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SQLquery~10 mins

Database design best practices in SQL - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a table with a primary key.

SQL
CREATE TABLE users (id INT [1] PRIMARY KEY, name VARCHAR(100));
Drag options to blanks, or click blank then click option'
AAUTO_INCREMENT
BUNIQUE
CNOT NULL
DDEFAULT
Attempts:
3 left
💡 Hint
Common Mistakes
Using UNIQUE alone does not auto-generate values.
NOT NULL only prevents nulls but does not auto-increment.
2fill in blank
medium

Complete the code to add a foreign key constraint.

SQL
ALTER TABLE orders ADD CONSTRAINT fk_user_id FOREIGN KEY (user_id) [1] users(id);
Drag options to blanks, or click blank then click option'
AJOINS
BLINKS
CCONNECTS
DREFERENCES
Attempts:
3 left
💡 Hint
Common Mistakes
Using LINKS or CONNECTS are not valid SQL keywords.
JOINS are used in queries, not in constraints.
3fill in blank
hard

Fix the error in the table creation by completing the code.

SQL
CREATE TABLE products (product_id INT PRIMARY KEY, price [1] DECIMAL(10, 2));
Drag options to blanks, or click blank then click option'
AUNIQUE
BAUTO_INCREMENT
CNOT NULL
DDEFAULT
Attempts:
3 left
💡 Hint
Common Mistakes
Using UNIQUE on price is not typical.
AUTO_INCREMENT is only for integer keys.
4fill in blank
hard

Fill both blanks to create a normalized table with a unique constraint.

SQL
CREATE TABLE employees (emp_id INT PRIMARY KEY, email VARCHAR(255) [1] [2]);
Drag options to blanks, or click blank then click option'
AUNIQUE
BNOT NULL
CDEFAULT
DAUTO_INCREMENT
Attempts:
3 left
💡 Hint
Common Mistakes
Forgetting NOT NULL allows empty emails.
Missing UNIQUE allows duplicate emails.
5fill in blank
hard

Fill all three blanks to create a table with a composite primary key and a foreign key.

SQL
CREATE TABLE enrollment (student_id INT, course_id INT, semester VARCHAR(10), PRIMARY KEY ([1], [2]), FOREIGN KEY (student_id) [3] students(id));
Drag options to blanks, or click blank then click option'
Astudent_id
Bcourse_id
CREFERENCES
Dsemester
Attempts:
3 left
💡 Hint
Common Mistakes
Using semester as part of the primary key is not typical here.
Forgetting REFERENCES causes foreign key errors.

Practice

(1/5)
1. Which of the following is a key reason to use primary keys in database tables?
easy
A. To store large amounts of text data
B. To create duplicate records easily
C. To speed up the database server hardware
D. To uniquely identify each record in the table

Solution

  1. Step 1: Understand the role of primary keys

    Primary keys uniquely identify each row in a table, preventing duplicates.
  2. Step 2: Compare options with primary key purpose

    Only To uniquely identify each record in the table describes uniqueness, which is the main purpose of primary keys.
  3. Final Answer:

    To uniquely identify each record in the table -> Option D
  4. Quick Check:

    Primary key = unique record ID [OK]
Hint: Primary keys always ensure unique records [OK]
Common Mistakes:
  • Thinking primary keys store large text
  • Confusing primary keys with performance hardware
  • Believing primary keys allow duplicates
2. Which SQL statement correctly creates a table with a primary key on the id column?
easy
A. CREATE TABLE users (id INT PRIMARY KEY, name VARCHAR(50));
B. CREATE TABLE users (id INT, name VARCHAR(50) PRIMARY KEY);
C. CREATE TABLE users (id INT, name VARCHAR(50), PRIMARY id);
D. CREATE TABLE users (id INT UNIQUE, name VARCHAR(50));

Solution

  1. Step 1: Review correct primary key syntax

    The primary key is declared as id INT PRIMARY KEY inside the column definition.
  2. Step 2: Check each option's syntax

    CREATE TABLE users (id INT PRIMARY KEY, name VARCHAR(50)); uses correct syntax; A has invalid syntax; B places PRIMARY KEY on wrong column; D uses UNIQUE but not PRIMARY KEY.
  3. Final Answer:

