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Keeping first vs last vs none in Pandas - Practice Questions

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Challenge - 5 Problems
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Duplicate Mastery
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❓ Predict Output
intermediate
2:00remaining
Output of drop_duplicates with keep='first'
What is the output DataFrame after running this code?
Pandas
import pandas as pd

df = pd.DataFrame({
    'A': [1, 2, 2, 3, 3, 3],
    'B': ['x', 'y', 'y', 'z', 'z', 'z']
})

result = df.drop_duplicates(subset=['A'], keep='first')
print(result)
A
   A  B
1  2  y
3  3  z
B
   A  B
2  2  y
4  3  z
C
   A  B
0  1  x
2  2  y
5  3  z
D
   A  B
0  1  x
1  2  y
3  3  z
Attempts:
2 left
💡 Hint
Keep='first' keeps the first occurrence of each duplicate group.
❓ Predict Output
intermediate
2:00remaining
Output of drop_duplicates with keep='last'
What is the output DataFrame after running this code?
Pandas
import pandas as pd

df = pd.DataFrame({
    'A': [1, 2, 2, 3, 3, 3],
    'B': ['x', 'y', 'y', 'z', 'z', 'z']
})

result = df.drop_duplicates(subset=['A'], keep='last')
print(result)
A
   A  B
0  1  x
1  2  y
3  3  z
B
   A  B
1  2  y
4  3  z
C
   A  B
0  1  x
2  2  y
5  3  z
D
   A  B
2  2  y
4  3  z
Attempts:
2 left
💡 Hint
Keep='last' keeps the last occurrence of each duplicate group.
❓ Predict Output
advanced
2:00remaining
Output of drop_duplicates with keep=False
What is the output DataFrame after running this code?
Pandas
import pandas as pd

df = pd.DataFrame({
    'A': [1, 2, 2, 3, 3, 3],
    'B': ['x', 'y', 'y', 'z', 'z', 'z']
})

result = df.drop_duplicates(subset=['A'], keep=False)
print(result)
A
   A  B
1  2  y
3  3  z
B
   A  B
0  1  x
CEmpty DataFrame\nColumns: [A, B]\nIndex: []
D
   A  B
0  1  x
1  2  y
3  3  z
Attempts:
2 left
💡 Hint
Keep=False drops all duplicates, keeping only unique rows.
🔧 Debug
advanced
2:00remaining
Identify the error in drop_duplicates usage
What error does this code raise when executed?
Pandas
import pandas as pd

df = pd.DataFrame({
    'A': [1, 2, 2],
    'B': ['x', 'y', 'y']
})

result = df.drop_duplicates(subset=['A'], keep='middle')
print(result)
AValueError: keep must be either 'first', 'last', or False
BTypeError: unhashable type: 'list'
CKeyError: 'middle'
DNo error, outputs DataFrame with all rows
Attempts:
2 left
💡 Hint
Check the allowed values for the keep parameter.
🚀 Application
expert
3:00remaining
Count unique rows after drop_duplicates with different keep values
Given this DataFrame, how many rows remain after applying drop_duplicates on column 'A' with keep='first', keep='last', and keep=False respectively?
Pandas
import pandas as pd

df = pd.DataFrame({
    'A': [1, 2, 2, 3, 3, 3, 4],
    'B': ['x', 'y', 'y', 'z', 'z', 'z', 'w']
})

count_first = len(df.drop_duplicates(subset=['A'], keep='first'))
count_last = len(df.drop_duplicates(subset=['A'], keep='last'))
count_none = len(df.drop_duplicates(subset=['A'], keep=False))

print(count_first, count_last, count_none)
A4 4 2
B4 4 1
C5 5 3
D5 5 2
Attempts:
2 left
💡 Hint
Count unique values and consider which rows are kept or removed.

Practice

(1/5)
1.

In pandas, what does keep='first' do when removing duplicates?

easy
A. Keeps the first occurrence of each duplicate and removes the rest
B. Keeps the last occurrence of each duplicate and removes the rest
C. Removes all duplicates, keeping only unique rows
D. Keeps all duplicates without removing any

Solution

  1. Step 1: Understand the meaning of keep='first'

    This option keeps the first row of each set of duplicates and removes the later ones.
  2. Step 2: Compare with other options

    Unlike keep='last' which keeps the last occurrence, keep='first' keeps the earliest one.
  3. Final Answer:

    Keeps the first occurrence of each duplicate and removes the rest -> Option A
  4. Quick Check:

    keep='first' = Keep first duplicate [OK]
Hint: Remember: 'first' keeps earliest duplicate row [OK]
Common Mistakes:
  • Confusing keep='first' with keep='last'
  • Thinking keep='first' removes all duplicates
  • Assuming keep='first' keeps all duplicates
2.

