rank() method and ranking methods in Pandas - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to rank the values in the 'score' column of the DataFrame.

Pandas

df['rank'] = df['score'].[1]()

Drag options to blanks, or click blank then click option'

Asort

Brank

Cindex

Dcount

Attempts:

3 left

💡 Hint

Common Mistakes

Using sort() instead of rank()

Using index() which does not rank values

The rank() method assigns ranks to values in a column.

2fill in blank

medium

Complete the code to rank the 'score' column with method 'min' to assign the minimum rank to ties.

Pandas

df['rank_min'] = df['score'].rank(method=[1])

Drag options to blanks, or click blank then click option'

A'first'

B'average'

C'max'

D'min'

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'average' which assigns average ranks to ties

Using 'max' which assigns maximum ranks to ties

The method='min' assigns the minimum rank to tied values.

3fill in blank

hard

Fix the error in the code to rank the 'score' column in descending order.

Pandas

df['rank_desc'] = df['score'].rank(ascending=[1])

Drag options to blanks, or click blank then click option'

AFalse

B'False'

CTrue

D'True'

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'False' as a string instead of boolean False

Using True which ranks ascending

To rank in descending order, set ascending=False as a boolean, not a string.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their ranks if their length is greater than 3.

Pandas

{word: df['score'].rank(method=[1])[i] for i, word in enumerate(words) if len(word) [2] 3}

Drag options to blanks, or click blank then click option'

A'average'

B>

C<

D'min'

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' in the condition

Using 'min' instead of 'average' for method

The method='average' assigns average ranks, and the condition len(word) > 3 filters words longer than 3 letters.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their ranks where rank is greater than 2.

Pandas

{word[1]: df['score'].rank(method=[2])[i] for i, word in enumerate(words) if df['score'].rank(method=[3])[i] > 2}

Drag options to blanks, or click blank then click option'

A.upper()

B'average'

C'min'

D'max'

Attempts:

3 left

💡 Hint

Common Mistakes

Not uppercasing the word

Using the same method for both blanks incorrectly

The first blank uses .upper() to uppercase words. The ranking methods are 'average' for the key and 'min' for the condition.

Practice

1. What does the rank() method in pandas do?

easy

A. Assigns ranks to values in a Series or DataFrame column based on their order

B. Sorts the data in ascending order permanently

C. Removes duplicate values from the data

D. Calculates the sum of all values in the data

Solution

1. Step 1: Understand the purpose of rank()

   The rank() method assigns a rank number to each value based on its position in sorted order.

2. Step 2: Differentiate from sorting and aggregation

   Unlike sorting or summing, rank() does not change order or calculate totals but gives position numbers.

3. Final Answer:

   Assigns ranks to values in a Series or DataFrame column based on their order -> Option A

4. Quick Check:

   rank() = Assign ranks [OK]

Hint: Remember: rank() gives position, not sorting or sums [OK]

Common Mistakes:

• Confusing rank() with sort()
• Thinking rank() removes duplicates
• Assuming rank() calculates sums

2. Which of the following is the correct syntax to rank a pandas Series s with method 'min'?

easy

A. s.rank(min='method')

B. s.rank(method='min')

C. rank(s, method='min')

D. s.rank(method=min)

Solution

1. Step 1: Recall the correct method call syntax

   In pandas, the rank method is called on the Series object with parameters inside parentheses and method as a string.

2. Step 2: Check each option for syntax errors

   s.rank(method='min') uses correct syntax: s.rank(method='min'). s.rank(min='method') wrongly uses parameter name. rank(s, method='min') uses wrong function call. s.rank(method=min) misses quotes around 'min'.

3. Final Answer:

   s.rank(method='min') -> Option B

4. Quick Check:

   Method name as string in rank() call [OK]

Hint: Use object.method(parameter='value') syntax [OK]

Common Mistakes:

• Omitting quotes around method name
• Using wrong parameter names
• Calling rank as a standalone function

3. Given the pandas Series s = pd.Series([3, 1, 4, 4, 2]), what is the output of s.rank(method='average')?

medium

A. [2.0, 1.0, 4.5, 4.5, 3.0]

B. [3.0, 1.0, 4.0, 5.0, 2.0]

C. [2.0, 1.0, 5.0, 5.0, 3.0]

D. [3.0, 1.0, 4.5, 4.5, 2.0]

Solution

1. Step 1: Sort values and assign ranks with 'average' method

   Sorted values: 1 (rank 1), 2 (rank 2), 3 (rank 3), 4 and 4 (ranks 4 and 5). For ties (4 and 4), average ranks = (4+5)/2 = 4.5.

