Async and await keywords in C Sharp (C#) - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare an asynchronous method.

C Sharp (C#)

public [1] Task<int> GetNumberAsync() {
    return Task.FromResult(5);
}

Drag options to blanks, or click blank then click option'

Aasync

Bawait

Cstatic

Dvoid

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'await' instead of 'async' in the method declaration.

Using 'void' as return type for async methods that return a value.

The async keyword marks a method as asynchronous, allowing use of await inside it.

2fill in blank

medium

Complete the code to wait for the asynchronous method to finish and get the result.

C Sharp (C#)

int result = [1] GetNumberAsync();

Drag options to blanks, or click blank then click option'

ATask

Basync

Cawait

Dreturn

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'async' instead of 'await' when calling the method.

Not using any keyword and trying to assign the Task directly to an int.

The await keyword waits for the asynchronous method to complete and returns its result.

3fill in blank

hard

Fix the error in the asynchronous method by completing the code.

C Sharp (C#)

public async Task<string> GetMessageAsync() {
    [1] Task.Delay(1000);
    return "Done";
}

Drag options to blanks, or click blank then click option'

Aasync

Bawait

Creturn

Dyield

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting to use 'await' before Task.Delay.

Using 'async' inside the method body instead of in the method signature.

The await keyword is needed to wait for the delay to complete before continuing.

4fill in blank

hard

Fill both blanks to create an asynchronous method that returns the length of a string after a delay.

C Sharp (C#)

public [1] Task<int> GetLengthAsync(string text) {
    [2] Task.Delay(500);
    return Task.FromResult(text.Length);
}

Drag options to blanks, or click blank then click option'

Aasync

Bawait

Cstatic

Dvoid

Attempts:

3 left

💡 Hint

Common Mistakes

Not marking the method as async.

Not awaiting the Task.Delay call.

The method must be marked async and use await to wait for the delay.

5fill in blank

hard

Fill all three blanks to create an async method that awaits a delay, then returns the uppercase version of a string.

C Sharp (C#)

public [1] Task<string> ConvertToUpperAsync(string input) {
    [2] Task.Delay(700);
    return Task.FromResult(input[3]);
}

Drag options to blanks, or click blank then click option'

Aasync

Bawait

C.ToUpper()

D.ToLower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using .ToLower() instead of .ToUpper().

Forgetting to await the Task.Delay.

Not marking the method as async.

The method is marked async, uses await to wait for the delay, and calls .ToUpper() on the input string.

Practice

1. What is the main purpose of the async keyword in C#?

easy

A. To make a method run faster by using multiple threads automatically

B. To mark a method that can run asynchronously without blocking the caller

C. To declare a method that returns void only

D. To pause the execution of a method until a task completes

Solution

1. Step 1: Understand the role of async

   The async keyword marks a method so it can run asynchronously, allowing other work to continue without waiting.

2. Step 2: Differentiate from other options

   It does not automatically make code faster or use multiple threads, nor does it pause execution by itself.

3. Final Answer:

   To mark a method that can run asynchronously without blocking the caller -> Option B

4. Quick Check:

   async marks asynchronous methods = A [OK]

Hint: Async marks methods that run without blocking [OK]

Common Mistakes:

• Thinking async makes code multithreaded automatically
• Confusing async with pausing execution
• Believing async only works with void methods

2. Which of the following is the correct way to declare an asynchronous method that returns a string in C#?

easy

A. public string async GetData()

B. public async string GetData()

C. public Task async<string> GetData()

D. public async Task<string> GetData()

Solution

1. Step 1: Recall async method return types

   Async methods that return a value must return Task<T>, where T is the return type, here string.

2. Step 2: Check syntax correctness

   public async Task<string> GetData() correctly uses async Task<string>. Other options have wrong order or missing Task.

3. Final Answer:

   public async Task<string> GetData() -> Option D

4. Quick Check:

   Async methods returning values use Task<T> = A [OK]

Hint: Async methods returning values use Task<T> type [OK]

Common Mistakes:

• Placing async after return type
• Returning just string instead of Task<string>
• Using async keyword incorrectly in method signature

3. What will be the output of the following C# code?

async Task<int> GetNumberAsync() { await Task.Delay(100); return 5; }
async Task Main() { var result = await GetNumberAsync(); Console.WriteLine(result); }

medium

A. 5

B. 0

C. Task

D. Compilation error

Solution

1. Step 1: Understand async method behavior

   The method GetNumberAsync waits 100ms then returns 5 asynchronously.

2. Step 2: Await the result and print

   The Main method awaits GetNumberAsync and prints the returned value, which is 5.

3. Final Answer:

   5 -> Option A

4. Quick Check:

   Await returns method result = 5 [OK]

Hint: Await unwraps async result to actual value [OK]

Common Mistakes:

• Expecting Task object printed instead of value
• Ignoring await causing wrong output
• Thinking async delays block main thread

4. Identify the error in this code snippet:

async Task<int> CalculateAsync() { return 10; }
void Main() { var result = CalculateAsync(); Console.WriteLine(result); }

medium

A. Missing await keyword when calling CalculateAsync

B. CalculateAsync should return int, not Task<int>

C. Main method must be async to call CalculateAsync

D. CalculateAsync cannot return a value

Solution

1. Step 1: Analyze method call and return type

   CalculateAsync returns a Task<int>, but Main calls it without await, so result is a Task, not int.

2. Step 2: Understand how to get actual value

   To get the int value, await must be used, but Main is not async, so this is a problem.

3. Final Answer:

   Missing await keyword when calling CalculateAsync -> Option A

4. Quick Check:

   Call async method with await = C [OK]

Hint: Always await async calls to get results [OK]

Common Mistakes:

• Calling async method without await
• Expecting async method to return direct value
• Making Main async without proper signature

5. You want to run two independent async tasks and get their results as soon as both finish. Which code correctly does this in C#?

hard

A. var result1 = await Task1(); var result2 = await Task2();

B. var result1 = Task1().Result; var result2 = Task2().Result;

C. var task1 = Task1(); var task2 = Task2(); var result1 = await task1; var result2 = await task2;

D. await Task.WhenAll(Task1(), Task2()); var result1 = Task1().Result; var result2 = Task2().Result;

Solution

1. Step 1: Understand running tasks concurrently

   Starting both tasks without awaiting immediately lets them run in parallel.

2. Step 2: Await both tasks after starting

   Awaiting each task after starting both ensures you wait for both to finish and get results efficiently.

3. Step 3: Analyze other options

   var result1 = await Task1(); var result2 = await Task2(); awaits sequentially, running tasks one after another. var result1 = Task1().Result; var result2 = Task2().Result; blocks synchronously causing deadlocks. await Task.WhenAll(Task1(), Task2()); var result1 = Task1().Result; var result2 = Task2().Result; awaits but then calls Result again, causing redundant calls.

4. Final Answer:

   var task1 = Task1(); var task2 = Task2(); var result1 = await task1; var result2 = await task2; -> Option C

5. Quick Check:

   Start tasks first, then await both = B [OK]

Hint: Start tasks first, then await both to run concurrently [OK]

Common Mistakes:

• Awaiting tasks one by one causing sequential execution
• Using .Result causing blocking and deadlocks
• Calling tasks multiple times causing duplicate work