Recall & Review
beginner
What is the main goal of the Trapping Rain Water Problem?
To find how much water can be trapped between bars of different heights after raining.
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beginner
What does the 'left max' array represent in the Trapping Rain Water Problem?
It stores the highest bar height from the left up to each position, helping to calculate trapped water.
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intermediate
Why do we use two pointers in the optimized solution of the Trapping Rain Water Problem?
To scan from both ends towards the center, reducing space usage and improving efficiency.
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intermediate
Explain how trapped water at a position is calculated.
Trapped water = minimum of max heights on left and right minus the height at that position, if positive.
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intermediate
What is the time and space complexity of the two-pointer approach for this problem?
Time complexity is O(n) and space complexity is O(1), where n is the number of bars.
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What does the Trapping Rain Water Problem calculate?
✗ Incorrect
The problem calculates how much water can be trapped between bars after raining.
Which data structure is commonly used to store max heights from left or right?
✗ Incorrect
Arrays are used to store max heights from left and right for each position.
In the two-pointer approach, what determines which pointer to move?
✗ Incorrect
The pointer with smaller max height moves inward to find trapped water.
What is the space complexity of the naive approach using left and right max arrays?
✗ Incorrect
The naive approach uses two extra arrays of size n, so space complexity is O(n).
Which of these is NOT a step in calculating trapped water at a position?
✗ Incorrect
We subtract the height at the position, not add it, to find trapped water.
Describe the two-pointer approach to solve the Trapping Rain Water Problem.
Think about scanning from both ends and comparing heights.
You got /5 concepts.
Explain how to calculate trapped water at a single position using max heights.
Water level depends on the shorter boundary around the bar.
You got /5 concepts.