Bird
Raised Fist0
Pandasdata~10 mins

Resampling time series data in Pandas - Step-by-Step Execution

Choose your learning style10 modes available
Concept Flow - Resampling time series data
Start with time series data
↓
Choose resampling frequency
↓
Apply resample() method
↓
Aggregate data (mean, sum, etc.)
↓
Get new resampled time series
↓
End
We start with time series data, pick a new time interval, resample using pandas, aggregate values, and get a new summarized time series.
Execution Sample
Pandas
import pandas as pd

# Create sample data
idx = pd.date_range('2024-01-01', periods=6, freq='H')
data = pd.Series([10, 20, 15, 30, 25, 40], index=idx)

# Resample hourly data to 3-hour intervals
resampled = data.resample('3H').mean()
print(resampled)
This code creates hourly data and resamples it to 3-hour intervals by averaging values.
Execution Table
StepActionInput DataResample FrequencyAggregationOutput Data
1Create hourly time series[10,20,15,30,25,40]Hourly (H)None2024-01-01 00:00:00 -> 10 2024-01-01 01:00:00 -> 20 2024-01-01 02:00:00 -> 15 2024-01-01 03:00:00 -> 30 2024-01-01 04:00:00 -> 25 2024-01-01 05:00:00 -> 40
2Choose resample frequencyHourly data3 Hours (3H)NonePreparing to group data into 3-hour bins
3Group data into 3-hour binsHourly data3HNoneBin 1: 00:00-02:59 -> [10,20,15] Bin 2: 03:00-05:59 -> [30,25,40]
4Aggregate each bin by meanBins3HMeanBin 1 mean: (10+20+15)/3 = 15 Bin 2 mean: (30+25+40)/3 = 31.67
5Create new resampled seriesAggregated means3HMean2024-01-01 00:00:00 -> 15 2024-01-01 03:00:00 -> 31.67
6Print resampled dataResampled series3HMeanOutput: 2024-01-01 00:00:00 15.00 2024-01-01 03:00:00 31.67 Freq: 3H, dtype: float64
💡 All original data grouped and aggregated into 3-hour intervals, resampling complete.
Variable Tracker
VariableStartAfter Step 1After Step 3After Step 4Final
dataNone[10,20,15,30,25,40] hourly indexed[[10,20,15],[30,25,40]] grouped by 3H[15, 31.67] means of groups[15, 31.67] resampled series
resampledNoneNoneNoneNone[15.0, 31.67] with 3H freq
Key Moments - 3 Insights
Why does the resampled series have fewer rows than the original?
Because resampling groups multiple original time points into larger intervals (3 hours here), so fewer aggregated points appear as shown in execution_table rows 3 and 5.
What happens if we use sum instead of mean for aggregation?
The grouped values would be added instead of averaged, changing the output values in step 4 and 5 accordingly.
Why is the new index at 00:00 and 03:00 after resampling?
Because pandas labels each resampled bin by the start time of the interval, as shown in execution_table row 5.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table at step 4, what is the mean of the first 3-hour bin?
A31.67
B15
C20
D10
💡 Hint
Check the 'Output Data' column at step 4 for the first bin's mean.
At which step does the data get grouped into 3-hour bins?
AStep 4
BStep 2
CStep 3
DStep 5
💡 Hint
Look for the step describing grouping in the 'Action' column.
If we changed the resample frequency to '2H', how would the number of output rows change?
AMore rows than with '3H'
BFewer rows than with '3H'
CSame number of rows
DNo rows
💡 Hint
Refer to variable_tracker 'data' row showing grouping by frequency.
Concept Snapshot
Resampling time series data with pandas:
- Use .resample('freq') on a time-indexed series or DataFrame
- 'freq' is new time interval (e.g., '3H' for 3 hours)
- Aggregate grouped data with mean(), sum(), etc.
- Result is a new time series with fewer or more points
- Index labels are interval start times
Full Transcript
This visual execution shows how pandas resamples time series data. We start with hourly data points. We pick a new frequency, here 3 hours. The data is grouped into 3-hour bins. Each bin's values are aggregated by mean. The output is a new series with fewer points, each representing the average over 3 hours. The index labels are the start times of each 3-hour interval. This process helps summarize or change the time scale of data easily.

