Generic class declaration in C Sharp (C#) - Mini Project: Build & Apply

Generic class declaration

📖 Scenario: You are creating a simple container that can hold any type of item. This container will be a generic class so it can store different types without rewriting code.

🎯 Goal: Build a generic class called Box that can store one item of any type. Then create an instance of Box for an integer and store a number inside it.

📋 What You'll Learn

Create a generic class named Box with one type parameter T.

Add a public property Item of type T with get and set accessors.

Create an instance of Box for int type named intBox.

Set the Item property of intBox to the integer value 123.

Print the value of intBox.Item.

💡 Why This Matters

🌍 Real World

Generic classes let you write flexible code that works with many data types without repeating yourself.

💼 Career

Understanding generics is important for writing reusable and type-safe code in professional C# development.

1

Create the generic class Box

Write a generic class declaration named Box with one type parameter T. Inside it, declare a public property Item of type T with get and set accessors.

C Sharp (C#)

// Your code here

Hint

Use public class Box<T> to declare the generic class. Then add a property Item of type T with get and set.

2

Create an instance of Box for integers

Create a variable named intBox and assign it a new instance of Box for the type int.

C Sharp (C#)

public class Box
{
    public T Item { get; set; }
}

// Your code here

Hint

Use Box<int> intBox = new Box<int>(); to create the instance.

3

Set the Item property of intBox

Assign the integer value 123 to the Item property of intBox.

C Sharp (C#)

public class Box
{
    public T Item { get; set; }
}

Box intBox = new Box();

// Your code here

Hint

Use intBox.Item = 123; to store the number.

4

Print the value stored in intBox.Item

Write a Console.WriteLine statement to print the value of intBox.Item.

C Sharp (C#)

public class Box
{
    public T Item { get; set; }
}

Box intBox = new Box();
intBox.Item = 123;

// Your code here

Hint

Use Console.WriteLine(intBox.Item); inside a Main method to print the value.

Practice

1.

What is the main purpose of declaring a generic class in C# using <T>?

easy

A. To allow the class to work with any data type safely

B. To restrict the class to only one specific data type

C. To make the class run faster by avoiding type checks

D. To create multiple classes with different names automatically

Solution

1. Step 1: Understand generic class purpose

   Generic classes use type parameters to work with any data type, improving code reuse and safety.

2. Step 2: Compare options with generic concept

   Only To allow the class to work with any data type safely correctly states that generics allow safe use with any data type.

3. Final Answer:

   To allow the class to work with any data type safely -> Option A

4. Quick Check:

   Generic class purpose = safe, reusable code [OK]

Hint: Generics = flexible types for safe reuse [OK]

Common Mistakes:

• Thinking generics restrict to one type
• Believing generics improve speed by skipping checks
• Confusing generics with automatic class creation

2.

Which of the following is the correct syntax to declare a generic class named Box with one type parameter?

?

easy

A. public class Box<T>() { }

B. public class Box<T> { }

C. public class Box(T) { }

D. public class Box[] { }

Solution

1. Step 1: Recall generic class syntax

   Generic classes use angle brackets with type parameters: class ClassName<T>.

2. Step 2: Check each option

   public class Box<T> { } matches correct syntax. Options A, B, and D have syntax errors or wrong symbols.

3. Final Answer:

   public class Box<T> { } -> Option B

4. Quick Check:

   Generic syntax = class Name<T> [OK]

Hint: Generic classes use angle brackets <> [OK]

Common Mistakes:

• Using parentheses instead of angle brackets
• Adding parentheses after class name
• Using square brackets instead of angle brackets

3.

What will be the output of the following C# code?

public class Container<T> {
    public T Value;
    public Container(T value) { Value = value; }
    public override string ToString() => $"Value: {Value}";
}

var intBox = new Container<int>(10);
var strBox = new Container<string>("Hello");
Console.WriteLine(intBox);
Console.WriteLine(strBox);

medium

A. Value: 10
Value: Hello

B. Value: intBox
Value: strBox

C. 10
Hello

D. Compilation error due to missing type constraints

Solution

1. Step 1: Understand class behavior

   The class stores a value of type T and overrides ToString() to print "Value: {Value}".

2. Step 2: Trace output of Console.WriteLine

   intBox.ToString() returns "Value: 10" and strBox.ToString() returns "Value: Hello".

3. Final Answer:

   Value: 10 Value: Hello -> Option A

4. Quick Check:

   ToString override prints value with prefix [OK]

Hint: ToString() shows formatted value, not variable name [OK]

Common Mistakes:

• Expecting variable names instead of values
• Ignoring ToString() override
• Thinking type constraints are required here

4.

Identify the error in this generic class declaration and fix it:

public class Pair<T, U>
{
    public T First;
    public U Second;

    public Pair(T first, U second)
    {
        First = first;
        Second = second;
    }
}

var p = new Pair<string>(5, "test");

medium

A. Generic class cannot have two type parameters

B. Constructor parameters should be swapped

C. Missing type arguments when creating instance: use new Pair<int, string>(5, "test")

D. Fields First and Second must be private

Solution

1. Step 1: Check instance creation syntax

   Generic classes require type arguments when instantiated unless using C# 7.1+ with target-typed new.

2. Step 2: Identify missing type arguments

   The code uses new Pair<string>(5, "test") without specifying <int, string>, causing error.

3. Final Answer:

   Missing type arguments when creating instance: use new Pair<int, string>(5, "test") -> Option C

4. Quick Check:

   Generic instantiation needs type args [OK]

Hint: Always specify type parameters when creating generic instances [OK]

Common Mistakes:

• Omitting type arguments on new
• Thinking generic classes can't have multiple parameters
• Changing constructor parameter order unnecessarily

5.

You want to create a generic class Cache<TKey, TValue> that stores key-value pairs and only allows reference types for TValue. Which declaration is correct?

hard

A. public class Cache<TKey, TValue> where TKey : struct { }

B. public class Cache<TKey, TValue> where TValue : struct { }

C. public class Cache<TKey, TValue> where TKey : class { }

D. public class Cache<TKey, TValue> where TValue : class { }

Solution

1. Step 1: Understand type constraints

   To restrict a generic type to reference types, use where Type : class.

2. Step 2: Apply constraint to TValue

   The question requires TValue to be a reference type, so constraint applies to TValue.

3. Final Answer:

   public class Cache<TKey, TValue> where TValue : class { } -> Option D

4. Quick Check:

   Reference type constraint = where TValue : class [OK]

Hint: Use 'where TValue : class' to restrict to reference types [OK]

Common Mistakes:

• Applying constraint to wrong type parameter
• Using 'struct' instead of 'class' for reference types
• Omitting constraints when needed