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Typescriptprogramming~5 mins

Keyof operator in Typescript

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Introduction

The keyof operator helps you get all the property names of an object type as a union of string literal types. It makes working with object keys easier and safer.

When you want to get all keys of an object type to use them elsewhere.
When you want to make sure a variable can only be one of the keys of an object.
When you want to create functions that work with object keys without hardcoding them.
When you want to avoid mistakes by using actual keys from an object type instead of strings.
When you want to build flexible and reusable code that adapts to object shapes.
Syntax
Typescript
type Keys = keyof ObjectType;

ObjectType is any object type you want to get keys from.

The result Keys is a union of string literal types representing the keys.

Examples
This gets the keys 'name' and 'age' from the Person type.
Typescript
type Person = { name: string; age: number; };
type PersonKeys = keyof Person;  // 'name' | 'age'
You can only assign keys that exist in the object type.
Typescript
const key: keyof Person = 'name';  // valid
// const wrongKey: keyof Person = 'height';  // error
This function safely gets a value from an object using a key that must exist on the object.
Typescript
function getValue<T, K extends keyof T>(obj: T, key: K) {
  return obj[key];
}
Sample Program

This program defines a Car type and a function that prints a property of a car. The function only accepts keys that exist on Car. It then prints the make and year of the car.

Typescript
type Car = {
  make: string;
  model: string;
  year: number;
};

function printCarProperty(car: Car, key: keyof Car) {
  console.log(`The car's ${key} is ${car[key]}`);
}

const myCar: Car = { make: 'Toyota', model: 'Corolla', year: 2020 };

printCarProperty(myCar, 'make');
printCarProperty(myCar, 'year');
OutputSuccess
Important Notes

The keyof operator works only on object types, not on primitive types.

Using keyof helps catch errors early by restricting keys to valid ones.

Summary

keyof gets all keys of an object type as a union of strings.

It helps write safer and clearer code by limiting keys to valid ones.

Commonly used in generic functions to work flexibly with object properties.

Practice

(1/5)
1. What does the keyof operator do in TypeScript?
easy
A. It returns the values of an object as a union type.
B. It converts a type to a string literal type.
C. It creates a union type of all keys of an object type.
D. It extracts the type of a function's return value.

Solution

  1. Step 1: Understand the purpose of keyof

    The keyof operator takes an object type and produces a union of its keys as string literal types.
  2. Step 2: Compare options with definition

    Only "It creates a union type of all keys of an object type." correctly describes this behavior. The other options describe unrelated TypeScript features.
  3. Final Answer:

    It creates a union type of all keys of an object type. -> Option C
  4. Quick Check:

    keyof = union of keys [OK]
Hint: Remember: keyof lists keys, not values or types [OK]
Common Mistakes:
  • Confusing keyof with getting values
  • Thinking it returns runtime keys instead of types
  • Mixing it up with return type extraction
2. Which of the following is the correct syntax to get keys of type Person using keyof?
easy
A. type Keys = Person.keyof;
B. type Keys = keyof(Person);
C. type Keys = keys<Person>;
D. type Keys = keyof Person;

Solution

  1. Step 1: Recall correct keyof syntax

    The correct syntax is keyof TypeName without parentheses or dot notation.
  2. Step 2: Evaluate each option

    type Keys = keyof Person; uses correct syntax. type Keys = keyof(Person); incorrectly uses parentheses. type Keys = keys<Person>; uses a non-existent keys keyword. type Keys = Person.keyof; uses invalid dot notation.
  3. Final Answer:

    type Keys = keyof Person; -> Option D
  4. Quick Check:

    Correct syntax = keyof Type [OK]
Hint: Use keyof TypeName without parentheses [OK]
Common Mistakes:
  • Adding parentheses around the type
  • Using dot notation like Type.keyof
  • Confusing keyof with keys
3. Given the code:
type Car = { make: string; model: string; year: number };
type CarKeys = keyof Car;

let key: CarKeys = 'year';
console.log(key);

What is the output when this code runs?
medium
A. 'year'
B. 'make'
C. Error: Type 'string' is not assignable
D. undefined

Solution

  1. Step 1: Understand keyof usage

    CarKeys is a union of keys: 'make' | 'model' | 'year'. The variable key is assigned the string 'year', which is valid.
  2. Step 2: Check console output

    The console logs the value of key, which is 'year'. No errors occur.
  3. Final Answer:

    'year' -> Option A
  4. Quick Check:

    Assigned key = 'year' [OK]
Hint: Assign only keys from the union to avoid errors [OK]
Common Mistakes:
  • Expecting runtime error for type assignment
  • Confusing keys with values
  • Thinking keyof returns values
4. Identify the error in this code:
type User = { id: number; name: string };
function getValue(obj: User, key: keyof User) {
  return obj.key;
}
medium
A. Using dot notation with variable key instead of bracket notation.
B. Missing return type annotation in function.
C. Incorrect type for parameter obj.
D. keyof User is not a valid type.

Solution

  1. Step 1: Analyze property access in function

    The function tries to access obj.key. Since key is a variable, dot notation looks for a property literally named 'key'.
  2. Step 2: Correct property access syntax

    To use a variable key, bracket notation obj[key] is required to access the dynamic property.
  3. Final Answer:

    Using dot notation with variable key instead of bracket notation. -> Option A
  4. Quick Check:

    Use obj[key] for dynamic keys [OK]
Hint: Use bracket notation for variable keys [OK]
Common Mistakes:
  • Using dot notation with variable keys
  • Ignoring TypeScript error messages
  • Assuming keyof is invalid
5. How can you write a generic function that takes an object and a key of that object, then returns the value of that key safely using keyof? Choose the correct implementation.
hard
A. function getProp<T>(obj: T, key: keyof T): string { return obj[key]; }
B. function getProp(obj: T, key: K): T[K] { return obj[key]; }
C. function getProp<T>(obj: T, key: string): any { return obj.key; }
D. function getProp(obj: T, key: K): K { return obj[key]; }

Solution

  1. Step 1: Understand generic constraints with keyof

    To ensure the key is valid for the object, the key type K must extend keyof T. This restricts keys to valid property names.
  2. Step 2: Check return type and access

    The return type should be T[K], the type of the property at key K. Accessing obj[key] returns this value safely.
  3. Step 3: Evaluate options

    function getProp(obj: T, key: K): T[K] { return obj[key]; } correctly uses generics and keyof. function getProp<T>(obj: T, key: string): any { return obj.key; } uses string key and dot notation, which is unsafe. function getProp<T>(obj: T, key: keyof T): string { return obj[key]; } fixes key type but wrongly fixes return type to string. function getProp(obj: T, key: K): K { return obj[key]; } lacks constraint on K and returns wrong type.
  4. Final Answer:

    function getProp<T, K extends keyof T>(obj: T, key: K): T[K] { return obj[key]; } -> Option B
  5. Quick Check:

    Generic key constrained by keyof = safe access [OK]
Hint: Use K extends keyof T and return T[K] [OK]
Common Mistakes:
  • Not constraining key type with keyof
  • Using string keys without type safety
  • Returning wrong or fixed types
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