Practice

(1/5)
1. What does resampling a time series in pandas usually do?
easy
A. Sort the data by values in ascending order
B. Remove all missing values from the dataset
C. Change the time frequency of the data to summarize or expand it
D. Convert the data into a different file format

Solution

  1. Step 1: Understand the purpose of resampling

    Resampling changes how often data points appear in time, either by grouping or expanding.
  2. Step 2: Identify what resampling affects

    It changes the time frequency, not sorting or file formats.
  3. Final Answer:

    Change the time frequency of the data to summarize or expand it -> Option C
  4. Quick Check:

    Resampling = Change frequency [OK]
Hint: Resampling changes how often data points appear in time [OK]
Common Mistakes:
  • Confusing resampling with sorting data
  • Thinking resampling removes missing values automatically
  • Believing resampling changes file formats
2. Which of the following is the correct syntax to downsample a pandas DataFrame df with a datetime index to monthly frequency and calculate the mean?
easy
A. df.resample('M').mean()
B. df.resample('M').sum()
C. df.resample('D').mean()
D. df.resample('M').fillna()

Solution

  1. Step 1: Identify the correct resample frequency for monthly data

    'M' stands for month-end frequency in pandas resampling.
  2. Step 2: Choose the correct aggregation function

    To calculate the mean after downsampling, use .mean().
  3. Final Answer:

    df.resample('M').mean() -> Option A
  4. Quick Check:

    Monthly mean = df.resample('M').mean() [OK]
Hint: Use 'M' for monthly and .mean() to aggregate [OK]
Common Mistakes:
  • Using 'D' instead of 'M' for monthly frequency
  • Using sum() when mean() is asked
  • Calling fillna() without upsampling
3. Given the following code, what will be the output of print(resampled)?
import pandas as pd
idx = pd.date_range('2023-01-01', periods=4, freq='D')
data = [10, 20, 30, 40]
df = pd.DataFrame({'value': data}, index=idx)
resampled = df.resample('2D').sum()
medium
A. value 2023-01-01 30 2023-01-03 70
B. value 2023-01-01 10 2023-01-02 20 2023-01-03 30 2023-01-04 40
C. value 2023-01-01 15 2023-01-03 35
D. {'2023-01-01': 30, '2023-01-03': 70}

Solution

  1. Step 1: Understand resampling with '2D' and sum aggregation

    Resampling with '2D' groups data every 2 days and sums values in each group.
  2. Step 2: Calculate sums for each 2-day period

    First period: 2023-01-01 + 2023-01-02 = 10 + 20 = 30; Second period: 2023-01-03 + 2023-01-04 = 30 + 40 = 70.
  3. Final Answer:

    value 2023-01-01 30 2023-01-03 70 -> Option A
  4. Quick Check:

    Sum every 2 days = 30, 70 [OK]
Hint: Sum values in 2-day groups after resampling [OK]
Common Mistakes:
  • Confusing sum with mean aggregation
  • Expecting original daily data instead of grouped
  • Misreading the index labels after resampling
4. What is wrong with this code snippet for upsampling daily data to hourly data?
df = pd.DataFrame({'value': [1, 2]}, index=pd.date_range('2023-01-01', periods=2, freq='D'))
upsampled = df.resample('H').mean()
medium
A. The frequency string 'H' is invalid for resampling
B. Upsampling without filling missing values results in NaNs
C. Using mean() is not allowed after resampling
D. The DataFrame index must be integers, not datetime

Solution

  1. Step 1: Identify the effect of upsampling daily to hourly

    Upsampling creates new rows for each hour, but original data has only daily points.
  2. Step 2: Recognize missing values after upsampling

    New hourly rows have no data, so mean() returns NaN unless filled.
  3. Final Answer:

    Upsampling without filling missing values results in NaNs -> Option B
  4. Quick Check:

    Upsampling needs fillna() to avoid NaNs [OK]
Hint: Upsampling creates gaps; fill missing values to avoid NaNs [OK]
Common Mistakes:
  • Thinking 'H' frequency is invalid
  • Believing mean() cannot be used after resampling
  • Ignoring datetime index requirement
5. You have minute-level temperature data in a DataFrame df with a datetime index. You want to create a new DataFrame with hourly average temperatures but only for hours where at least 45 minutes of data exist. Which approach correctly achieves this?
hard
A. df.resample('H').mean().dropna()
B. df.resample('H').mean()
C. df.resample('H').sum().where(lambda x: x >= 45).dropna()
D. df.resample('H').apply(lambda x: x.mean() if len(x) >= 45 else None).dropna()

Solution

  1. Step 1: Understand the requirement for minimum data points per hour

    We want hourly averages only if 45 or more minutes of data exist (i.e., at least 45 rows per hour).
  2. Step 2: Use a custom function with resample and apply

    Using apply with a lambda checks the length of each group and calculates mean only if condition met; else returns None.
  3. Step 3: Remove hours with insufficient data

    Calling dropna() removes hours where the condition failed (null values).
  4. Final Answer:

    df.resample('H').apply(lambda x: x.mean() if len(x) >= 45 else None).dropna() -> Option D
  5. Quick Check:

    Custom apply filters groups by size before averaging [OK]
Hint: Use apply with condition on group size, then dropna() [OK]
Common Mistakes:
  • Using mean() without checking group size
  • Using sum() instead of mean() for temperature
  • Dropping NaNs without filtering groups first
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard