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Emergency stop implementation in PLC Programming - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to define the emergency stop input.

PLC Programming
EM_STOP := [1];
Drag options to blanks, or click blank then click option'
AOutput1
BInput1
CTimer1
DCounter1
Attempts:
3 left
💡 Hint
Common Mistakes
Using an output or timer instead of an input.
Confusing input and output variables.
2fill in blank
medium

Complete the code to stop the motor when emergency stop is pressed.

PLC Programming
IF [1] = TRUE THEN
  Motor := FALSE;
END_IF;
Drag options to blanks, or click blank then click option'
AStart_Button
BMotor
CEM_STOP
DTimer1
Attempts:
3 left
💡 Hint
Common Mistakes
Checking the motor variable instead of the emergency stop input.
Using the start button variable by mistake.
3fill in blank
hard

Fix the error in the emergency stop logic to ensure motor stops immediately.

PLC Programming
IF EM_STOP [1] TRUE THEN
  Motor := FALSE;
END_IF;
Drag options to blanks, or click blank then click option'
A<>
B==
C!=
D=
Attempts:
3 left
💡 Hint
Common Mistakes
Using ':=' which assigns instead of compares.
Using '!=' or '<>' which check inequality.
4fill in blank
hard

Fill both blanks to create a safety check that resets the motor only if emergency stop is not pressed and start button is pressed.

PLC Programming
IF EM_STOP [1] FALSE AND Start_Button [2] TRUE THEN
  Motor := TRUE;
END_IF;
Drag options to blanks, or click blank then click option'
A==
B=
C!=
D<>
Attempts:
3 left
💡 Hint
Common Mistakes
Using assignment ':=' instead of comparison '='.
Mixing equality and inequality operators.
5fill in blank
hard

Fill all three blanks to implement a complete emergency stop logic: stop motor if emergency stop pressed, else start motor if start button pressed and safety sensor is OK.

PLC Programming
IF EM_STOP [1] TRUE THEN
  Motor := FALSE;
ELSIF Start_Button [2] TRUE AND Safety_Sensor [3] TRUE THEN
  Motor := TRUE;
END_IF;
Drag options to blanks, or click blank then click option'
A==
B=
C!=
D<>
Attempts:
3 left
💡 Hint
Common Mistakes
Using ':=' instead of '=' in conditions.
Using inequality operators incorrectly.

Practice

(1/5)
1. What is the main purpose of an emergency stop in a PLC program?
easy
A. To immediately stop the machine for safety reasons
B. To start the machine automatically
C. To increase the machine speed
D. To reset the machine after a fault

Solution

  1. Step 1: Understand emergency stop function

    The emergency stop is designed to stop machines immediately to protect people from harm.
  2. Step 2: Identify correct purpose

    Stopping the machine immediately for safety is the key role of the emergency stop.
  3. Final Answer:

    To immediately stop the machine for safety reasons -> Option A
  4. Quick Check:

    Emergency stop = immediate machine stop [OK]
Hint: Emergency stop always stops machine immediately [OK]
Common Mistakes:
  • Thinking emergency stop starts the machine
  • Confusing emergency stop with reset
  • Assuming it controls speed
2. Which of the following is the correct way to check an emergency stop button input named ESTOP in ladder logic?
easy
A. Timer instruction on ESTOP input
B. Normally Open contact of ESTOP input
C. Normally Closed contact of ESTOP input
D. Counter instruction on ESTOP input

Solution

  1. Step 1: Understand emergency stop wiring

    Emergency stop buttons are usually wired as Normally Closed (NC) contacts for safety, so pressing opens the circuit.
  2. Step 2: Use Normally Closed contact in logic

    In ladder logic, use the Normally Closed contact of ESTOP input to detect if the button is pressed (circuit open).
  3. Final Answer:

    Normally Closed contact of ESTOP input -> Option C
  4. Quick Check:

    ESTOP uses NC contact in ladder [OK]
Hint: Emergency stops use Normally Closed contacts [OK]
Common Mistakes:
  • Using Normally Open contact instead of Normally Closed
  • Using timers or counters incorrectly
  • Ignoring safety wiring standards
3. Given this ladder logic snippet for emergency stop:
--|/|--[ESTOP]----( )--[MOTOR_RUN]

What happens to MOTOR_RUN when the emergency stop button is pressed?
medium
A. MOTOR_RUN coil de-energizes and motor stops
B. MOTOR_RUN coil toggles state
C. MOTOR_RUN coil energizes and motor runs
D. No change to MOTOR_RUN coil

Solution

  1. Step 1: Interpret Normally Closed contact symbol

    The symbol |/| means Normally Closed contact of ESTOP input; it passes power when ESTOP is not pressed.
  2. Step 2: Effect of pressing ESTOP

    Pressing ESTOP opens the NC contact, breaking the circuit and de-energizing MOTOR_RUN coil, stopping the motor.
  3. Final Answer:

    MOTOR_RUN coil de-energizes and motor stops -> Option A
  4. Quick Check:

    Press ESTOP = MOTOR_RUN off [OK]
Hint: NC contact breaks circuit when pressed [OK]
Common Mistakes:
  • Confusing Normally Closed with Normally Open
  • Assuming coil toggles instead of stops
  • Ignoring contact state changes
4. This ladder logic is intended to implement an emergency stop:
--| |--[ESTOP]----( )--[MOTOR_RUN]

What is wrong with this implementation?
medium
A. Missing timer to delay motor stop
B. ESTOP input should be a counter
C. MOTOR_RUN coil is not connected
D. Using Normally Open contact for ESTOP can fail to stop motor

Solution

  1. Step 1: Check contact type used for ESTOP

    The logic uses Normally Open contact | | for ESTOP, which means motor runs only when ESTOP is pressed, opposite of safety design.
  2. Step 2: Understand safety wiring

    Emergency stops must use Normally Closed contacts to ensure motor stops immediately when pressed.
  3. Final Answer:

    Using Normally Open contact for ESTOP can fail to stop motor -> Option D
  4. Quick Check:

    ESTOP must use NC contact, not NO [OK]
Hint: Emergency stop must use NC contact, not NO [OK]
Common Mistakes:
  • Using Normally Open contact for emergency stop
  • Adding unnecessary timers
  • Misusing counters for inputs
5. You want to implement an emergency stop that overrides all other start commands for a motor. Which ladder logic snippet correctly achieves this?
--|/|--[ESTOP]----+----( )--[MOTOR_RUN]
                  |
--| |--[START]----+
hard
A. Use NO ESTOP contact in series with START to control MOTOR_RUN coil
B. Use NC ESTOP contact in series with START to control MOTOR_RUN coil
C. Use NC ESTOP contact in parallel with START to control MOTOR_RUN coil
D. Use NO ESTOP contact in parallel with START to control MOTOR_RUN coil

Solution

  1. Step 1: Analyze override logic

    Emergency stop must override start commands, so ESTOP NC contact should be in series to break circuit if pressed.
  2. Step 2: Check ladder logic structure

    NC ESTOP contact in series with START contact means if ESTOP is pressed, circuit breaks and MOTOR_RUN coil de-energizes regardless of START.
  3. Final Answer:

    Use NC ESTOP contact in series with START to control MOTOR_RUN coil -> Option B
  4. Quick Check:

    NC ESTOP in series overrides START [OK]
Hint: Put NC ESTOP contact in series to override start [OK]
Common Mistakes:
  • Placing ESTOP contact in parallel, losing override
  • Using NO contact for ESTOP
  • Not ensuring ESTOP breaks circuit immediately
Recommended

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10 questions~5 mineasy hard