Practice
1. What is the main characteristic of a
star schema in a data warehouse?easy
Solution
Step 1: Understand star schema structure
A star schema has a central fact table that stores measurable data.Step 2: Identify dimension tables role
Dimension tables surround the fact table and provide descriptive attributes.Final Answer:
One central fact table connected to multiple dimension tables -> Option AQuick Check:
Star schema = central fact + many dimensions [OK]
Hint: Fact table is the center, dimensions are spokes [OK]
Common Mistakes:
- Confusing fact and dimension tables
- Thinking star schema has multiple fact tables
- Assuming no relationships exist
2. Which SQL JOIN type is typically used to connect fact and dimension tables in a star schema?
easy
Solution
Step 1: Understand fact-dimension relationship
Fact tables usually have matching keys in dimension tables.Step 2: Choose JOIN type for matching rows
INNER JOIN returns only matching rows, ideal for star schema queries.Final Answer:
INNER JOIN -> Option AQuick Check:
Fact and dimension use INNER JOIN [OK]
Hint: Use INNER JOIN to link matching keys [OK]
Common Mistakes:
- Using CROSS JOIN which multiplies rows
- Using FULL OUTER JOIN causing unnecessary nulls
- Using LEFT JOIN when INNER JOIN suffices
3. Given a star schema with a fact table
Sales and dimension table Product, what does this SQL query return?SELECT p.ProductName, SUM(s.SalesAmount) AS TotalSales FROM Sales s JOIN Product p ON s.ProductID = p.ProductID GROUP BY p.ProductName;
medium
Solution
Step 1: Analyze JOIN and GROUP BY
The query joins Sales and Product on ProductID and groups results by product name.Step 2: Understand aggregation
SUM(s.SalesAmount) calculates total sales per product group.Final Answer:
Total sales amount for each product -> Option BQuick Check:
GROUP BY product sums sales per product [OK]
Hint: GROUP BY product sums sales per product [OK]
Common Mistakes:
- Ignoring GROUP BY causing total for all products
- Confusing JOIN keys
- Assuming query lists products without sales
4. Identify the error in this SQL query using a star schema:
SELECT d.CustomerName, SUM(f.SalesAmount) FROM FactSales f JOIN DimProduct d ON f.ProductID = d.ProductID GROUP BY d.CustomerName;
medium
Solution
Step 1: Check JOIN condition keys
FactSales.ProductID should join with DimProduct.ProductID, but SELECT and GROUP BY use CustomerName from a different dimension.Step 2: Identify mismatch in dimension usage
CustomerName likely belongs to DimCustomer, not DimProduct, so JOIN keys are incorrect.Final Answer:
JOIN condition uses wrong keys -> Option DQuick Check:
JOIN keys must match correct dimension [OK]
Hint: Match JOIN keys to correct dimension table [OK]
Common Mistakes:
- Grouping by column not selected
- Using alias inconsistently
- Missing aggregation alias
5. You want to design a star schema for sales data including customers, products, and time. Which approach best supports fast queries and easy analysis?
hard
Solution
Step 1: Understand star schema design principles
Star schema uses one fact table for measurable events and multiple dimension tables for descriptive data.Step 2: Evaluate options for query speed and simplicity
Create one fact table for sales and separate dimension tables for customers, products, and time matches star schema best, enabling fast joins and simple queries.Final Answer:
Create one fact table for sales and separate dimension tables for customers, products, and time -> Option CQuick Check:
Star schema = 1 fact + many dimensions [OK]
Hint: One fact table, many dimension tables for star schema [OK]
Common Mistakes:
- Using multiple fact tables unnecessarily
- Flattening all data into one table
- Choosing normalized schema over star schema for BI
