Why records were introduced in C Sharp (C#) - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare a record type named Person.

C Sharp (C#)

public [1] Person(string Name, int Age);

Drag options to blanks, or click blank then click option'

Arecord

Bclass

Cstruct

Dinterface

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'class' instead of 'record' will create a normal class without value equality.

Using 'struct' creates a value type but lacks record features.

The record keyword declares a record type, which is a reference type with value-based equality.

2fill in blank

medium

Complete the code to create a new Person record with name 'Alice' and age 30.

C Sharp (C#)

var person = new Person([1], 30);

Drag options to blanks, or click blank then click option'

A"Alice"

BAlice

Cperson.Name

D30

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting quotes around string literals causes errors.

Using variable names instead of string literals.

String values must be enclosed in double quotes in C#.

3fill in blank

hard

Fix the error in comparing two Person records for equality.

C Sharp (C#)

bool areEqual = person1 [1] person2;

Drag options to blanks, or click blank then click option'

Aequals

B!=

C==

D=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' instead of '==' causes assignment, not comparison.

Using 'equals' is not a valid operator in C#.

Records support value-based equality using the == operator.

4fill in blank

hard

Fill in the blank to create a copy of a Person record with a changed Age.

C Sharp (C#)

var olderPerson = person with [1];

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A[ Age = 31 ]

B( Age = 31 )

C< Age = 31 >

D{ Age = 31 }

Attempts:

3 left

💡 Hint

Common Mistakes

Using parentheses or brackets instead of braces causes syntax errors.

Omitting braces entirely is invalid syntax.

The with expression uses braces to specify property changes in a record copy.

5fill in blank

hard

Fill all three blanks to define a record with positional parameters and override ToString method.

C Sharp (C#)

public [1] Person(string Name, int Age) {
    public override string ToString() => $"[2] is [3] years old.";
}

Drag options to blanks, or click blank then click option'

Arecord

Bclass

CName

DAge

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'class' instead of 'record' loses record benefits.

Using incorrect property names in the string causes errors.

Records are declared with record. The ToString method uses the properties Name and Age to display info.