Why inheritance needs types in Typescript

Introduction

Inheritance helps us create new things based on old ones. Types make sure these new things behave correctly and safely.

When you want to build a new class that shares features with an existing class.

When you want to make sure the new class follows the rules of the old class.

When you want to catch mistakes early by checking types before running the program.

Syntax

Typescript

class Parent {
  property: string;
  constructor(property: string) {
    this.property = property;
  }
}

class Child extends Parent {
  extraProperty: number;
  constructor(property: string, extraProperty: number) {
    super(property);
    this.extraProperty = extraProperty;
  }
}

extends keyword means Child inherits from Parent.

TypeScript checks that Child matches Parent's type rules.

Examples

Dog inherits name from Animal and adds breed.

Typescript

class Animal {
  name: string;
  constructor(name: string) {
    this.name = name;
  }
}

class Dog extends Animal {
  breed: string;
  constructor(name: string, breed: string) {
    super(name);
    this.breed = breed;
  }
}

Car inherits wheels from Vehicle and adds brand.

Typescript

class Vehicle {
  wheels: number;
  constructor(wheels: number) {
    this.wheels = wheels;
  }
}

class Car extends Vehicle {
  brand: string;
  constructor(wheels: number, brand: string) {
    super(wheels);
    this.brand = brand;
  }
}

Sample Program

This program shows a Student inheriting from Person. Types make sure Student has a name and studentId. The greet method uses both.

Typescript

class Person {
  name: string;
  constructor(name: string) {
    this.name = name;
  }
  greet() {
    return `Hello, my name is ${this.name}`;
  }
}

class Student extends Person {
  studentId: number;
  constructor(name: string, studentId: number) {
    super(name);
    this.studentId = studentId;
  }
  greet() {
    return `${super.greet()} and my student ID is ${this.studentId}`;
  }
}

const student = new Student("Alice", 12345);
console.log(student.greet());

Important Notes

Types help catch errors like missing properties or wrong data types before running the code.

Inheritance with types makes your code easier to understand and maintain.

Summary

Inheritance lets one class reuse code from another.

Types ensure the new class follows the rules of the original class.

This helps prevent mistakes and makes code safer.

Practice

1. Why do we need types when using inheritance in TypeScript?

easy

A. To ensure the child class follows the structure of the parent class

B. To make the code run faster

C. To allow multiple inheritance

D. To avoid writing constructors

Solution

1. Step 1: Understand inheritance purpose

   Inheritance allows a child class to reuse code from a parent class.

2. Step 2: Role of types in inheritance

   Types ensure the child class matches the parent's structure, preventing mistakes.

3. Final Answer:

   To ensure the child class follows the structure of the parent class -> Option A

4. Quick Check:

   Types keep inheritance safe = A [OK]

Hint: Types keep child classes consistent with parents [OK]

Common Mistakes:

• Thinking types speed up code execution
• Confusing inheritance with multiple inheritance
• Believing constructors are avoided by types

2. Which of the following is the correct way to declare a class Dog that inherits from class Animal in TypeScript?

easy

A. class Dog Animal {}

B. class Dog inherits Animal {}

C. class Dog : Animal {}

D. class Dog extends Animal {}

Solution

1. Step 1: Recall TypeScript inheritance syntax

   TypeScript uses the keyword extends to inherit from a class.

2. Step 2: Check each option

   Only class Dog extends Animal {} uses extends correctly; others use invalid syntax.

3. Final Answer:

   class Dog extends Animal {} -> Option D

4. Quick Check:

   Inheritance uses 'extends' keyword = A [OK]

Hint: Remember: 'extends' keyword for class inheritance [OK]

Common Mistakes:

• Using 'inherits' instead of 'extends'
• Using ':' like other languages (e.g., C#)
• Omitting 'extends' keyword

3. What will be the output of this TypeScript code?

class Animal {
  name: string;
  constructor(name: string) {
    this.name = name;
  }
  speak() {
    return `${this.name} makes a sound.`;
  }
}

class Dog extends Animal {
  speak() {
    return `${this.name} barks.`;
  }
}

const dog = new Dog('Buddy');
console.log(dog.speak());

medium

A. Buddy makes a sound.

B. Buddy barks.

C. Error: speak method missing

D. undefined barks.

Solution

1. Step 1: Understand class inheritance and method overriding

   Dog inherits from Animal and overrides the speak() method.

2. Step 2: Check the output of dog.speak()

   dog.speak() calls Dog's speak(), returning 'Buddy barks.'

3. Final Answer:

   Buddy barks. -> Option B

4. Quick Check:

   Overridden method runs = D [OK]

Hint: Overridden methods in child class run, not parent's [OK]

Common Mistakes:

• Expecting parent method output
• Thinking speak method is missing
• Assuming name is undefined

4. Identify the error in this TypeScript code:

class Animal {
  name: string;
  constructor(name: string) {
    this.name = name;
  }
}

class Dog extends Animal {
  constructor() {
    super();
  }
}

medium

A. Missing argument in super() call

B. Dog class cannot have a constructor

C. name property should be private

D. super() should be called after this.name assignment

Solution

1. Step 1: Check Animal constructor parameters

   Animal's constructor requires a string argument name.

2. Step 2: Check Dog constructor call to super()

   Dog calls super() without arguments, causing an error.

3. Final Answer:

   Missing argument in super() call -> Option A

4. Quick Check:

   super() needs required parameters = B [OK]

Hint: super() must get all required parent constructor args [OK]

Common Mistakes:

• Calling super() without arguments when parent needs them
• Thinking child class can't have constructor
• Confusing property access modifiers

5. You want to create a class Rectangle that inherits from Shape. The Shape class requires a color string property. How should you define the Rectangle constructor to properly use inheritance and types in TypeScript?

hard

A. constructor(color: string) { this.color = color; }

B. constructor(width: number, height: number) { this.width = width; this.height = height; }

C. constructor(color: string, width: number, height: number) { super(color); this.width = width; this.height = height; }

D. constructor() { super(); this.width = 0; this.height = 0; }

Solution

1. Step 1: Understand parent constructor requirements

   Shape requires a color string in its constructor.

2. Step 2: Define Rectangle constructor with all needed parameters

   Rectangle must accept color and pass it to super(color), plus its own properties.

3. Step 3: Check options for correct super call and property assignments

   Only constructor(color: string, width: number, height: number) { super(color); this.width = width; this.height = height; } correctly calls super(color) and assigns width and height.

4. Final Answer:

   constructor(color: string, width: number, height: number) { super(color); this.width = width; this.height = height; } -> Option C

5. Quick Check:

   Pass parent args via super() = C [OK]

Hint: Pass all parent constructor args to super() in child constructor [OK]

Common Mistakes:

• Omitting super() call or its arguments
• Assigning parent properties directly without super()
• Missing child class properties in constructor