Control flow analysis behavior in Typescript - Mini Project: Build & Apply

Control flow analysis behavior

📖 Scenario: You are building a simple TypeScript program that uses control flow to check user age and determine access permission.

🎯 Goal: Create a program that uses control flow analysis to check if a user is an adult and print the correct message.

📋 What You'll Learn

Create a variable age with a number value.

Create a variable isAdult that will hold a boolean value.

Use an if statement to set isAdult to true if age is 18 or more, otherwise false.

Print the message "User is an adult" if isAdult is true, otherwise print "User is not an adult".

💡 Why This Matters

🌍 Real World

Control flow analysis helps programs make decisions based on data, like checking user permissions or validating input.

💼 Career

Understanding control flow is essential for writing correct and safe TypeScript code in web development and software engineering.

1

Create the age variable

Create a variable called age and set it to the number 20.

Typescript

# Create a variable called age and set it to 20
// Your code here

Hint

Use let age: number = 20; to create the variable.

2

Create the isAdult variable

Create a variable called isAdult and set it to false.

Typescript

let age: number = 20;
// Create a variable called isAdult and set it to false
// Your code here

Hint

Use let isAdult: boolean = false; to create the variable.

3

Use if statement to update isAdult

Use an if statement with the condition age >= 18 to set isAdult to true inside the block.

Typescript

let age: number = 20;
let isAdult: boolean = false;
// Use if statement to set isAdult to true if age is 18 or more
// Your code here

Hint

Write if (age >= 18) { isAdult = true; } to update the variable.

4

Print the correct message based on isAdult

Use an if statement to print "User is an adult" if isAdult is true, otherwise print "User is not an adult".

Typescript

let age: number = 20;
let isAdult: boolean = false;
if (age >= 18) {
    isAdult = true;
}
// Print message based on isAdult
// Your code here

Hint

Use if (isAdult) { console.log("User is an adult"); } else { console.log("User is not an adult"); }.

Practice

1.

What does TypeScript's control flow analysis primarily help with?

easy

A. Running the program faster by optimizing loops

B. Tracking variable types through code paths to catch errors early

C. Automatically fixing syntax errors in the code

D. Converting TypeScript code into JavaScript

Solution

1. Step 1: Understand control flow analysis purpose

   Control flow analysis tracks how variables change types through different code paths.

2. Step 2: Identify its main benefit

   This helps TypeScript catch type errors before running the program.

3. Final Answer:

   Tracking variable types through code paths to catch errors early -> Option B

4. Quick Check:

   Control flow analysis = type tracking [OK]

Hint: Control flow = tracking variable types in code paths [OK]

Common Mistakes:

• Confusing control flow analysis with code execution speed
• Thinking it fixes syntax errors automatically
• Believing it compiles TypeScript to JavaScript

2.

Which of the following TypeScript code snippets correctly narrows a variable's type using control flow analysis?

let value: string | number = 5;
if (typeof value === 'string') {
  console.log(value.toUpperCase());
}

easy

A. The code should use instanceof instead of typeof

B. The code will cause a runtime error because value can be a number

C. The code needs a type assertion to call toUpperCase()

D. The code is correct and safe to call toUpperCase() inside the if block

Solution

1. Step 1: Check the type guard condition

   The condition typeof value === 'string' narrows value to string inside the if block.

2. Step 2: Confirm safe method call

   Since value is string here, calling toUpperCase() is safe and valid.

3. Final Answer:

   The code is correct and safe to call toUpperCase() inside the if block -> Option D

4. Quick Check:

   Type guard narrows type = safe method call [OK]

Hint: Use typeof checks to narrow union types safely [OK]

Common Mistakes:

• Calling string methods without type narrowing
• Confusing typeof with instanceof for primitives
• Assuming type assertions are always needed

3.

What will be the output of this TypeScript code?

function checkValue(x: string | number) {
  if (typeof x === 'number') {
    return x.toFixed(2);
  } else {
    return x.toUpperCase();
  }
}
console.log(checkValue('hello'));
console.log(checkValue(3.14159));

medium

A. Runtime error because toFixed is not a function

B. "hello" and "3.14159"

C. "HELLO" and "3.14"

D. "HELLO" and "3.14159"

Solution

1. Step 1: Analyze the first call with string

   For 'hello', the else block runs, returning 'HELLO' after toUpperCase().

2. Step 2: Analyze the second call with number

   For 3.14159, the if block runs, returning '3.14' after toFixed(2).

3. Final Answer:

   "HELLO" and "3.14" -> Option C

4. Quick Check:

   Type guards produce correct string outputs [OK]

Hint: Check typeof to predict which block runs [OK]

Common Mistakes:

• Assuming toFixed returns a number, not string
• Ignoring type narrowing in if-else
• Mixing up output formatting

4.

Identify the error in this TypeScript code related to control flow analysis:

function process(input: string | null) {
  if (input) {
    console.log(input.toLowerCase());
  } else {
    console.log(input.toLowerCase());
  }
}

medium

A. Calling toLowerCase() on null in the else block causes a runtime error

B. The if condition should be input !== null instead of input

C. TypeScript will automatically fix this error during compilation

D. There is no error; the code is safe

Solution

1. Step 1: Check the else block usage

   In the else block, input is null, so calling toLowerCase() causes a runtime error.

2. Step 2: Understand control flow limitation

   Control flow analysis narrows input in the if block but not in else, so unsafe call happens.

3. Final Answer:

   Calling toLowerCase() on null in the else block causes a runtime error -> Option A

4. Quick Check:

   Null check needed before method call [OK]

Hint: Else block may have null; avoid method calls there [OK]

Common Mistakes:

• Assuming if(input) excludes null everywhere
• Expecting TypeScript to fix runtime errors
• Using loose null checks without safe calls

5.

Given this TypeScript code, what is the best way to fix the control flow analysis issue to avoid errors?

function formatInput(input: string | number | null) {
  if (typeof input === 'string') {
    return input.trim();
  } else if (typeof input === 'number') {
    return input.toFixed(1);
  }
  return input.trim();
}

hard

A. Add a null check before the last return to avoid calling trim() on null

B. Remove the last return statement because it's unreachable

C. Change all trim() calls to toString()

D. Use a type assertion to force input as string in the last return

Solution

1. Step 1: Identify the problem with last return

   The last return input.trim() runs when input is null, causing an error.

2. Step 2: Fix by adding null check

   Adding a check like if (input !== null) before calling trim() prevents errors.

3. Final Answer:

   Add a null check before the last return to avoid calling trim() on null -> Option A

4. Quick Check:

   Null checks prevent unsafe method calls [OK]

Hint: Always check for null before calling methods on unions [OK]

Common Mistakes:

• Ignoring null possibility in union types
• Assuming last return is unreachable
• Using type assertions without safety