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Typescriptprogramming~5 mins

Indexed access types in Typescript

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Introduction

Indexed access types let you get the type of a specific property from another type. This helps you reuse types easily without repeating them.

When you want to use the type of a property from an object type in another place.
When you want to make sure a variable matches the type of a specific property inside an object.
When you want to create a new type based on one or more properties of an existing type.
When you want to avoid repeating type definitions and keep your code DRY (Don't Repeat Yourself).
Syntax
Typescript
type NewType = ExistingType['propertyName'];

You use square brackets with the property name as a string inside to get the type.

You can also use union of keys like ExistingType['prop1' | 'prop2'] to get combined types.

Examples
This gets the type of the name property from Person, which is string.
Typescript
type Person = { name: string; age: number };
type NameType = Person['name'];
This gets the type of age or name, so the type is number | string.
Typescript
type Person = { name: string; age: number };
type AgeOrName = Person['age' | 'name'];
This extracts the type of the make property from the Car interface.
Typescript
interface Car {
  make: string;
  year: number;
}
type MakeType = Car['make'];
Sample Program

This program shows how to use indexed access types to get property types from the User interface. We assign values matching those types and print them.

Typescript
interface User {
  id: number;
  username: string;
  isActive: boolean;
}

// Get the type of the 'username' property
let userName: User['username'];
userName = 'alice123';

// Get the type of 'id' or 'isActive'
let userInfo: User['id' | 'isActive'];
userInfo = 42; // valid
userInfo = true; // also valid

console.log(userName);
console.log(userInfo);
OutputSuccess
Important Notes

Indexed access types help keep your types consistent and avoid mistakes.

If you use a property name that does not exist, TypeScript will show an error.

You can combine indexed access types with other TypeScript features for powerful type manipulation.

Summary

Indexed access types let you get the type of a property from another type.

Use square brackets with the property name to extract the type.

This helps reuse types and keep your code clean and safe.

Practice

(1/5)
1. What does the TypeScript indexed access type Person['name'] represent?
easy
A. A function that returns the 'name' property
B. The type of the 'name' property in the Person type
C. An error because 'name' is not a valid type
D. A new property called 'name' added to Person

Solution

  1. Step 1: Understand indexed access syntax

    The syntax Type['property'] extracts the type of the specified property from the given type.
  2. Step 2: Apply to Person['name']

    This means Person['name'] is the type of the 'name' property inside the Person type.
  3. Final Answer:

    The type of the 'name' property in the Person type -> Option B
  4. Quick Check:

    Indexed access type = property type [OK]
Hint: Remember: Type['prop'] gives the type of that property [OK]
Common Mistakes:
  • Thinking it creates a new property
  • Confusing it with a function call
  • Assuming it causes a syntax error
2. Which of the following is the correct syntax to get the type of property age from type Person using indexed access types?
easy
A. type AgeType = Person['age'];
B. type AgeType = Person.age;
C. type AgeType = Person("age");
D. type AgeType = Person<age>;

Solution

  1. Step 1: Recall indexed access syntax

    The correct syntax uses square brackets with the property name as a string: Type['property'].
  2. Step 2: Check each option

    type AgeType = Person['age']; matches this syntax exactly: Person['age']. Others use dot notation or parentheses which are invalid here.
  3. Final Answer:

    type AgeType = Person['age']; -> Option A
  4. Quick Check:

    Use square brackets with quotes for indexed access [OK]
Hint: Use square brackets and quotes for property names [OK]
Common Mistakes:
  • Using dot notation instead of brackets
  • Using parentheses like a function call
  • Using angle brackets incorrectly
3. Given the type type Person = { name: string; age: number; }, what is the type of Person['age']?
medium
A. string
B. boolean
C. any
D. number

Solution

  1. Step 1: Look at the Person type definition

    The property 'age' in Person is defined as a number.
  2. Step 2: Indexed access extracts that type

    So Person['age'] is the type number.
  3. Final Answer:

    number -> Option D
  4. Quick Check:

    Person['age'] = number [OK]
Hint: Check the property type inside the original type [OK]
Common Mistakes:
  • Confusing 'age' type with 'name' type
  • Assuming default any type
  • Mixing up string and number types
4. What is wrong with this TypeScript code?
type Person = { name: string; age: number; };
type AgeType = Person[age];
medium
A. AgeType cannot be assigned
B. Person type is not defined
C. Missing quotes around 'age' in indexed access
D. No error, code is correct

Solution

  1. Step 1: Identify the indexed access syntax error

    In Person[age], 'age' should be a string literal in quotes: Person['age'].
  2. Step 2: Understand why quotes are needed

    Without quotes, TypeScript treats age as a variable, which is undefined here, causing an error.
  3. Final Answer:

    Missing quotes around 'age' in indexed access -> Option C
  4. Quick Check:

    Property names in indexed access need quotes [OK]
Hint: Always put property names in quotes inside brackets [OK]
Common Mistakes:
  • Omitting quotes around property names
  • Assuming dot notation works in type access
  • Confusing variables with string literals
5. Given the type type Config = { options: { debug: boolean; verbose: boolean; }; version: string; }, which type correctly extracts the type of the debug property using indexed access types?
hard
A. Config['options']['debug']
B. Config.options.debug
C. Config['debug']
D. Config['options.debug']

Solution

  1. Step 1: Understand nested indexed access

    The 'debug' property is inside 'options', so we first access 'options' then 'debug'.
  2. Step 2: Apply chained indexed access syntax

    Use Config['options']['debug'] to get the type of 'debug'.
  3. Step 3: Check other options

    Config.options.debug uses dot notation which is invalid in type access. Config['debug'] tries to access 'debug' directly on Config which doesn't exist. Config['options.debug'] treats 'options.debug' as a single property name which is incorrect.
  4. Final Answer:

    Config['options']['debug'] -> Option A
  5. Quick Check:

    Use chained brackets for nested properties [OK]
Hint: Chain brackets for nested property types [OK]
Common Mistakes:
  • Using dot notation in type access
  • Accessing nested property directly without parent
  • Treating nested keys as single string
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