Sometimes, you want to know what kind of thing (type) a variable or object is while the program is running. This helps you make decisions or handle data correctly.
When you want to check if an object is a certain type before using it.
When you need to print or log the type of an object for debugging.
When writing code that works with different types and needs to behave differently.
When you want to get the name of a type to display to users or save in files.
Syntax
C Sharp (C#)
Type typeInfo = obj.GetType();
string typeName = obj.GetType().Name;
GetType() is a method that tells you the exact type of an object.
You can get the full type info or just the name using Name property.
Examples
This prints the full type of number, which is System.Int32.
C Sharp (C#)
int number = 5;
Type typeInfo = number.GetType();
Console.WriteLine(typeInfo);
This prints just the name of the type, which is String.
C Sharp (C#)
string text = "hello";
Console.WriteLine(text.GetType().Name);
This checks if obj is a double and prints a message.
C Sharp (C#)
object obj = 3.14;
if (obj.GetType() == typeof(double))
{
Console.WriteLine("It's a double!");
}
Sample Program
This program loops through different items, gets their type at runtime, and prints both the value and its type name.
C Sharp (C#)
using System;
class Program
{
staticvoid Main()
{
object[] items = { 42, "apple", 3.14, true };
foreach (var item in items)
{
Type type = item.GetType();
Console.WriteLine($"Value: {item}, Type: {type.Name}");
}
}
}
OutputSuccess
Important Notes
Using GetType() works only on objects, so value types like int are boxed when used this way.
You can compare types using == and typeof() to check for specific types.
Summary
GetType() tells you the exact type of an object while the program runs.
You can use the type info to make decisions or show type names.
Comparing types helps you handle different data safely.
Practice
(1/5)
1. What does the GetType() method do in C#?
easy
A. Changes the type of an object
B. Creates a new object of a specified type
C. Returns the exact runtime type of an object
D. Deletes the object from memory
Solution
Step 1: Understand the purpose of GetType()
The GetType() method is used to find out the exact type of an object while the program is running.
Step 2: Differentiate from other actions
It does not change, create, or delete objects; it only returns type information.
Final Answer:
Returns the exact runtime type of an object -> Option C
Quick Check:
GetType() returns type info [OK]
Hint: Remember: GetType() tells you what type an object is [OK]
Common Mistakes:
Thinking GetType() changes the object
Confusing GetType() with creating objects
Assuming GetType() deletes objects
2. Which of the following is the correct syntax to get the type of an object obj in C#?
easy
A. obj.GetType()
B. GetType(obj)
C. typeof(obj)
D. obj.Type()
Solution
Step 1: Recall method call syntax
In C#, to get the runtime type of an object, you call the method on the object: obj.GetType().
Step 2: Understand other options
GetType(obj) is invalid syntax, typeof(obj) is incorrect because typeof expects a type name, not a variable, and obj.Type() does not exist.
Final Answer:
obj.GetType() -> Option A
Quick Check:
Call GetType() on the object [OK]
Hint: Use dot notation: object.GetType() [OK]
Common Mistakes:
Using typeof with a variable instead of a type
Trying to call GetType as a standalone function
Using incorrect method names like Type()
3. What will be the output of the following code?
object val = 123;
Console.WriteLine(val.GetType().Name);
medium
A. Int32
B. int
C. Object
D. String
Solution
Step 1: Identify the runtime type of val
The variable val is declared as object but holds the integer value 123, which is of type Int32 in C#.
Step 2: Understand GetType().Name output
Calling val.GetType().Name returns the name of the actual runtime type, which is Int32.
Final Answer:
Int32 -> Option A
Quick Check:
Runtime type name = Int32 [OK]
Hint: GetType().Name shows exact type name [OK]
Common Mistakes:
Expecting 'int' instead of 'Int32'
Thinking it returns 'Object' because of variable type
Confusing with string output
4. Identify the error in this code snippet:
object data = "hello";
if (data.GetType() == string)
{
Console.WriteLine("It's a string!");
}
medium
A. Missing semicolon after Console.WriteLine
B. Comparing GetType() to a type name instead of a Type object
C. Using == instead of .Equals() for type comparison
D. GetType() cannot be used on object variables
Solution
Step 1: Analyze the type comparison
The code compares data.GetType() to string, but string is a keyword, not a Type object.
Step 2: Correct way to compare types
To compare types, use typeof(string) which returns the Type object for string. So the condition should be data.GetType() == typeof(string).
Final Answer:
Comparing GetType() to a type name instead of a Type object -> Option B
Quick Check:
Use typeof(TypeName) for type comparison [OK]
Hint: Compare with typeof(TypeName), not just type name [OK]
Common Mistakes:
Using type name without typeof()
Thinking == can't compare types
Assuming GetType() is invalid on object
5. You want to write a method that accepts an object and prints a special message if the object is an integer or a string. Which code correctly uses runtime type information to do this?