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Typescriptprogramming~10 mins

Namespace merging in Typescript - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to declare a namespace named 'Shapes'.

Typescript
namespace [1] {
  export const pi = 3.14;
}
Drag options to blanks, or click blank then click option'
AShapes
BMath
CCircle
DGeometry
Attempts:
3 left
💡 Hint
Common Mistakes
Using a different name than 'Shapes' causes the namespace to be unrelated.
Forgetting to use the 'namespace' keyword.
2fill in blank
medium

Complete the code to add a function 'area' inside the 'Shapes' namespace.

Typescript
namespace Shapes {
  export const pi = 3.14;
  export function [1](radius: number): number {
    return pi * radius * radius;
  }
}
Drag options to blanks, or click blank then click option'
Acircumference
Barea
Cperimeter
Dvolume
Attempts:
3 left
💡 Hint
Common Mistakes
Using a wrong function name like 'circumference' or 'volume'.
Not exporting the function to make it accessible outside.
3fill in blank
hard

Fix the error in merging two namespaces named 'Shapes'.

Typescript
namespace Shapes {
  export const pi = 3.14;
}

namespace Shapes {
  export function [1](radius: number): number {
    return Shapes.pi * radius * radius;
  }
}
Drag options to blanks, or click blank then click option'
Aarea
Bradius
Cdiameter
Dcircumference
Attempts:
3 left
💡 Hint
Common Mistakes
Using different namespace names prevents merging.
Naming the function incorrectly.
4fill in blank
hard

Fill both blanks to create a merged namespace 'Shapes' with a constant and a function.

Typescript
namespace [1] {
  export const [2] = 3.14;
}

namespace Shapes {
  export function area(radius: number): number {
    return Shapes.pi * radius * radius;
  }
}
Drag options to blanks, or click blank then click option'
AShapes
BCircle
Cpi
Dradius
Attempts:
3 left
💡 Hint
Common Mistakes
Using different namespace names prevents merging.
Using a wrong constant name breaks the calculation.
5fill in blank
hard

Fill all three blanks to create a merged namespace 'Shapes' with a constant, a function, and a nested namespace.

Typescript
namespace [1] {
  export const [2] = 3.14;
  export function area(radius: number): number {
    return pi * radius * radius;
  }
  export namespace [3] {
    export function circumference(radius: number): number {
      return 2 * Shapes.pi * radius;
    }
  }
}
Drag options to blanks, or click blank then click option'
AShapes
Bpi
CCircle
DGeometry
Attempts:
3 left
💡 Hint
Common Mistakes
Using different names breaks the namespace structure.
Forgetting to export nested namespaces or constants.

Practice

(1/5)
1. What happens when two namespaces with the same name are declared in TypeScript?
easy
A. The second namespace overwrites the first one.
B. They merge into a single namespace combining all members.
C. A compile-time error occurs due to duplicate namespace names.
D. Only the first namespace is used; the second is ignored.

Solution

  1. Step 1: Understand namespace merging concept

    TypeScript allows multiple namespace declarations with the same name to combine their members into one.
  2. Step 2: Effect of merging

    All functions, variables, or types inside these namespaces become part of a single namespace accessible together.
  3. Final Answer:

    They merge into a single namespace combining all members. -> Option B
  4. Quick Check:

    Namespace merging = combined members [OK]
Hint: Same namespace names combine their contents automatically [OK]
Common Mistakes:
  • Thinking second namespace replaces the first
  • Expecting a compile error for duplicate namespaces
  • Assuming namespaces remain separate
2. Which of the following is the correct syntax to export a function inside a namespace for external use?
easy
A. namespace MySpace { export function greet() { return 'Hi'; } }
B. namespace MySpace { public function greet() { return 'Hi'; } }
C. namespace MySpace { export greet() { return 'Hi'; } }
D. namespace MySpace { function greet() { return 'Hi'; } }

Solution

  1. Step 1: Identify export keyword usage

    To make a function accessible outside the namespace, it must be marked with export.
  2. Step 2: Check syntax correctness

    Only namespace MySpace { export function greet() { return 'Hi'; } } correctly uses export function greet() inside the namespace.
  3. Final Answer:

    namespace MySpace { export function greet() { return 'Hi'; } } -> Option A
  4. Quick Check:

    Export keyword needed for external access [OK]
Hint: Use 'export' before function to share outside namespace [OK]
Common Mistakes:
  • Omitting 'export' keyword
  • Using 'public' keyword which is invalid in namespaces
  • Incorrect export syntax without 'function' keyword
3. Consider the following code:
namespace Alpha {
  export const value = 10;
}
namespace Alpha {
  export function getValue() { return value * 2; }
}
console.log(Alpha.getValue());

What is the output when this code runs?
medium
A. 20
B. 10
C. undefined
D. Runtime error

Solution

  1. Step 1: Understand namespace merging effect

    Both namespace blocks named 'Alpha' merge, so value and getValue are in the same namespace.
  2. Step 2: Evaluate function output

    getValue() returns value * 2, which is 10 * 2 = 20.
  3. Final Answer:

    20 -> Option A
  4. Quick Check:

    Namespace members combined, output = 20 [OK]
Hint: Merged namespaces share all exported members [OK]
Common Mistakes:
  • Thinking namespaces are separate causing undefined
  • Expecting runtime error due to multiple declarations
  • Confusing output with original value
4. Identify the error in this code snippet:
namespace Beta {
  export let count = 5;
}
namespace Beta {
  let count = 10;
  export function showCount() { return count; }
}
console.log(Beta.showCount());
medium
A. Function 'showCount' cannot access 'count' declared outside.
B. Cannot declare 'count' twice in the same namespace.
C. Missing 'export' keyword on the second 'count'.
D. The inner 'count' shadows the exported 'count', causing unexpected output.

Solution

  1. Step 1: Analyze variable declarations in merged namespace

    The second namespace declares a local count without export, which shadows the exported count from the first namespace.
  2. Step 2: Effect on function output

    showCount() returns the inner count (10), not the exported one (5), which may be unexpected.
  3. Final Answer:

    The inner 'count' shadows the exported 'count', causing unexpected output. -> Option D
  4. Quick Check:

    Local variable shadows exported one [OK]
Hint: Inner variables can hide outer exported ones [OK]
Common Mistakes:
  • Assuming redeclaration causes error
  • Expecting 'showCount' to return 5
  • Thinking export is needed on inner variable
5. You want to extend an existing namespace Utils defined in another file by adding a new exported function double that doubles a number. Which is the correct way to do this using namespace merging?
hard
A. module Utils { function double(x: number) { return x * 2; } }
B. namespace Utils { function double(x: number) { return x * 2; } }
C. namespace Utils { export function double(x: number) { return x * 2; } }
D. namespace Utils { const double = (x: number) => x * 2; }

Solution

  1. Step 1: Use 'namespace' keyword to extend existing namespace

    To add members to an existing namespace, declare a new namespace block with the same name.
  2. Step 2: Export the new function properly

    The function must be exported to be accessible outside the namespace.
  3. Final Answer:

    namespace Utils { export function double(x: number) { return x * 2; } } -> Option C
  4. Quick Check:

    Extend with 'namespace' and export function [OK]
Hint: Use 'namespace' with same name and export new members [OK]
Common Mistakes:
  • Using 'module' instead of 'namespace'
  • Not exporting the new function
  • Declaring function without namespace
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10 questions~5 mineasy hard