Output coil in PLC Programming - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to turn on the output coil named 'Motor'.

PLC Programming

OUTPUT [1] ;

Drag options to blanks, or click blank then click option'

AMotor

BStart

CStop

DReset

Attempts:

3 left

💡 Hint

Common Mistakes

Using a wrong coil name like 'Start' or 'Stop'.

Forgetting the coil name after OUTPUT.

The output coil is named 'Motor', so the command to turn it on is 'OUTPUT Motor ;'.

2fill in blank

medium

Complete the code to turn off the output coil named 'Light'.

PLC Programming

RESET [1] ;

Drag options to blanks, or click blank then click option'

APump

BFan

CLight

DValve

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong coil name like 'Fan' or 'Pump'.

Using OUTPUT instead of RESET to turn off.

To turn off the output coil named 'Light', use 'RESET Light ;'.

3fill in blank

hard

Fix the error in the code to turn on the output coil 'Conveyor'.

PLC Programming

OUTPUT [1] ;

Drag options to blanks, or click blank then click option'

AConveyor1

BConveryor

CConveyorBelt

DConveyor

Attempts:

3 left

💡 Hint

Common Mistakes

Misspelling the coil name.

Not noticing the typo in the command keyword.

The command should be 'OUTPUT Conveyor ;' but here 'OUTPT' is a typo. The blank is for the coil name 'Conveyor'.

4fill in blank

hard

Fill both blanks to set the output coil 'Heater' ON when input 'TempHigh' is true.

PLC Programming

IF [1] THEN
  OUTPUT [2] ;
END_IF

Drag options to blanks, or click blank then click option'

ATempHigh

BTempLow

CHeater

DCooler

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong input like 'TempLow'.

Activating the wrong coil like 'Cooler'.

The condition is 'TempHigh' and the coil to turn on is 'Heater'.

5fill in blank

hard

Fill all three blanks to reset the output coil 'Alarm' when input 'ResetButton' is pressed and 'AlarmActive' is true.

PLC Programming

IF [1] AND [2] THEN
  RESET [3] ;
END_IF

Drag options to blanks, or click blank then click option'

AResetButton

BAlarmActive

CAlarm

DStartButton

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong inputs like 'StartButton'.

Resetting the wrong coil.

The condition checks 'ResetButton' and 'AlarmActive' inputs, then resets the 'Alarm' coil.

Practice

1. What is the main purpose of an output coil in PLC programming?

easy

A. To control devices like lights or motors by turning them ON or OFF

B. To read input signals from sensors

C. To store data temporarily

D. To perform mathematical calculations

Solution

1. Step 1: Understand the role of output coils

   Output coils are used to control physical devices by turning them ON or OFF based on program logic.

2. Step 2: Differentiate from other PLC elements

   Input signals are read by input instructions, data storage is done by registers, and calculations are done by math instructions, not output coils.

3. Final Answer:

   To control devices like lights or motors by turning them ON or OFF -> Option A

4. Quick Check:

   Output coil controls devices = B [OK]

Hint: Output coils always control devices ON/OFF [OK]

Common Mistakes:

• Confusing output coils with input instructions
• Thinking output coils store data
• Assuming output coils perform calculations

2. Which of the following is the correct syntax to define an output coil named Motor in ladder logic?

easy

A. ( ) Motor

B. COIL Motor

C. OUT Motor

D. SET Motor

Solution

1. Step 1: Recognize ladder logic output coil symbol

   In ladder logic, output coils are represented by parentheses around the coil name, like ( ) Motor.

2. Step 2: Compare other options

   OUT and SET are instructions but not standard coil syntax; COIL is not a typical keyword.

3. Final Answer:

   ( ) Motor -> Option A

4. Quick Check:

   Output coil uses parentheses = A [OK]

Hint: Output coils use parentheses in ladder logic [OK]

Common Mistakes:

• Using keywords like OUT or SET instead of parentheses
• Confusing coil syntax with input instructions
• Omitting parentheses around coil name

3. Given the ladder logic snippet:

( ) Light
--[ ] Switch

What happens when the Switch input is ON?

medium

A. Nothing changes

B. The Light output coil turns ON

C. The Switch input turns OFF

D. The Light output coil turns OFF

Solution

1. Step 1: Understand the ladder logic flow

   The normally open contact [ ] Switch controls the output coil ( ) Light. When Switch is ON (closed), current flows to Light coil.

2. Step 2: Determine output coil state

   Since Switch is ON, the Light coil energizes and turns ON the Light output.

3. Final Answer:

   The Light output coil turns ON -> Option B

4. Quick Check:

   Switch ON energizes Light coil = D [OK]

Hint: Input ON energizes output coil ON [OK]

Common Mistakes:

• Thinking output coil turns OFF when input is ON
• Confusing input and output roles
• Assuming no change occurs

4. Identify the error in this ladder logic snippet:

( ) Motor
--[ ] Start
--[/] Stop

where [/] is a normally closed contact. The Motor never stays ON even when Start is pressed and Stop is released.

medium

A. The output coil syntax is incorrect

B. The Stop contact should be normally open, not normally closed

C. The contacts are not connected in parallel

D. The Start contact is wired incorrectly

Solution

1. Step 1: Analyze contact wiring logic

   The Start and Stop contacts are in series, so both must be ON for Motor coil to energize.

2. Step 2: Understand typical start/stop control

   Usually, Start and Stop contacts are wired in parallel or with a latch to maintain Motor ON after Start is pressed.

3. Step 3: Identify wiring issue

   Because contacts are in series without latching, Motor never stays ON; wiring should be parallel or use latch logic.

4. Final Answer:

   The contacts are not connected in parallel -> Option C

5. Quick Check:

   Start/Stop need parallel or latch wiring = C [OK]

Hint: Start/Stop usually wired parallel or latched [OK]

Common Mistakes:

• Assuming output coil syntax is wrong
• Changing Stop contact type incorrectly
• Not recognizing wiring arrangement

5. You want to control a valve using an output coil named Valve. The valve should turn ON only if both Pressure_OK and Temperature_OK inputs are ON. Which ladder logic snippet correctly implements this?

hard

A. ( ) Valve
--[/] Pressure_OK
--[ ] Temperature_OK

B. ( ) Valve
--[ ] Pressure_OK
--[/] Temperature_OK

C. ( ) Valve
--[ ] Pressure_OK
--| | Temperature_OK

D. ( ) Valve
--[ ] Pressure_OK
--[ ] Temperature_OK

Solution

1. Step 1: Understand AND condition in ladder logic

   To turn Valve ON only if both inputs are ON, the contacts must be in series, both normally open.

2. Step 2: Check each option

   ( ) Valve
   --[ ] Pressure_OK
   --[ ] Temperature_OK
   

   has both [ ] Pressure_OK and [ ] Temperature_OK in series, correct for AND logic.

   ( ) Valve
   --[ ] Pressure_OK
   --[/] Temperature_OK
   

   uses normally closed for Temperature_OK, wrong.

   ( ) Valve
   --[ ] Pressure_OK
   --| | Temperature_OK
   

   uses invalid symbol | |.

   ( ) Valve
   --[/] Pressure_OK
   --[ ] Temperature_OK
   

   uses normally closed for Pressure_OK, wrong.

3. Final Answer:

   with both normally open contacts in series -> Option D

4. Quick Check:

   Both inputs ON in series = Valve ON [OK]

Hint: AND logic uses series normally open contacts [OK]

Common Mistakes:

• Using normally closed contacts incorrectly
• Confusing AND with OR logic
• Using invalid contact symbols