Introduction
The ROW_NUMBER function helps you give a unique number to each row in your data, making it easy to order or pick specific rows.
ROW_NUMBER() OVER (PARTITION BY column1, column2, ... ORDER BY column3 [ASC|DESC], ...)
SELECT ROW_NUMBER() OVER (ORDER BY salary DESC) AS rank, employee_name, salary FROM employees;
SELECT department, employee_name, ROW_NUMBER() OVER (PARTITION BY department ORDER BY hire_date) AS hire_order FROM employees;
SELECT ROW_NUMBER() OVER (ORDER BY id) AS row_num, * FROM products;
WITH sales_data AS ( SELECT employee_id, department, sales_amount FROM sales ) SELECT employee_id, department, sales_amount, ROW_NUMBER() OVER (PARTITION BY department ORDER BY sales_amount DESC) AS sales_rank FROM sales_data;
ROW_NUMBER() function do in SQL?ROW_NUMBER() function assigns a unique sequential integer to rows in the result set, starting at 1.COUNT(), SUM(), or WHERE clause, not ROW_NUMBER().salary in descending order?ROW_NUMBER() OVER (ORDER BY column) to assign numbers ordered by a column.SELECT ROW_NUMBER() OVER (ORDER BY salary DESC) AS rn FROM employees; correctly uses OVER (ORDER BY salary DESC). The other options omit the OVER clause, pass arguments directly to ROW_NUMBER(), or misplace the ORDER BY clause.sales with columns region and amount, what will this query return?SELECT region, amount, ROW_NUMBER() OVER (PARTITION BY region ORDER BY amount DESC) AS rn FROM sales;
PARTITION BY region restarts the row numbering for each region group separately.amount DESC means the highest amount in each region gets row number 1, next highest 2, and so on.SELECT name, ROW_NUMBER() ORDER BY salary FROM employees;
ROW_NUMBER() function requires an OVER() clause specifying ordering or partitioning.ROW_NUMBER() without OVER(), which causes a syntax error. ORDER BY inside SELECT is invalid without OVER().employees table. Which query correctly uses ROW_NUMBER() to achieve this?rn <= 2 to get top 2 employees per department.Pass the test and this pattern moves unknown