2. Step 2: Map ranks back to original positions

   Original values: 3 -> rank 3, 1 -> rank 1, 4 -> rank 4.5, 4 -> rank 4.5, 2 -> rank 2. So ranks are [3,1,4.5,4.5,2].

3. Step 3: Check options carefully

   [2.0, 1.0, 4.5, 4.5, 3.0] matches ranks but with 3 replaced by 2.0. Re-examining, 3 is the third smallest value, so rank 3.0 is correct. [2.0, 1.0, 4.5, 4.5, 3.0] shows 2.0 for first value which is 3, so [2.0, 1.0, 4.5, 4.5, 3.0] is incorrect. [3.0, 1.0, 4.5, 4.5, 2.0] shows [3.0,1.0,4.5,4.5,2.0] which matches our calculation.

4. Final Answer:

   [3.0, 1.0, 4.5, 4.5, 2.0] -> Option D

5. Quick Check:

   Average method averages tie ranks correctly [OK]

Hint: Average method assigns mean rank to ties [OK]

Common Mistakes:

• Not averaging ranks for ties
• Assigning ranks in descending order by mistake
• Mixing up rank positions

4. You run df['rank'] = df['score'].rank(method='first') but get unexpected ranks. What is a likely cause?

medium

A. The 'method' parameter does not accept 'first'

B. You forgot to import pandas

C. The 'score' column contains duplicate values and 'first' ranks by order of appearance

D. You need to sort the DataFrame before ranking

Solution

1. Step 1: Understand 'first' method behavior

   The 'first' method assigns ranks in order of appearance for ties, so duplicates get ranks based on their position in the data.

2. Step 2: Identify why ranks seem unexpected

   If duplicates exist, ranks may not be sorted by value but by order, causing confusion if expecting sorted ranks.

3. Final Answer:

   The 'score' column contains duplicate values and 'first' ranks by order of appearance -> Option C

4. Quick Check:

   'first' ranks ties by appearance order [OK]

Hint: Check if duplicates affect 'first' method ranking [OK]

Common Mistakes:

• Assuming 'first' sorts before ranking
• Thinking 'first' is invalid method
• Forgetting duplicates affect rank order

5. You have a DataFrame df with a 'score' column. You want to rank scores in descending order, assign average ranks for ties, and get the rank as a percentage of total rows. Which code achieves this?

hard

A. df['rank'] = df['score'].rank(ascending=False, method='average', pct=True)

B. df['rank'] = df['score'].rank(ascending=True, method='average', pct=True)

C. df['rank'] = df['score'].rank(ascending=False, method='min', pct=False)

D. df['rank'] = df['score'].rank(method='average', pct=True)

Solution

1. Step 1: Set descending order and average method

   To rank highest scores first, set ascending=False. To assign average ranks for ties, use method='average'.

2. Step 2: Get rank as percentage

   Set pct=True to get ranks as percentage of total rows.

3. Step 3: Verify options

   df['rank'] = df['score'].rank(ascending=False, method='average', pct=True) matches all requirements. df['rank'] = df['score'].rank(ascending=True, method='average', pct=True) ranks ascending, wrong order. df['rank'] = df['score'].rank(ascending=False, method='min', pct=False) uses 'min' method and no percentage. df['rank'] = df['score'].rank(method='average', pct=True) misses descending order.

4. Final Answer:

   df['rank'] = df['score'].rank(ascending=False, method='average', pct=True) -> Option A

5. Quick Check:

   Descending + average + pct=True = df['rank'] = df['score'].rank(ascending=False, method='average', pct=True) [OK]

Hint: Use ascending=False and pct=True for descending percent ranks [OK]

Common Mistakes:

• Forgetting ascending=False for descending rank
• Using wrong method for ties
• Missing pct=True for percentage rank