These functions help you quickly find the biggest or smallest values in your data. They make it easy to see top or bottom results without sorting everything.
Finding the top 3 highest sales days in a store.
Getting the 5 smallest temperatures recorded in a week.
Selecting the top 10 students with highest scores in a test.
Finding the lowest 2 prices of products in a list.
Hint: Use nsmallest(n, column) with number first [OK]
Common Mistakes:
Swapping arguments order
Using nlargest instead of nsmallest
Passing column name before number
3. Given the DataFrame:
import pandas as pd
data = {'name': ['Anna', 'Bob', 'Cara', 'Dave'], 'age': [23, 45, 31, 22]}
df = pd.DataFrame(data)
What is the output of df.nlargest(2, 'age')?
medium
A. Rows for Dave and Bob with ages 22 and 45
B. Rows for Anna and Dave with ages 23 and 22
C. Rows for Bob and Cara with ages 45 and 31
D. Rows for Cara and Anna with ages 31 and 23
Solution
Step 1: Identify the ages in the DataFrame
The ages are Anna: 23, Bob: 45, Cara: 31, Dave: 22.
Step 2: Select the 2 largest ages
The two largest ages are 45 (Bob) and 31 (Cara).
Final Answer:
Rows for Bob and Cara with ages 45 and 31 -> Option C
Quick Check:
nlargest(2, 'age') = Bob, Cara [OK]
Hint: Pick top n values by column with nlargest() [OK]
Common Mistakes:
Choosing smallest instead of largest
Mixing up row order
Confusing names with ages
4. What is wrong with this code snippet?
df.nsmallest('score', 5)
Assuming df is a DataFrame with a column named 'score'.
medium
A. The arguments are in the wrong order
B. The method name should be nlargest
C. The number 5 should be a string
D. The column name should be an integer
Solution
Step 1: Check the method signature for nsmallest()
The correct order is nsmallest(n, columns), where n is an integer and columns is a string or list.
Step 2: Identify the error in the code
The code passes the column name first and then the number, which is reversed.
Final Answer:
The arguments are in the wrong order -> Option A
Quick Check:
nsmallest(n, column) needs number first [OK]
Hint: Number first, column second in nsmallest() [OK]
Common Mistakes:
Swapping argument order
Using wrong method name
Passing wrong data types
5. You have a DataFrame df with columns ['product', 'price', 'rating']. You want to find the top 3 products with the highest rating but lowest price among those top rated. Which pandas code snippet correctly achieves this?
hard
A. df.nlargest(3, 'rating').nsmallest(3, 'price')
B. df.nlargest(3, 'rating').sort_values('price').head(3)
C. df.nsmallest(3, 'price').nlargest(3, 'rating')
D. df.sort_values(['rating', 'price'], ascending=[False, True]).head(3)
Solution
Step 1: Understand the goal
We want top 3 products by highest rating, but among those, pick the ones with lowest price.
Step 2: Analyze each option
df.nlargest(3, 'rating').nsmallest(3, 'price') chains nlargest then nsmallest but nsmallest after nlargest may reduce rows incorrectly. df.nlargest(3, 'rating').sort_values('price').head(3) sorts price after selecting top rating but may not correctly filter lowest price among top rated. df.nsmallest(3, 'price').nlargest(3, 'rating') reverses the order, which is wrong. df.sort_values(['rating', 'price'], ascending=[False, True]).head(3) sorts by rating descending and price ascending, then picks top 3, which correctly prioritizes rating then price.
Final Answer:
df.sort_values(['rating', 'price'], ascending=[False, True]).head(3) -> Option D
Quick Check:
Sort by rating desc, price asc, then head(3) [OK]
Hint: Sort by rating desc, price asc, then take top 3 [OK]
Common Mistakes:
Chaining nlargest and nsmallest incorrectly
Not sorting by both columns properly
Selecting wrong rows due to order
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