Why custom functions matter in Pandas - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a simple function that doubles a number.

Pandas

def double(x):
    return x [1] 2

result = double(5)
print(result)

Drag options to blanks, or click blank then click option'

A*

B+

C-

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' instead of '*' will add 2 instead of doubling.

The function multiplies the input by 2 to double it.

2fill in blank

medium

Complete the code to apply a custom function to a pandas DataFrame column.

Pandas

import pandas as pd

def add_five(n):
    return n + 5

df = pd.DataFrame({'num': [1, 2, 3]})
df['new_num'] = df['num'].[1](add_five)
print(df)

Drag options to blanks, or click blank then click option'

Aapplymap

Bapply

Cmap

Dtransform

Attempts:

3 left

💡 Hint

Common Mistakes

Using applymap which works on DataFrames, not Series.

The apply method applies a function to each element in the Series.

3fill in blank

hard

Fix the error in the custom function that should return the square of a number.

Pandas

def square(x):
    return x [1] x

print(square(4))

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A*

B+

C-

D//

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' will add the number to itself, not square it.

To get the square, multiply the number by itself using '*'.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if length is greater than 3.

Pandas

words = ['apple', 'bat', 'car', 'door']
lengths = {word: [1] for word in words if len(word) [2] 3}
print(lengths)

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Alen(word)

B<

C>

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' will select words with length less than 3.

The dictionary maps each word to its length if the length is greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their lengths if length is greater than 3.

Pandas

words = ['apple', 'bat', 'car', 'door']
result = { [1]: [2] for word in words if len(word) [3] 3 }
print(result)

Drag options to blanks, or click blank then click option'

Aword.upper()

Blen(word)

C>

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using word.lower() instead of uppercase.

The dictionary comprehension maps each word in uppercase to its length if the length is greater than 3.