Class implementing multiple interfaces in Typescript - Time & Space Complexity

Time Complexity: Class implementing multiple interfaces

O(n)

Understanding Time Complexity

When a class implements multiple interfaces, it must provide all the methods those interfaces require.

We want to see how the time to create and use such a class grows as we add more interfaces or methods.

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

interface A {
  methodA(): void;
}
interface B {
  methodB(): void;
}

class Multi implements A, B {
  methodA() { console.log('A'); }
  methodB() { console.log('B'); }
}

const obj = new Multi();
obj.methodA();
obj.methodB();
    

This code defines two interfaces and a class that implements both, then calls their methods.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: Calling each method once.
• How many times: Each method runs exactly once per call.

How Execution Grows With Input

Each method runs independently, so adding more methods means more calls.

Input Size (number of methods)	Approx. Operations
2	2 method calls
10	10 method calls
100	100 method calls

Pattern observation: The total work grows directly with the number of methods called.

Final Time Complexity

Time Complexity: O(n)

This means the time grows in a straight line with the number of methods you call on the class.

Common Mistake

[X] Wrong: "Implementing more interfaces makes the program slower in a complex way."

[OK] Correct: Each method runs independently, so adding interfaces just adds more simple calls, not complicated slowdowns.

Interview Connect

Understanding how multiple interfaces affect method calls helps you explain design choices clearly and shows you know how code scales.

Self-Check

"What if each method called inside the class runs a loop over an array? How would the time complexity change?"

Practice

1.

What does it mean when a TypeScript class implements multiple interfaces?

Choose the best explanation.

easy

A. The class inherits code from all those interfaces.

B. The class promises to have all methods and properties from all those interfaces.

C. The class can only use one interface at a time.

D. The class automatically creates instances of those interfaces.

Solution

1. Step 1: Understand what interfaces define

   Interfaces describe method and property shapes but do not provide code.

2. Step 2: Understand what implementing multiple interfaces means

   A class implementing multiple interfaces must provide all methods and properties from each interface.

3. Final Answer:

   The class promises to have all methods and properties from all those interfaces. -> Option B

4. Quick Check:

   Implementing multiple interfaces means fulfilling all their contracts [OK]

Hint: Implementing means fulfilling all interface contracts [OK]

Common Mistakes:

• Thinking interfaces provide code to inherit
• Believing a class can only implement one interface
• Confusing interfaces with classes

2.

Which of the following is the correct syntax for a class Car implementing two interfaces Engine and Wheels?

easy

A. class Car implements Engine, Wheels {}

B. class Car extends Engine, Wheels {}

C. class Car implements (Engine & Wheels) {}

D. class Car inherits Engine, Wheels {}

Solution

1. Step 1: Recall TypeScript syntax for multiple interfaces

   Use implements Interface1, Interface2 to implement multiple interfaces.

2. Step 2: Check each option

   class Car implements Engine, Wheels {} uses correct syntax. The options using extends and inherits use invalid keywords. class Car implements (Engine & Wheels) {} uses invalid parentheses and &.

3. Final Answer:

   class Car implements Engine, Wheels {} -> Option A

4. Quick Check:

   Multiple interfaces use comma-separated list after implements [OK]

Hint: Use comma-separated interfaces after implements keyword [OK]

Common Mistakes:

• Using extends instead of implements for interfaces
• Trying to use & or parentheses in implements clause
• Using inherits keyword which doesn't exist

3.

Consider these interfaces and class:

interface A { foo(): string; }
interface B { bar(): number; }

class C implements A, B {
  foo() { return "hello"; }
  bar() { return 42; }
}

const c = new C();
console.log(c.foo(), c.bar());

What is the output?

medium

A. hello 42

B. SyntaxError

C. [object Object] 42

D. "hello 42"

Solution

1. Step 1: Understand method return values

   Method foo() returns string "hello" and bar() returns number 42.

2. Step 2: Understand console.log output

   console.log prints values separated by space without quotes for strings.

3. Final Answer:

   hello 42 -> Option A

4. Quick Check:

   Method returns printed as values without quotes [OK]

Hint: console.log prints string without quotes, separated by spaces [OK]

Common Mistakes:

• Expecting quotes around string output
• Confusing object output with string
• Thinking code causes syntax error

4.

What is wrong with this TypeScript code?

interface X { doX(): void; }
interface Y { doY(): void; }

class Z implements X, Y {
  doX() { console.log("X done"); }
}

medium

A. Method doX() should return a value.

B. Class Z cannot implement two interfaces at once.

C. Class Z must implement method doY() from interface Y.

D. Interfaces cannot be implemented by classes.

Solution

1. Step 1: Check all interface methods

   Interface Y requires method doY() which is missing in class Z.

2. Step 2: Understand TypeScript rules for implementing interfaces

   A class must implement all methods from all interfaces it declares.

3. Final Answer:

   Class Z must implement method doY() from interface Y. -> Option C

4. Quick Check:

   All interface methods must be implemented [OK]

Hint: Implement all methods from every interface listed [OK]

Common Mistakes:

• Thinking partial implementation is allowed
• Confusing interfaces with classes
• Believing interfaces provide code

5.

You have these interfaces:

interface Printer { print(): void; }
interface Scanner { scan(): string; }

Write a class AllInOne that implements both interfaces and stores the last scanned text in a property lastScan. Which code snippet correctly implements this?

hard

A. class AllInOne implements Printer, Scanner {
lastScan = "";
print() { console.log("Printing..."); }
}

B. class AllInOne implements Printer, Scanner {
print() { console.log("Printing..."); }
scan() { return "document"; }
}

C. class AllInOne implements Printer, Scanner {
lastScan: string;
print() { console.log("Printing..."); }
scan() { return this.lastScan; }
}

D. class AllInOne implements Printer, Scanner {
lastScan = "";
print() { console.log("Printing..."); }
scan() { this.lastScan = "document"; return this.lastScan; }
}

Solution

1. Step 1: Check interface methods implemented

   Printer requires print(), Scanner requires scan(). class AllInOne implements Printer, Scanner { lastScan = ""; print() { console.log("Printing..."); } scan() { this.lastScan = "document"; return this.lastScan; } } implements both.

2. Step 2: Check lastScan property usage

   class AllInOne implements Printer, Scanner { lastScan = ""; print() { console.log("Printing..."); } scan() { this.lastScan = "document"; return this.lastScan; } } initializes lastScan and updates it inside scan(), fulfilling the requirement.

3. Final Answer:

   class AllInOne implements Printer, Scanner { lastScan = ""; print() { console.log("Printing..."); } scan() { this.lastScan = "document"; return this.lastScan; } } -> Option D

4. Quick Check:

   Implement all methods and update lastScan property [OK]

Hint: Implement all methods and update properties as required [OK]

Common Mistakes:

• Omitting one interface method
• Not updating lastScan property
• Declaring property but not initializing or updating it