Latching circuit (seal-in logic) in PLC Programming - Time & Space Complexity
We want to understand how the time it takes to run a latching circuit program changes as the input size changes.
Specifically, we ask: How does the program's execution time grow when the number of inputs or cycles increases?
Analyze the time complexity of the following code snippet.
// Simple latching circuit (seal-in logic)
IF StartButton THEN
Motor := TRUE;
ELSIF StopButton THEN
Motor := FALSE;
ELSE
Motor := Motor; // Keep previous state
END_IF;
This code keeps a motor running after pressing start until stop is pressed, using seal-in logic.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: The program runs this logic once every scan cycle.
- How many times: It repeats continuously, once per cycle, but no loops inside the code.
The program checks inputs and updates output once per cycle, regardless of input size.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | 2 checks + 1 assignment |
| 100 | 2 checks + 1 assignment |
| 1000 | 2 checks + 1 assignment |
Pattern observation: The number of operations stays the same no matter how many cycles or inputs, because the logic is simple and fixed.
Time Complexity: O(1)
This means the program takes about the same time to run each cycle, no matter how many times it runs or how many inputs it has.
[X] Wrong: "The program takes longer as the motor runs longer because it keeps checking forever."
[OK] Correct: Each cycle runs the same simple checks quickly; the length of running time does not add more work per cycle.
Understanding how simple control logic runs efficiently helps you explain how automation programs handle real-time tasks smoothly.
"What if we added a loop inside the logic to check multiple sensors? How would the time complexity change?"
Practice
latching circuit (seal-in logic) in PLC programming?Solution
Step 1: Understand the function of latching circuits
Latching circuits keep an output ON even after the start input is released.Step 2: Identify the stop input role
The stop input breaks the latch, turning the output OFF safely.Final Answer:
To keep a device ON after pressing start until stop is pressed -> Option AQuick Check:
Latching circuit = Keeps device ON until stopped [OK]
- Thinking latch turns device OFF immediately after start
- Confusing latch with reset logic
- Ignoring the stop input function
Start, stop pushbutton Stop, and output coil Motor?Solution
Step 1: Check the order of stop and start contacts
Stop is normally closed and should be first to allow breaking the circuit; start is normally open and second.Step 2: Confirm the seal-in contact
The output coil Motor is used as a contact in parallel with Start to latch the circuit.Final Answer:
Stop first, then Start, with Motor contact in parallel to Start -> Option CQuick Check:
Stop before Start, Motor seals in [OK]
- Placing Start before Stop contact
- Missing Motor contact in parallel
- Confusing normally open and normally closed contacts
|---[Stop]---[Start]---(Motor)---| | | | | +----(Motor)---------|
If the Start button is pressed and released, then the Stop button is pressed, what is the state of
Motor output?Solution
Step 1: Analyze pressing Start
Pressing Start energizes Motor coil, which closes Motor contact in parallel, latching the circuit ON.Step 2: Analyze pressing Stop
Pressing Stop opens the circuit, breaking the latch and turning Motor OFF.Final Answer:
Motor stays ON after Start release, OFF when Stop pressed -> Option BQuick Check:
Latching holds Motor ON until Stop breaks it [OK]
- Thinking Motor turns OFF immediately after Start release
- Ignoring Stop button effect
- Confusing latch with toggle
|---[Start]---[Stop]---(Motor)---| | | | | +----(Motor)---------|
Solution
Step 1: Check contact order
Stop contact should be first and normally closed to allow breaking the circuit safely.Step 2: Confirm Start contact position
Start contact should be after Stop and normally open to energize Motor.Final Answer:
Start and Stop contacts are in wrong order; Stop should be first -> Option DQuick Check:
Stop first, then Start for correct latch [OK]
- Placing Start before Stop
- Confusing normally open/closed contacts
- Missing Motor contact in parallel
Safety is closed. Which ladder logic modification correctly adds this condition?Solution
Step 1: Understand safety switch role
Safety must be closed to allow motor start; it should be in series to block power if open.Step 2: Place Safety contact correctly
Putting Safety in series before Start and Motor ensures motor cannot latch if Safety is open.Final Answer:
Add Safety contact in series before Start and Motor contacts -> Option AQuick Check:
Safety in series blocks motor if open [OK]
- Placing Safety in parallel, bypassing it
- Putting Safety after Motor coil, ineffective
- Confusing series and parallel placement
Ready to prove it?
Pass the test and this pattern moves unknown
