Expression-bodied lambdas in C Sharp (C#) - Mini Project: Build & Apply

Expression-bodied Lambdas in C#

📖 Scenario: You are working on a small program that processes a list of numbers. You want to use simple functions to perform calculations on these numbers.

🎯 Goal: Learn how to write expression-bodied lambda functions in C# to make your code shorter and easier to read.

📋 What You'll Learn

Create a list of integers

Create an expression-bodied lambda to double a number

Use the lambda to create a new list with doubled values

Print the new list

💡 Why This Matters

🌍 Real World

Expression-bodied lambdas are used to write short, clear functions for data processing, event handling, and callbacks in many C# applications.

💼 Career

Knowing how to write concise lambdas helps you write cleaner code and work efficiently in C# development jobs.

1

Create a list of integers

Create a list of integers called numbers with these exact values: 1, 2, 3, 4, 5

C Sharp (C#)

# Create the list called numbers with values 1, 2, 3, 4, 5
// Your code here

Need a hint?

Use List<int> and initialize it with the values inside curly braces.

2

Create an expression-bodied lambda to double a number

Create an expression-bodied lambda called doubleNumber that takes an int parameter n and returns n * 2

C Sharp (C#)

using System.Collections.Generic;

List numbers = new List { 1, 2, 3, 4, 5 };

// Create the expression-bodied lambda doubleNumber here
// Your code here

Need a hint?

Use Func<int, int> and the lambda arrow => with a single expression.

3

Use the lambda to create a new list with doubled values

Create a new list of integers called doubledNumbers by using numbers.ConvertAll with the doubleNumber lambda

C Sharp (C#)

using System;
using System.Collections.Generic;

List numbers = new List { 1, 2, 3, 4, 5 };

Func doubleNumber = n => n * 2;

// Create doubledNumbers list using numbers.ConvertAll and doubleNumber
// Your code here

Need a hint?

Use ConvertAll method on the numbers list and pass doubleNumber as the converter.

4

Print the new list

Use a foreach loop to print each number in doubledNumbers on its own line

C Sharp (C#)

using System;
using System.Collections.Generic;

List numbers = new List { 1, 2, 3, 4, 5 };

Func doubleNumber = n => n * 2;

List doubledNumbers = numbers.ConvertAll(doubleNumber);

// Print each number in doubledNumbers using foreach
// Your code here

Need a hint?

Use foreach (int num in doubledNumbers) and inside the loop use Console.WriteLine(num);.