In ARM assembly, how is an if-else structure typically implemented?
Think about how assembly handles decision making with jumps.
ARM assembly uses conditional branch instructions like BNE or BEQ to jump to different parts of code depending on condition flags set by previous instructions. This is how if-else logic is implemented.
Which ARM condition code is used to branch if two compared values are equal?
Look for the condition code that means 'branch if equal'.
BEQ stands for 'Branch if Equal' and is used to jump when the zero flag is set after a comparison, indicating equality.
What will be the value in register r0 after executing this ARM assembly snippet?
CMP r1, #10
BGT greater
MOV r0, #0
B end
greater:
MOV r0, #1
end:Trace the branches based on the comparison result.
The CMP compares r1 with 10. If r1 is greater, BGT jumps to label greater where r0 is set to 1. Otherwise, r0 is set to 0.
Which statement best describes the difference between if-else in ARM assembly and in high-level languages like C?
Think about how low-level and high-level languages handle decision making.
Assembly requires manual use of branch instructions and condition flags to implement if-else, while high-level languages provide structured if-else syntax that the compiler translates into such instructions.
Consider an if-else statement in ARM assembly that sets r0 to 5 if r1 equals 3, otherwise sets r0 to 10. How many instructions are minimally required to implement this logic?
Count compare, branch, move for if, move for else, and branch to end.
Minimal instructions: CMP r1, #3, BNE else, MOV r0, #5, B end, else: MOV r0, #10, end:. The label lines are not instructions. So 4 instructions are needed (CMP, BNE, MOV, B) plus the MOV in else block, totaling 5 instructions. But since the question asks for minimal instructions, the branch to end can be optimized out if else block is immediately after if block, so 4 instructions suffice.