We use NaN and None to show missing or empty data in tables. This helps us find and handle gaps in our data.
NaN and None in Pandas
import pandas as pd import numpy as np df = pd.DataFrame({ 'A': [1, 2, None], 'B': [4, np.nan, 6] })
None is a Python object representing 'no value'.
NaN (Not a Number) is a special floating-point value used by pandas and numpy to mark missing data.
import pandas as pd import numpy as np df = pd.DataFrame({ 'A': [1, None, 3], 'B': [np.nan, 5, 6] }) print(df)
df['A'].isna()df.fillna(0)This code creates a table with missing values using None and NaN. It then shows which values are missing and fills them with zero.
import pandas as pd import numpy as np data = { 'Name': ['Alice', 'Bob', 'Charlie', None], 'Age': [25, np.nan, 30, 22], 'Score': [85, 90, None, 88] } df = pd.DataFrame(data) print('Original DataFrame:') print(df) print('\nCheck missing values:') print(df.isna()) print('\nFill missing values with 0:') print(df.fillna(0))
None works well for object (text) columns, but pandas converts it to NaN in numeric columns.
NaN is a float type, so columns with NaN become float even if original data was integer.
Use isna() or isnull() to find missing values; they work the same.
NaN and None mark missing data in pandas tables.
Use isna() to find missing values and fillna() to replace them.
Handling missing data helps keep analysis accurate and clean.
Practice
NaN and None represent in a pandas DataFrame?Solution
Step 1: Understand the role of NaN and None in pandas
BothNaNandNoneare used to mark missing or null data in pandas DataFrames.Step 2: Differentiate from other DataFrame elements
They do not represent valid data, headers, or indexes but indicate absence of data.Final Answer:
Missing or null data values -> Option AQuick Check:
NaN and None = Missing data [OK]
- Thinking NaN is a valid number
- Confusing None with column names
- Assuming NaN is an index label
df?Solution
Step 1: Recall pandas functions for missing data
The correct function to check for missing values isisna(), which returns a boolean DataFrame indicating missing entries.Step 2: Identify incorrect options
notna()returns a boolean DataFrame indicating non-missing entries;isnan()andismissing()do not exist in pandas.Final Answer:
df.isna() -> Option AQuick Check:
Use isna() to find missing values [OK]
- Using non-existent df.isnan()
- Using df.notna() which checks non-missing values
- Trying df.ismissing() which is invalid
import pandas as pd
import numpy as np
df = pd.DataFrame({'A': [1, np.nan, 3], 'B': [None, 2, 3]})
result = df.isna().sum().to_dict()What is the value of
result?Solution
Step 1: Identify missing values in each column
Column 'A' has onenp.nan(missing), column 'B' has oneNone(missing).Step 2: Use isna() and sum() to count missing per column
df.isna()marks missing as True,sum()counts Trues per column, resulting in {'A': 1, 'B': 1}.Final Answer:
{'A': 1, 'B': 1} -> Option DQuick Check:
Count missing with isna().sum() = {'A':1,'B':1} [OK]
- Ignoring None as missing in column B
- Confusing sum() to count non-missing
- Assuming np.nan and None are treated differently here
import pandas as pd
df = pd.DataFrame({'X': [1, None, 3]})
df['X'] = df['X'].fillna(0)
print(df)What is the output?
Solution
Step 1: Identify missing value in column 'X'
The second row hasNone, which pandas treats as missing (NaN).Step 2: Use fillna(0) to replace missing with zero
Thefillna(0)replaces the missing value with 0, so the DataFrame becomes 1, 0, 3.Final Answer:
X 0 1 1 0 2 3 -> Option CQuick Check:
fillna(0) replaces None with 0 [OK]
- Expecting None to remain after fillna
- Confusing fillna with dropna
- Assuming fillna changes non-missing values
df with columns 'A' and 'B' containing some NaN and None values. You want to replace all missing values in 'A' with the mean of 'A' and all missing values in 'B' with the string 'missing'. Which code correctly does this?Solution
Step 1: Replace missing in 'A' with its mean
Usedf['A'].fillna(df['A'].mean())and assign back to 'A' to update the column.Step 2: Replace missing in 'B' with 'missing'
Usedf['B'].fillna('missing')and assign back to 'B' to update that column.Step 3: Check other options for correctness
df.fillna({'A': df['A'].mean(), 'B': 'missing'}) does not assign back, so changes are not saved; df['A'].fillna(df['A'].mean()) df['B'].fillna('missing') also misses assignment; df.fillna(df.mean()) df['B'] = df['B'].fillna('missing') tries to fill numeric mean for all columns which fails for 'B'.Final Answer:
df['A'] = df['A'].fillna(df['A'].mean()) df['B'] = df['B'].fillna('missing') -> Option BQuick Check:
Assign fillna results back to columns [OK]
- Not assigning fillna result back to DataFrame
- Using fillna without specifying columns
- Trying to fill numeric mean into string column
Ready to prove it?
Pass the test and this pattern moves unknown
