Resampling time series data in Pandas - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to resample the DataFrame to daily frequency and calculate the mean.

Pandas

daily_mean = df.resample([1]).mean()

Drag options to blanks, or click blank then click option'

A'D'

B'W'

C'M'

D'H'

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'W' which resamples weekly instead of daily.

Using 'M' which resamples monthly instead of daily.

Using 'H' which resamples hourly instead of daily.

To resample time series data to daily frequency, use 'D' as the rule in the resample method.

2fill in blank

medium

Complete the code to resample the DataFrame to monthly frequency and calculate the sum.

Pandas

monthly_sum = df.resample([1]).sum()

Drag options to blanks, or click blank then click option'

A'D'

B'Y'

C'Q'

D'M'

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'D' which resamples daily instead of monthly.

Using 'Q' which resamples quarterly instead of monthly.

Using 'Y' which resamples yearly instead of monthly.

To resample data monthly, use 'M' as the rule in the resample method.

3fill in blank

hard

Fix the error in the code to resample the DataFrame to hourly frequency and calculate the mean.

Pandas

hourly_mean = df.resample([1]).mean()

Drag options to blanks, or click blank then click option'

A'h'

B'hour'

C'H'

D'hr'

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase 'h' which is not recognized.

Using full words like 'hour' or abbreviations like 'hr' which are invalid.

The correct frequency string for hourly resampling in pandas is 'H' (uppercase).

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps each word to its length only if the length is greater than 3.

Pandas

lengths = {word: [1] for word in words if [2]

Drag options to blanks, or click blank then click option'

Alen(word)

Blen(word) > 3

Cword

Dword > 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'word' instead of 'len(word)' for the value.

Using 'word > 3' which compares string to number and causes error.

The dictionary comprehension maps each word to its length using len(word), and filters words with length greater than 3 using len(word) > 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase keys to values only if the value is greater than 0.

Pandas

result = {{ [1]: [2] for k, v in data.items() if v [3] 0 }}

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dk.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using k.lower() instead of k.upper() for keys.

Using v < 0 or other operators that do not filter positive values.

Using k or v incorrectly in the comprehension.

The dictionary comprehension uses k.upper() as keys, v as values, and filters items where v > 0.

Practice

1. What does resampling a time series in pandas usually do?

easy

A. Sort the data by values in ascending order

B. Remove all missing values from the dataset

C. Change the time frequency of the data to summarize or expand it

D. Convert the data into a different file format

Solution

1. Step 1: Understand the purpose of resampling

   Resampling changes how often data points appear in time, either by grouping or expanding.

2. Step 2: Identify what resampling affects

   It changes the time frequency, not sorting or file formats.

3. Final Answer:

   Change the time frequency of the data to summarize or expand it -> Option C

4. Quick Check:

   Resampling = Change frequency [OK]

Hint: Resampling changes how often data points appear in time [OK]

Common Mistakes:

• Confusing resampling with sorting data
• Thinking resampling removes missing values automatically
• Believing resampling changes file formats

2. Which of the following is the correct syntax to downsample a pandas DataFrame df with a datetime index to monthly frequency and calculate the mean?

easy

A. df.resample('M').mean()

B. df.resample('M').sum()

C. df.resample('D').mean()

D. df.resample('M').fillna()

Solution

1. Step 1: Identify the correct resample frequency for monthly data

   'M' stands for month-end frequency in pandas resampling.

2. Step 2: Choose the correct aggregation function

   To calculate the mean after downsampling, use .mean().

3. Final Answer:

   df.resample('M').mean() -> Option A

4. Quick Check:

   Monthly mean = df.resample('M').mean() [OK]

Hint: Use 'M' for monthly and .mean() to aggregate [OK]

Common Mistakes:

• Using 'D' instead of 'M' for monthly frequency
• Using sum() when mean() is asked
• Calling fillna() without upsampling

3. Given the following code, what will be the output of print(resampled)?

import pandas as pd
idx = pd.date_range('2023-01-01', periods=4, freq='D')
data = [10, 20, 30, 40]
df = pd.DataFrame({'value': data}, index=idx)
resampled = df.resample('2D').sum()

medium

A. value
2023-01-01 30
2023-01-03 70

B. value
2023-01-01 10
2023-01-02 20
2023-01-03 30
2023-01-04 40

C. value
2023-01-01 15
2023-01-03 35

D. {'2023-01-01': 30, '2023-01-03': 70}

Solution

1. Step 1: Understand resampling with '2D' and sum aggregation

   Resampling with '2D' groups data every 2 days and sums values in each group.

2. Step 2: Calculate sums for each 2-day period

   First period: 2023-01-01 + 2023-01-02 = 10 + 20 = 30; Second period: 2023-01-03 + 2023-01-04 = 30 + 40 = 70.

3. Final Answer:

   value 2023-01-01 30 2023-01-03 70 -> Option A

4. Quick Check:

   Sum every 2 days = 30, 70 [OK]

Hint: Sum values in 2-day groups after resampling [OK]

Common Mistakes:

• Confusing sum with mean aggregation
• Expecting original daily data instead of grouped
• Misreading the index labels after resampling

4. What is wrong with this code snippet for upsampling daily data to hourly data?

df = pd.DataFrame({'value': [1, 2]}, index=pd.date_range('2023-01-01', periods=2, freq='D'))
upsampled = df.resample('H').mean()

medium

A. The frequency string 'H' is invalid for resampling

B. Upsampling without filling missing values results in NaNs

C. Using mean() is not allowed after resampling

D. The DataFrame index must be integers, not datetime

Solution

1. Step 1: Identify the effect of upsampling daily to hourly

   Upsampling creates new rows for each hour, but original data has only daily points.

2. Step 2: Recognize missing values after upsampling

   New hourly rows have no data, so mean() returns NaN unless filled.

3. Final Answer:

   Upsampling without filling missing values results in NaNs -> Option B

4. Quick Check:

   Upsampling needs fillna() to avoid NaNs [OK]

Hint: Upsampling creates gaps; fill missing values to avoid NaNs [OK]

Common Mistakes:

• Thinking 'H' frequency is invalid
• Believing mean() cannot be used after resampling
• Ignoring datetime index requirement

5. You have minute-level temperature data in a DataFrame df with a datetime index. You want to create a new DataFrame with hourly average temperatures but only for hours where at least 45 minutes of data exist. Which approach correctly achieves this?

hard

A. df.resample('H').mean().dropna()

B. df.resample('H').mean()

C. df.resample('H').sum().where(lambda x: x >= 45).dropna()

D. df.resample('H').apply(lambda x: x.mean() if len(x) >= 45 else None).dropna()

Solution

1. Step 1: Understand the requirement for minimum data points per hour

   We want hourly averages only if 45 or more minutes of data exist (i.e., at least 45 rows per hour).

2. Step 2: Use a custom function with resample and apply

   Using apply with a lambda checks the length of each group and calculates mean only if condition met; else returns None.

3. Step 3: Remove hours with insufficient data

   Calling dropna() removes hours where the condition failed (null values).

4. Final Answer:

   df.resample('H').apply(lambda x: x.mean() if len(x) >= 45 else None).dropna() -> Option D

5. Quick Check:

   Custom apply filters groups by size before averaging [OK]

Hint: Use apply with condition on group size, then dropna() [OK]

Common Mistakes:

• Using mean() without checking group size
• Using sum() instead of mean() for temperature
• Dropping NaNs without filtering groups first