dt accessor for datetime properties in Pandas

Introduction

The dt accessor helps you easily get parts of dates and times from your data. It makes working with dates simple and clear.

You want to find the year or month from a list of dates.

You need to filter data by day of the week, like only Mondays.

You want to add a new column showing the hour from timestamps.

You need to check if dates fall on weekends.

You want to extract the day or week number from dates.

Syntax

Pandas

dataframe['date_column'].dt.property

date_column must be a datetime type for dt to work.

Common properties include year, month, day, hour, weekday, and more.

Examples

Gets the year from each date in the date column.

Pandas

df['date'].dt.year

Extracts the month number from each date.

Pandas

df['date'].dt.month

Returns the day of the week as a number (Monday=0, Sunday=6).

Pandas

df['date'].dt.weekday

Gets the hour from datetime values that include time.

Pandas

df['date'].dt.hour

Sample Program

This code creates a table with dates and extracts different parts like year, month, day, weekday number, and hour into new columns.

Pandas

import pandas as pd

data = {'date': ['2023-01-15 08:30:00', '2023-06-20 14:45:00', '2023-12-25 00:00:00']}
df = pd.DataFrame(data)
df['date'] = pd.to_datetime(df['date'])

# Extract year, month, day, weekday, and hour
df['year'] = df['date'].dt.year
df['month'] = df['date'].dt.month
df['day'] = df['date'].dt.day
df['weekday'] = df['date'].dt.weekday
df['hour'] = df['date'].dt.hour

print(df)

Important Notes

If your date column is not datetime type, use pd.to_datetime() to convert it first.

The weekday property counts Monday as 0 and Sunday as 6.

You can also use dt.day_name() to get the weekday name as text.

Summary

The dt accessor lets you get parts of dates easily.

Use it to extract year, month, day, hour, weekday, and more.

Make sure your data is in datetime format before using dt.

Practice

1.

What does the dt accessor in pandas allow you to do?

easy

A. Extract parts like year, month, and day from datetime columns

B. Convert strings to numbers

C. Sort data alphabetically

D. Create new columns with random values

Solution

1. Step 1: Understand the purpose of dt accessor

   The dt accessor is used with datetime columns to access their components like year, month, day, etc.

2. Step 2: Compare options with this purpose

   Only Extract parts like year, month, and day from datetime columns describes extracting parts of datetime, which matches the dt accessor's use.

3. Final Answer:

   Extract parts like year, month, and day from datetime columns -> Option A

4. Quick Check:

   dt accessor = extract datetime parts [OK]

Hint: Remember: dt means date-time parts extraction [OK]

Common Mistakes:

• Thinking dt converts strings to numbers
• Confusing dt with sorting functions
• Assuming dt creates random data

2.

Which of the following is the correct syntax to get the month from a pandas datetime column df['date']?

df['date']?.month

easy

A. df['date'].month()

B. df['date'].dt.month

C. df['date'].dt('month')

D. df['date'].month.dt

Solution

1. Step 1: Recall correct dt accessor syntax

   To access datetime parts, use .dt followed by the property without parentheses.

2. Step 2: Check each option

   df['date'].dt.month uses .dt.month correctly. df['date'].month() wrongly uses parentheses. df['date'].dt('month') uses wrong syntax. df['date'].month.dt reverses order.

3. Final Answer:

   df['date'].dt.month -> Option B

4. Quick Check:

   Use .dt.property syntax [OK]

Hint: Use .dt before datetime property without parentheses [OK]

Common Mistakes:

• Calling month as a function with ()
• Using dt as a function
• Reversing dt and property order

3.

Given the following code, what will be the output?

import pandas as pd

dates = pd.Series(pd.to_datetime(['2023-01-15', '2023-07-20', '2023-12-31']))
months = dates.dt.month
print(months.tolist())

medium

A. [15, 20, 31]

B. ['January', 'July', 'December']

C. [1, 7, 12]

D. [2023, 2023, 2023]

Solution

1. Step 1: Understand the code

   The code creates a Series of datetime objects for three dates, then extracts the month number using dt.month.

2. Step 2: Determine the month numbers

   January is month 1, July is 7, December is 12, so the list is [1, 7, 12].

3. Final Answer:

   [1, 7, 12] -> Option C

4. Quick Check:

   dt.month extracts month numbers [OK]

Hint: dt.month returns month numbers as integers [OK]

Common Mistakes:

• Confusing day with month
• Expecting month names instead of numbers
• Printing year instead of month

4.

What is wrong with this code snippet?

import pandas as pd

dates = pd.Series(['2023-01-15', '2023-07-20'])
print(dates.dt.day)

medium

A. The Series is not converted to datetime before using dt accessor

B. The dt accessor does not have a day property

C. The print statement syntax is incorrect

D. The dates list is empty

Solution

1. Step 1: Check the data type of the Series

   The Series contains strings, not datetime objects, so dt accessor cannot be used directly.

2. Step 2: Identify the error cause

   Without converting to datetime using pd.to_datetime(), accessing dt.day raises an error.

3. Final Answer:

   The Series is not converted to datetime before using dt accessor -> Option A

4. Quick Check:

   Convert to datetime before using dt [OK]

Hint: Always convert to datetime before using dt accessor [OK]

Common Mistakes:

• Assuming dt works on string Series
• Thinking dt.day does not exist
• Ignoring data type requirements

5.

You have a DataFrame df with a datetime column 'timestamp'. You want to create a new column 'is_weekend' that is True if the date is Saturday or Sunday, and False otherwise. Which code correctly does this?

df['is_weekend'] = df['timestamp'].dt.weekday > 4

hard

A. df['is_weekend'] = df['timestamp'].dt.weekday in [5, 6]

B. df['is_weekend'] = df['timestamp'].dt.day > 4

C. df['is_weekend'] = df['timestamp'].dt.weekday == 5 or 6

D. df['is_weekend'] = df['timestamp'].dt.weekday > 4

Solution

1. Step 1: Understand weekday numbering

   In pandas, dt.weekday returns 0 for Monday up to 6 for Sunday. Weekend days are 5 (Saturday) and 6 (Sunday).

2. Step 2: Check each option's logic

   df['is_weekend'] = df['timestamp'].dt.weekday > 4 uses > 4, which means days 5 and 6 are True. df['is_weekend'] = df['timestamp'].dt.day > 4 checks day of month, not weekday. df['is_weekend'] = df['timestamp'].dt.weekday == 5 or 6 uses incorrect syntax for or. df['is_weekend'] = df['timestamp'].dt.weekday in [5, 6] uses 'in' which is invalid for Series.

3. Final Answer:

   df['is_weekend'] = df['timestamp'].dt.weekday > 4 -> Option D

4. Quick Check:

   Weekend days have weekday > 4 [OK]

Hint: Weekend days have weekday numbers 5 or 6, so > 4 works [OK]

Common Mistakes:

• Using day instead of weekday
• Wrong boolean logic with or
• Using 'in' with pandas Series