Bird
Raised Fist0
C Sharp (C#)programming~30 mins

Zip operation in C Sharp (C#) - Mini Project: Build & Apply

Choose your learning style10 modes available
Zip Operation in C#
📖 Scenario: You work in a small store. You have two lists: one with product names and one with their prices. You want to combine these lists to see each product with its price.
🎯 Goal: Build a program that uses the Zip operation to pair each product with its price and print the pairs.
📋 What You'll Learn
Create two lists: one called products with exact values "Apple", "Banana", "Cherry"
Create another list called prices with exact values 1.2, 0.5, 2.0
Use a variable called productPrices to store the zipped pairs
Use a foreach loop with variables product and price to iterate over productPrices
Print each product and price in the format: "Apple: $1.2"
💡 Why This Matters
🌍 Real World
Stores and shops often have separate lists for products and prices. Combining them helps show clear price tags or receipts.
💼 Career
Knowing how to combine related data from different lists is useful in many programming jobs, especially in data processing and user interface development.
Progress0 / 4 steps
1
Create the product and price lists
Create a list of strings called products with these exact values: "Apple", "Banana", "Cherry". Also create a list of doubles called prices with these exact values: 1.2, 0.5, 2.0.
C Sharp (C#)
Hint

Use List<string> for products and List<double> for prices. Initialize them with the exact values.

2
Create the zipped pairs
Create a variable called productPrices that uses products.Zip(prices, (product, price) => (product, price)) to combine the two lists into pairs.
C Sharp (C#)
Hint

Use var productPrices = products.Zip(prices, (product, price) => (product, price)); to combine the lists.

3
Loop through the zipped pairs
Use a foreach loop with variables product and price to iterate over productPrices.
C Sharp (C#)
Hint

Use foreach (var (product, price) in productPrices) to loop through the pairs.

4
Print each product with its price
Inside the foreach loop, write Console.WriteLine($"{product}: ${price}"); to print each product and its price.
C Sharp (C#)
Hint

Use Console.WriteLine($"{product}: ${price}"); inside the loop to print each pair.

Practice

(1/5)
1.

What does the Zip method do in C#?

Choose the best description.

easy
A. Combines all elements from two collections into one long list.
B. Sorts elements in a collection in ascending order.
C. Filters elements from a collection based on a condition.
D. Pairs elements from two collections one by one until the shorter ends.

Solution

  1. Step 1: Understand the purpose of Zip

    The Zip method pairs elements from two collections by their positions.
  2. Step 2: Recognize stopping condition

    It stops when the shorter collection runs out of elements, so no extra elements are included.
  3. Final Answer:

    Pairs elements from two collections one by one until the shorter ends. -> Option D
  4. Quick Check:

    Zip pairs elements until the shorter ends = B [OK]
Hint: Zip pairs elements until shortest collection ends [OK]
Common Mistakes:
  • Thinking Zip combines all elements regardless of length
  • Confusing Zip with filtering or sorting
  • Assuming Zip merges collections end-to-end
2.

Which of the following is the correct syntax to use Zip on two lists list1 and list2 to sum their elements?

var result = list1.Zip(list2, (a, b) => ? );
easy
A. a + b
B. a - b
C. a * b
D. a / b

Solution

  1. Step 1: Identify the operation to sum elements

    The lambda expression should add the two elements: a + b.
  2. Step 2: Confirm syntax correctness

    The syntax list1.Zip(list2, (a, b) => a + b) correctly sums paired elements.
  3. Final Answer:

    a + b -> Option A
  4. Quick Check:

    Sum elements with Zip = a + b [OK]
Hint: Use (a, b) => a + b to sum zipped elements [OK]
Common Mistakes:
  • Using wrong operator like - or * instead of +
  • Forgetting lambda syntax
  • Mixing parameter order
3.

What is the output of this C# code?

var numbers = new[] {1, 2, 3};
var words = new[] {"one", "two"};
var zipped = numbers.Zip(words, (n, w) => $"{n}:{w}");
foreach(var item in zipped) Console.Write(item + " ");
medium
A. 1:one 2:two 3:
B. one:1 two:2
C. 1:one 2:two
D. 1:one 2:two 3:three

Solution

  1. Step 1: Check lengths of arrays

    numbers has 3 elements, words has 2 elements; Zip stops at shorter length (2).
  2. Step 2: Pair elements and format output

    Pairs: (1, "one"), (2, "two"); output strings: "1:one", "2:two".
  3. Final Answer:

    1:one 2:two -> Option C
  4. Quick Check:

    Zip stops at shorter list = C [OK]
Hint: Zip stops at shorter list length, so output matches shortest [OK]
Common Mistakes:
  • Expecting output for all elements of longer list
  • Mixing order of elements in output
  • Adding extra spaces or elements
4.

Identify the error in this code snippet using Zip:

var a = new[] {1, 2, 3};
var b = new[] {4, 5};
var result = a.Zip(b, (x, y) => x + y).ToList();
Console.WriteLine(result[2]);
medium
A. Syntax error in Zip lambda expression
B. Index out of range exception at result[2]
C. Null reference exception
D. No error, prints 7

Solution

  1. Step 1: Understand Zip output length

    Zip stops at shorter array length, so result has 2 elements only.
  2. Step 2: Accessing invalid index

    Accessing result[2] (third element) causes IndexOutOfRangeException.
  3. Final Answer:

    Index out of range exception at result[2] -> Option B
  4. Quick Check:

    Accessing beyond Zip length causes error = A [OK]
Hint: Zip result length = shorter input length; check indexes [OK]
Common Mistakes:
  • Assuming Zip output length equals longer list
  • Ignoring zero-based indexing
  • Confusing syntax errors with runtime errors
5.

You have two lists:

var keys = new[] {"a", "b", "c", "d"};
var values = new[] {1, 2, 3};

Using Zip, how can you create a dictionary that pairs keys and values only for matching positions?

hard
A. keys.Zip(values, (k, v) => new {k, v}).ToDictionary(x => x.k, x => x.v)
B. keys.Select((k, i) => new {k, v = values[i]}).ToDictionary(x => x.k, x => x.v)
C. keys.Concat(values).ToDictionary(k => k, v => v)
D. values.Zip(keys, (k, v) => new {k, v}).ToDictionary(x => x.k, x => x.v)

Solution

  1. Step 1: Use Zip to pair keys and values

    Zip pairs elements by position, stopping at shorter list length (3 pairs).
  2. Step 2: Convert pairs to dictionary

    Create anonymous objects with key and value, then call ToDictionary with key and value selectors.
  3. Final Answer:

    keys.Zip(values, (k, v) => new {k, v}).ToDictionary(x => x.k, x => x.v) -> Option A
  4. Quick Check:

    Zip pairs + ToDictionary = A [OK]
Hint: Zip keys and values, then ToDictionary with selectors [OK]
Common Mistakes:
  • Using Concat instead of Zip
  • Reversing keys and values in Zip
  • Using Select without bounds check causing errors
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard