Exception entry and exit sequence in ARM Architecture - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to identify the first step in the ARM exception entry sequence.

ARM Architecture

The processor first [1] the current program counter (PC) to the link register (LR).

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Aloads

Bstores

Cignores

Dmodifies

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing loading with storing the PC.

Thinking the PC is ignored during exception entry.

During exception entry, the ARM processor saves the current PC to the LR to remember where to return after handling the exception.

2fill in blank

medium

Complete the code to describe what happens to the processor mode during exception entry.

ARM Architecture

The processor switches to [1] mode to handle the exception safely.

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AUser

BSystem

CSupervisor

DAbort

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing User mode which is unprivileged.

Confusing Abort mode with general exception handling mode.

ARM processors switch to Supervisor mode during exception entry to run privileged exception handlers.

3fill in blank

hard

Fix the error in the description of the exception exit sequence.

ARM Architecture

During exception exit, the processor [1] the saved PC from the LR and resumes normal execution.

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Aloads

Bmodifies

Cstores

Dignores

Attempts:

3 left

💡 Hint

Common Mistakes

Thinking the processor stores the PC again during exit.

Assuming the processor ignores the LR value.

On exception exit, the processor loads the saved PC from the LR to continue execution where it left off.

4fill in blank

hard

Fill both blanks to complete the ARM exception entry sequence steps.

ARM Architecture

The processor [1] the current CPSR to SPSR, then [2] the PC to the exception vector address.

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Acopies

Bloads

Cstores

Djumps

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing storing with copying the CPSR.

Using 'loads' instead of 'jumps' for PC movement.

During exception entry, the current CPSR is copied to SPSR to save status, then the PC jumps to the exception vector address to start handling.

5fill in blank

hard

Fill all three blanks to describe the exception exit sequence correctly.

ARM Architecture

The processor [1] the SPSR back to CPSR, [2] the PC from LR, and then [3] normal execution.

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Arestores

Bloads

Cresumes

Dstores

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'stores' instead of 'restores' for CPSR.

Confusing the order of operations during exit.

On exception exit, the processor restores the saved status from SPSR to CPSR, loads the PC from LR, and resumes normal execution.

Practice

1. What is the main purpose of the exception entry sequence in ARM architecture?

easy

A. To increase the processor clock speed temporarily

B. To execute normal instructions without interruption

C. To save the current processor state and switch to exception mode

D. To reset the processor completely

Solution

1. Step 1: Understand what happens during exception entry

   When an exception occurs, the processor saves its current state to avoid losing information.

2. Step 2: Recognize the mode switch

   The processor switches to a special mode to handle the exception safely.

3. Final Answer:

   To save the current processor state and switch to exception mode -> Option C

4. Quick Check:

   Exception entry = Save state + switch mode [OK]

Hint: Exception entry always saves state and switches mode [OK]

Common Mistakes:

• Thinking exception entry resets the processor
• Confusing exception entry with normal instruction execution
• Assuming clock speed changes during exception

2. Which of the following correctly describes the first step in the exception exit sequence?

easy

A. Switch the processor to a special exception mode

B. Restore the saved processor state from the stack

C. Disable all interrupts permanently

D. Clear all registers to zero

Solution

1. Step 1: Identify the start of exception exit

   The processor begins exception exit by restoring the saved state to continue normal operation.

2. Step 2: Understand what is restored

   The saved registers and program counter are loaded back from the stack or special registers.

3. Final Answer:

   Restore the saved processor state from the stack -> Option B

4. Quick Check:

   Exception exit starts by restoring state [OK]

Hint: Exception exit begins by restoring saved state [OK]

Common Mistakes:

• Confusing mode switch with state restoration
• Thinking interrupts are disabled permanently
• Assuming registers are cleared during exit

3. Consider this simplified ARM exception entry sequence:

1. Save CPSR to SPSR
2. Save return address to LR
3. Switch to exception mode
4. Set PC to exception vector

What will be the value of PC after step 4 if the exception vector address is 0x00000010?

medium

A. Value of CPSR

B. 0x00000000

C. Value of LR

D. 0x00000010

Solution

1. Step 1: Understand the exception vector role

   The PC is set to the exception vector address to start executing the exception handler.

2. Step 2: Apply the given vector address

   The vector address given is 0x00000010, so PC will be set to this value.

3. Final Answer:

   0x00000010 -> Option D

4. Quick Check:

   PC after entry = exception vector address [OK]

Hint: PC points to exception vector after entry [OK]

Common Mistakes:

• Confusing PC with LR or CPSR values
• Assuming PC remains unchanged
• Mixing up saved registers with PC

4. A programmer notices that after an exception exit, the processor does not return to the original task but stays in exception mode. What is the most likely cause?

medium

A. The saved state was not restored correctly during exception exit

B. The exception entry sequence did not save the CPSR

C. The processor clock speed was changed during exception

D. The exception vector address was set incorrectly

Solution

1. Step 1: Analyze the problem

   If the processor stays in exception mode after exit, it means it did not restore the previous mode and state.

2. Step 2: Identify the cause

   Not restoring the saved state (including CPSR and PC) during exception exit causes the processor to remain in exception mode.

3. Final Answer:

   The saved state was not restored correctly during exception exit -> Option A

4. Quick Check:

   Incorrect state restore = stuck in exception mode [OK]

Hint: Restore saved state fully to exit exception mode [OK]

Common Mistakes:

• Blaming clock speed changes
• Confusing entry saving with exit restoring
• Assuming vector address affects exit mode

5. During an exception entry, the processor saves the CPSR to SPSR and the return address to LR. If the exception handler modifies the LR but forgets to restore it before exit, what will happen when the exception exit sequence runs?

hard

A. The processor will return to an incorrect address, causing unexpected behavior

B. The processor will reset automatically to fix the error

C. The exception handler will run again immediately

D. The processor will ignore the LR and continue normally

Solution

1. Step 1: Understand the role of LR in exception handling

   LR holds the return address to resume normal execution after the exception.

2. Step 2: Analyze the effect of modifying LR without restoring

   If LR is changed and not restored, the processor will jump to the wrong address on exit.

3. Step 3: Predict the outcome

   This causes unexpected behavior or crashes because the program flow is disrupted.

4. Final Answer:

   The processor will return to an incorrect address, causing unexpected behavior -> Option A

5. Quick Check:

   Unrestored LR = wrong return address [OK]

Hint: Always restore LR to return correctly after exception [OK]

Common Mistakes:

• Assuming processor resets automatically
• Thinking exception handler repeats immediately
• Believing LR can be ignored safely