Why Queue Exists and What Problems It Solves in DSA Python - Test Your Knowledge

Practice - 5 Tasks

1fill in blank

easy

Complete the code to add an element to the end of the queue.

DSA Python

queue = []
queue.[1](5)
print(queue)

Drag options to blanks, or click blank then click option'

Ainsert

Bpop

Cappend

Dremove

Attempts:

3 left

💡 Hint

Common Mistakes

Using pop removes an element instead of adding.

Using insert adds at a specific position, not the end.

We use append to add an element at the end of the list, which acts as the queue's rear.

2fill in blank

medium

Complete the code to remove the first element from the queue.

DSA Python

queue = [1, 2, 3]
removed = queue.[1](0)
print(queue, removed)

Drag options to blanks, or click blank then click option'

Apop

Bremove

Cappend

Dinsert

Attempts:

3 left

💡 Hint

Common Mistakes

Using remove deletes by value, not by position.

Using append adds instead of removing.

Using pop(0) removes and returns the first element, simulating dequeue operation.

3fill in blank

hard

Fix the error in the code to correctly simulate a queue's dequeue operation.

DSA Python

queue = [10, 20, 30]
item = queue.[1]
print(queue, item)

Drag options to blanks, or click blank then click option'

Aremove

Bpop

Cappend

Dpop(0)

Attempts:

3 left

💡 Hint

Common Mistakes

Using pop() removes last instead of first.

Using remove needs a value, not index.

To remove the first element, pop(0) must be used. pop() removes the last element.

4fill in blank

hard

Fill both blanks to create a queue using list and perform enqueue and dequeue.

DSA Python

queue = []
queue.[1](1)
removed = queue.[2](0)
print(queue, removed)

Drag options to blanks, or click blank then click option'

Aappend

Bpop

Cpop(0)

Dinsert

Attempts:

3 left

💡 Hint

Common Mistakes

Using pop() removes last element, not first.

Using insert adds at front, not end.

Use append to add at the end and pop(0) to remove from the front, following queue rules.

5fill in blank

hard

Fill both blanks to create a dictionary comprehension that counts letters in a word if count is greater than 1.

DSA Python

word = 'queue'
result = {letter: word.{BLANK_2}}(letter) for letter in set(word) if word.{{BLANK_2}}(letter) > 1
print(result)

Drag options to blanks, or click blank then click option'

A{

Bcount

D[

Attempts:

3 left

💡 Hint

Common Mistakes

Using list brackets instead of curly braces.

Using wrong method to count letters.

The dictionary comprehension starts with {, uses count method to count letters, and filters counts greater than 1.