Finding duplicates on specific columns helps you spot repeated information in just those parts of your data. This is useful to clean or analyze data more accurately.
Duplicates on specific columns in Pandas
DataFrame.duplicated(subset=[column_names], keep='first')subset lets you pick which columns to check for duplicates.
keep controls which duplicates to mark: 'first' keeps the first occurrence, 'last' keeps the last, and False marks all duplicates.
df.duplicated(subset=['email'])df.duplicated(subset=['date', 'location'], keep=False)
df.duplicated(subset=['product_id'], keep='last')
This code creates a small table of orders. It checks for repeated orders by the same customer for the same product. It adds a new column showing which rows are duplicates (True) and which are not (False).
import pandas as pd data = { 'order_id': [1, 2, 3, 4, 5, 6], 'customer': ['Alice', 'Bob', 'Alice', 'Bob', 'Alice', 'Charlie'], 'product': ['Book', 'Pen', 'Book', 'Pen', 'Notebook', 'Book'] } df = pd.DataFrame(data) # Find duplicates based on 'customer' and 'product' columns duplicates = df.duplicated(subset=['customer', 'product'], keep='first') # Show the original data with a new column marking duplicates df['is_duplicate'] = duplicates print(df)
Duplicates are checked row by row based on the selected columns only.
Setting keep=False marks all duplicates as True, including the first occurrence.
You can use the boolean result to filter or remove duplicates easily.
Use duplicated() with subset to find duplicates on specific columns.
The keep parameter controls which duplicates are marked.
This helps clean or analyze data where only some columns matter for duplication.
Practice
subset parameter do in the duplicated() method in pandas?Solution
Step 1: Understand the purpose of
Theduplicated()duplicated()method identifies duplicate rows in a DataFrame.Step 2: Role of
Thesubsetparametersubsetparameter limits the duplicate check to specific columns instead of all columns.Final Answer:
It specifies which columns to check for duplicates. -> Option AQuick Check:
subset= columns to check duplicates [OK]
- Thinking subset removes duplicates
- Confusing subset with sorting
- Assuming subset changes data types
df?Solution
Step 1: Recall pandas method for duplicates
The correct method isduplicated()to find duplicate rows.Step 2: Correct use of subset parameter
Thesubsetparameter takes a list of column names to check duplicates on.Final Answer:
df.duplicated(subset=['A', 'B']) -> Option AQuick Check:
Correct method and subset syntax [OK]
- Using non-existent methods like duplicates()
- Passing columns instead of subset
- Wrong method names like find_duplicates()
import pandas as pd
data = {'A': [1, 2, 1, 3], 'B': [4, 5, 4, 6], 'C': [7, 8, 9, 10]}
df = pd.DataFrame(data)
print(df.duplicated(subset=['A', 'B']))What is the output?
Solution
Step 1: Understand the DataFrame and subset
The DataFrame has rows with columns A and B: (1,4), (2,5), (1,4), (3,6).Step 2: Identify duplicates on columns 'A' and 'B'
The third row (index 2) duplicates the first row (index 0) on columns A and B.Final Answer:
[False, False, True, False] -> Option CQuick Check:
Only third row is duplicate on A and B [OK]
- Assuming duplicates on all columns
- Marking first occurrence as duplicate
- Confusing index positions
df.duplicated(subset=['A', 'B'], keep='last')
but get unexpected results. What is a common mistake causing this?
Solution
Step 1: Understand
keepparameter behaviorkeep='last'marks all duplicates except the last occurrence as True.Step 2: Identify common confusion
Many expect it to mark the last duplicate as True, but it actually keeps the last as False (not duplicate).Final Answer:
Using keep='last' marks the last occurrence as False, others as True. -> Option BQuick Check:
keep='last' keeps last duplicate False [OK]
- Thinking keep='last' marks last duplicate True
- Passing subset as string instead of list
- Believing duplicated() lacks keep parameter
df with columns 'Name', 'Age', 'City'. You want to remove rows where 'Name' and 'City' are duplicates but keep the first occurrence. Which code correctly does this?Solution
Step 1: Identify method to remove duplicates
Usedrop_duplicates()to remove duplicate rows.Step 2: Use subset and keep parameters correctly
Passsubset=['Name', 'City']andkeep='first'to keep first occurrence and remove others.Step 3: Check options
df = df.drop_duplicates(subset=['Name', 'City'], keep='first') uses correct method and parameters. df[~df.duplicated(subset=['Name', 'City'], keep='first')] usesduplicated()with negation but does not assign back to df. df = df.drop_duplicates(columns=['Name', 'City'], keep='last') uses wrong parameter name. df = df.duplicated(subset=['Name', 'City'], keep='first') returns boolean Series, not DataFrame.Final Answer:
df = df.drop_duplicates(subset=['Name', 'City'], keep='first') -> Option DQuick Check:
drop_duplicates with subset and keep='first' removes duplicates [OK]
- Using duplicated() instead of drop_duplicates() to remove rows
- Passing columns instead of subset
- Not assigning result back to df
Ready to prove it?
Pass the test and this pattern moves unknown
