Variables and SET statements in SQL

Introduction

Variables let you store temporary values in your database session. SET statements assign values to these variables so you can use them later in your queries.

When you want to store a value to use multiple times in a query.

When you need to calculate a value once and reuse it in several places.

When you want to make your query easier to read by naming important values.

When you want to change a value quickly without rewriting the whole query.

Syntax

SQL

DECLARE @variable_name datatype;
SET @variable_name = value;

You must declare a variable before using SET to assign a value.

Variable names usually start with @ and have a datatype like INT or VARCHAR.

Examples

Declare an integer variable named @age and set its value to 30.

SQL

DECLARE @age INT;
SET @age = 30;

Declare a text variable @name with space for 50 characters and set it to 'Alice'.

SQL

DECLARE @name VARCHAR(50);
SET @name = 'Alice';

Declare a decimal variable @total and set it to 99.99.

SQL

DECLARE @total DECIMAL(10,2);
SET @total = 99.99;

Sample Program

This example declares a variable @count, sets it to 5, and then selects it to show the value.

SQL

DECLARE @count INT;
SET @count = 5;
SELECT @count AS NumberOfItems;

Important Notes

Variables exist only during the current session or batch.

You can change a variable's value by using SET again.

Some SQL systems also allow SELECT to assign variables, but SET is clearer.

Summary

Variables store temporary values in SQL queries.

Use DECLARE to create a variable and SET to assign a value.

Variables help make queries easier to write and understand.

Practice

1. What is the purpose of using variables in SQL with DECLARE and SET statements?

easy

A. To store temporary values that can be used later in the query

B. To permanently save data in the database

C. To create new tables automatically

D. To delete rows from a table

Solution

1. Step 1: Understand variable usage in SQL

   Variables declared with DECLARE hold temporary values during query execution.

2. Step 2: Identify the purpose of SET

   SET assigns values to these variables for use later in the query.

3. Final Answer:

   To store temporary values that can be used later in the query -> Option A

4. Quick Check:

   Variables = Temporary storage [OK]

Hint: Variables hold temporary data during query execution [OK]

Common Mistakes:

• Thinking variables save data permanently
• Confusing variables with table creation
• Assuming variables delete data

2. Which of the following is the correct syntax to declare an integer variable named @count and set its value to 10 in SQL?

easy

A. DECLARE @count INT; SET @count = 10;

B. SET @count INT; DECLARE @count = 10;

C. DECLARE @count = 10 INT;

D. SET @count = 10 INT;

Solution

1. Step 1: Review correct variable declaration syntax

   In SQL, DECLARE @variable_name TYPE; declares a variable.

2. Step 2: Assign value using SET

   SET @variable_name = value; assigns the value.

3. Final Answer:

   DECLARE @count INT; SET @count = 10; -> Option A

4. Quick Check:

   DECLARE then SET = correct syntax [OK]

Hint: Declare first, then set value with SET [OK]

Common Mistakes:

• Using SET before DECLARE
• Mixing declaration and assignment in wrong order
• Incorrect placement of data type

3. Consider the following SQL code:

DECLARE @x INT;
SET @x = 5;
SET @x = @x + 3;
SELECT @x;

What will be the output of the SELECT statement?

medium

A. 5

B. 8

C. 3

D. NULL

Solution

1. Step 1: Initialize variable @x

   @x is declared as integer and set to 5.

2. Step 2: Update @x by adding 3

   @x = 5 + 3 = 8.

3. Final Answer:

   8 -> Option B

4. Quick Check:

   5 + 3 = 8 [OK]

Hint: Add values stepwise to variable [OK]

Common Mistakes:

• Forgetting to update variable value
• Assuming variable resets after SET
• Confusing initial and updated values

4. Identify the error in the following SQL code:

DECLARE @total INT
SET total = 100;
SELECT @total;

medium

A. Missing semicolon after DECLARE statement

B. SELECT statement syntax is incorrect

C. Variable name missing '@' in SET statement

D. Variable @total not declared

Solution

1. Step 1: Check variable declaration

   @total is declared correctly with DECLARE @total INT.

2. Step 2: Check SET statement

   SET statement uses total without '@', which is incorrect; it should be @total.

3. Final Answer:

   Variable name missing '@' in SET statement -> Option C

4. Quick Check:

   Variable names need '@' prefix [OK]

Hint: Always use '@' before variable names [OK]

Common Mistakes:

• Omitting '@' in variable usage
• Forgetting semicolons (usually optional)
• Misreading SELECT syntax

5. You want to calculate the total price for 3 items each costing 15, 20, and 25 using variables. Which SQL code correctly declares variables, sets their values, and calculates the total?

hard

A. DECLARE @item1 INT = 15, @item2 INT = 20, @item3 INT = 25; SET @total = @item1 + @item2 + @item3; SELECT @total;

B. DECLARE @total INT; SET total = 15 + 20 + 25; SELECT @total;

C. SET @item1 = 15; SET @item2 = 20; SET @item3 = 25; SET @total = @item1 + @item2 + @item3; SELECT @total;

D. DECLARE @item1 INT; DECLARE @item2 INT; DECLARE @item3 INT; DECLARE @total INT; SET @item1 = 15; SET @item2 = 20; SET @item3 = 25; SET @total = @item1 + @item2 + @item3; SELECT @total;

Solution

1. Step 1: Declare all variables before use

   Variables @item1, @item2, @item3, and @total must be declared first.

2. Step 2: Assign values and calculate total

   Assign each item price with SET, then sum them into @total.

3. Step 3: Select the total value

   Use SELECT to output the total price.

4. Final Answer:

   DECLARE @item1 INT; DECLARE @item2 INT; DECLARE @item3 INT; DECLARE @total INT; SET @item1 = 15; SET @item2 = 20; SET @item3 = 25; SET @total = @item1 + @item2 + @item3; SELECT @total; -> Option D

5. Quick Check:

   Declare then set all variables before calculation [OK]

Hint: Declare all variables first, then assign and calculate [OK]

Common Mistakes:

• Assigning values without declaring variables
• Trying to declare and assign in one line incorrectly
• Missing variable declarations