-bodied lambdas use the => operator followed by a single expression, simplifying function syntax.

2. Step 2: Identify the purpose

   This syntax is used to write short functions without braces or explicit return statements.

3. Final Answer:

   To write a short function with a single expression without braces or return keyword -> Option A

4. Quick Check:

   Expression-bodied lambda = short single-expression function [OK]

Hint: Remember: expression-bodied lambdas simplify single-expression functions [OK]

Common Mistakes:

• Confusing with variable declarations
• Thinking it creates classes or handles exceptions
• Assuming it requires braces and return keyword

2. Which of the following is the correct syntax for an expression-bodied lambda that adds two integers a and b?

easy

A. (a, b) => a + b

B. (a, b) => a + b;

C. (a, b) => { return a + b; }

D. (a, b) => { a + b }

Solution

1. Step 1: Identify expression-bodied lambda syntax

   Expression-bodied lambdas use => followed by a single expression without braces or return keyword.

2. Step 2: Check each option

   (a, b) => a + b correctly uses (a, b) => a + b without braces or return. (a, b) => { return a + b; } uses braces and return (not expression-bodied). (a, b) => a + b; has a semicolon after expression (not needed). (a, b) => { a + b } uses braces without return (invalid).

3. Final Answer:

   (a, b) => a + b -> Option A

4. Quick Check:

   Expression-bodied lambda syntax = (params) => expression [OK]

Hint: No braces or return keyword in expression-bodied lambdas [OK]

Common Mistakes:

• Adding braces and return keyword
• Including semicolon after expression
• Using braces without return keyword

3. What is the output of the following C# code?

Func<int, int> square = x => x * x;
Console.WriteLine(square(4));

medium

A. 8

B. 4

C. 16

D. Compilation error

Solution

1. Step 1: Understand the lambda function

   The lambda expression x => x * x defines a function that returns the square of x.

2. Step 2: Evaluate the function call

   Calling square(4) computes 4 * 4 = 16.

3. Final Answer:

   16 -> Option C

4. Quick Check:

   4 squared = 16 [OK]

Hint: Multiply input by itself to get square [OK]

Common Mistakes:

• Confusing output with input
• Expecting compilation error
• Misreading the lambda expression

4. Identify the error in the following expression-bodied lambda:

Func<int, int> increment = x => { x + 1; };

medium

A. Semicolon after expression is invalid

B. Braces are not allowed in expression-bodied lambdas

C. Lambda must have two parameters

D. Missing return keyword inside braces

Solution

1. Step 1: Analyze the lambda syntax

   The lambda uses braces, so it must have an explicit return statement to return a value.

2. Step 2: Identify the missing return

   Inside braces, the expression x + 1 is evaluated but not returned, causing a compile error.

3. Final Answer:

   Missing return keyword inside braces -> Option D

4. Quick Check:

   Braces require return keyword [OK]

Hint: Use return inside braces or remove braces for expression-bodied lambda [OK]

Common Mistakes:

• Assuming braces are disallowed
• Thinking semicolon after expression is invalid
• Expecting multiple parameters

5. Given a list of integers, which expression-bodied lambda correctly filters out even numbers and returns their squares?

var numbers = new List<int> {1, 2, 3, 4, 5};
var result = numbers.Where( /* lambda here */ ).Select(x => x * x).ToList();

hard

A. x => x % 2 == 0

B. x => x % 2 != 0

C. x => { return x % 2 != 0; }

D. x => { x % 2 != 0; }

Solution

1. Step 1: Understand filtering condition

   We want to keep odd numbers, so the condition is x % 2 != 0.

2. Step 2: Choose correct lambda syntax

   x => x % 2 != 0 uses expression-bodied lambda without braces, correctly returning the condition. x => x % 2 == 0 keeps even numbers (wrong). x => { return x % 2 != 0; } uses braces with return (valid but not expression-bodied). x => { x % 2 != 0; } uses braces without return (invalid).

3. Final Answer:

   x => x % 2 != 0 -> Option B

4. Quick Check:

   Filter odds with expression-bodied lambda [OK]

Hint: No braces and return for expression-bodied lambdas [OK]

Common Mistakes:

• Using braces without return
• Choosing wrong condition for filtering
• Mixing expression-bodied with block-bodied syntax