    CREATE TABLE users (id INT PRIMARY KEY, name VARCHAR(50)); -> Option A
  4. Quick Check:

    Primary key syntax = column_name TYPE PRIMARY KEY [OK]
Hint: Primary key goes right after the column type [OK]
Common Mistakes:
  • Placing PRIMARY KEY on wrong column
  • Using UNIQUE instead of PRIMARY KEY
  • Incorrect syntax for primary key declaration
3. Given these two tables:
CREATE TABLE authors (author_id INT PRIMARY KEY, name VARCHAR(100));
CREATE TABLE books (book_id INT PRIMARY KEY, title VARCHAR(100), author_id INT, FOREIGN KEY (author_id) REFERENCES authors(author_id));
What will happen if you try to insert a book with author_id = 5, but no author with author_id = 5 exists?
medium
A. The insert will succeed and create a new author automatically
B. The insert will fail due to foreign key constraint violation
C. The insert will succeed but author_id will be set to NULL
D. The insert will succeed but cause duplicate author records

Solution

  1. Step 1: Understand foreign key constraints

    Foreign keys require the referenced value to exist in the parent table to maintain data integrity.
  2. Step 2: Apply constraint to the insert operation

    Inserting a book with author_id = 5 fails if no author with id 5 exists, causing a constraint violation.
  3. Final Answer:

    The insert will fail due to foreign key constraint violation -> Option B
  4. Quick Check:

    Foreign key enforces existing parent record [OK]
Hint: Foreign keys block inserts without matching parent [OK]
Common Mistakes:
  • Assuming foreign keys auto-create missing parents
  • Thinking foreign keys allow NULL by default
  • Ignoring constraint errors on insert
4. You have a table orders with columns order_id (primary key), customer_id, and order_date. You want to add a foreign key constraint on customer_id referencing customers(customer_id). Which of these statements has an error?
medium
A. ALTER TABLE orders ADD FOREIGN KEY (customer_id) REFERENCES customers(customer_id);
B. ALTER TABLE orders ADD CONSTRAINT fk_customer FOREIGN KEY (customer_id) REFERENCES customers(customer_id);
C. ALTER TABLE orders ADD FOREIGN KEY customer_id REFERENCES customers(customer_id);
D. ALTER TABLE orders ADD CONSTRAINT fk_customer FOREIGN KEY (customer_id) REFERENCES customers(customer_id) ON DELETE CASCADE;

Solution

  1. Step 1: Review correct syntax for adding foreign keys

    The correct syntax requires parentheses around the column name after FOREIGN KEY.
  2. Step 2: Identify the incorrect statement

    ALTER TABLE orders ADD FOREIGN KEY customer_id REFERENCES customers(customer_id); misses parentheses around customer_id, causing syntax error.
  3. Final Answer:

    ALTER TABLE orders ADD FOREIGN KEY customer_id REFERENCES customers(customer_id); -> Option C
  4. Quick Check:

    Foreign key column must be in parentheses [OK]
Hint: Always use parentheses around foreign key columns [OK]
Common Mistakes:
  • Omitting parentheses around column names
  • Forgetting to name the constraint (optional but recommended)
  • Misplacing ON DELETE options
5. You are designing a database for a library. You want to track books, authors, and the categories each book belongs to. Which design best follows database design best practices?
hard
A. Separate tables for books, authors, and categories with primary keys and foreign keys linking them
B. Separate tables for books and categories only, storing author names as text in books
C. One table for books and authors combined, and a separate table for categories
D. One table with columns: book_id, book_title, author_name, category_name

Solution

  1. Step 1: Analyze normalization and relationships

    Best practice is to separate entities into tables and link them with keys to avoid duplication.
  2. Step 2: Evaluate each option's design

    Separate tables for books, authors, and categories with primary keys and foreign keys linking them uses separate tables with keys, which supports clear organization and data consistency.
  3. Final Answer:

    Separate tables for books, authors, and categories with primary keys and foreign keys linking them -> Option A
  4. Quick Check:

    Separate tables + keys = best design [OK]
Hint: Use separate tables and keys for related data [OK]
Common Mistakes:
  • Putting all data in one table causing duplicates
  • Mixing unrelated data in same table
  • Storing related entity names as plain text
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10 questions~5 mineasy hard