Which of the following is the correct syntax to remove duplicates in a pandas DataFrame df keeping only the last occurrence?

df._____('column_name', keep='last')
easy
A. drop_dupes
B. remove_duplicates
C. drop_duplicates
D. delete_duplicates

Solution

  1. Step 1: Identify the pandas method for removing duplicates

    The correct method is drop_duplicates to remove duplicate rows.
  2. Step 2: Confirm syntax for keeping last occurrence

    Using keep='last' inside drop_duplicates keeps the last duplicate row.
  3. Final Answer:

    drop_duplicates -> Option C
  4. Quick Check:

    Method to remove duplicates = drop_duplicates [OK]
Hint: Use df.drop_duplicates() to remove duplicates [OK]
Common Mistakes:
  • Using non-existent methods like remove_duplicates
  • Confusing method names with similar words
  • Forgetting to specify keep='last'
3.

What will be the output of the following code?

import pandas as pd

data = {'A': [1, 2, 2, 3, 3, 3], 'B': ['x', 'y', 'y', 'z', 'z', 'z']}
df = pd.DataFrame(data)
result = df.drop_duplicates(keep=False)
print(result)
medium
A. Rows with unique values only, no duplicates
B. All rows except the first occurrence of duplicates
C. Rows with A=1 B='x', A=2 B='y', A=3 B='z' only
D. Empty DataFrame

Solution

  1. Step 1: Understand keep=False behavior

    Using keep=False removes all duplicates, keeping only rows that appear once.
  2. Step 2: Identify unique rows in the DataFrame

    In the data, only the row with A=1 and B='x' is unique; others appear multiple times.
  3. Final Answer:

    Rows with unique values only, no duplicates -> Option A
  4. Quick Check:

    keep=False = Keep only unique rows [OK]
Hint: keep=False drops all duplicates, keeps only unique rows [OK]
Common Mistakes:
  • Thinking keep=False keeps first or last duplicates
  • Expecting some duplicates to remain
  • Confusing output with keep='first' or keep='last'
4.

Consider this code snippet:

import pandas as pd

data = {'col': [1, 1, 2, 2, 3]}
df = pd.DataFrame(data)
result = df.drop_duplicates(keep='middle')
print(result)

What is the error in this code?

medium
A. DataFrame missing required columns
B. Invalid value for the 'keep' parameter
C. Syntax error in DataFrame creation
D. No error, code runs fine

Solution

  1. Step 1: Check the 'keep' parameter values

    The valid values for 'keep' are 'first', 'last', or False. 'middle' is invalid.
  2. Step 2: Identify the error raised by invalid 'keep'

    Using 'middle' causes a ValueError because pandas does not recognize it.
  3. Final Answer:

    Invalid value for the 'keep' parameter -> Option B
  4. Quick Check:

    keep must be 'first', 'last', or False [OK]
Hint: Use only 'first', 'last', or False for keep parameter [OK]
Common Mistakes:
  • Using unsupported strings for keep
  • Assuming 'middle' is valid
  • Ignoring error messages
5.

You have a DataFrame df with duplicate rows based on column 'ID'. You want to remove all duplicates completely, so only rows with unique 'ID' remain. Which code snippet achieves this?

1) df.drop_duplicates(subset=['ID'], keep='first')
2) df.drop_duplicates(subset=['ID'], keep='last')
3) df.drop_duplicates(subset=['ID'], keep=False)
4) df.drop_duplicates()
hard
A. Option 1
B. Option 4
C. Option 2
D. Option 3

Solution

  1. Step 1: Understand the goal

    The goal is to remove all duplicates so only unique 'ID' rows remain.
  2. Step 2: Analyze each option

    Options 1 and 2 keep one duplicate (first or last). Option 4 removes duplicates but keeps first by default. Only option 3 with keep=False removes all duplicates completely.
  3. Final Answer:

    Option 3 -> Option D
  4. Quick Check:

    keep=False removes all duplicates [OK]
Hint: Use keep=False to remove all duplicates fully [OK]
Common Mistakes:
  • Using keep='first' or 'last' when full removal needed
  • Not specifying subset for duplicate check
  • Assuming default drop_duplicates removes all duplicates
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