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DSA Pythonprogramming~20 mins

Stack Using Linked List vs Array Stack Trade-offs in DSA Python - Compare & Choose

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Challenge - 5 Problems
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🧠 Conceptual
intermediate
2:00remaining
Memory Usage Comparison
Which statement correctly describes the memory usage difference between a stack implemented using a linked list and one using an array?
ALinked list stack uses extra memory for pointers, while array stack uses contiguous memory without extra pointers.
BArray stack uses extra memory for pointers, while linked list stack uses contiguous memory without extra pointers.
CBoth linked list and array stacks use the same amount of memory per element.
DLinked list stack uses less memory overall because it stores only data without pointers.
Attempts:
2 left
💡 Hint
Think about how linked lists store each element compared to arrays.
❓ Predict Output
intermediate
2:00remaining
Stack Overflow Behavior
What will be the output of the following Python code simulating a stack push operation on an array stack with fixed size 3?
DSA Python
class ArrayStack:
    def __init__(self):
        self.stack = [None]*3
        self.top = -1
    def push(self, val):
        if self.top == 2:
            print('Stack Overflow')
        else:
            self.top += 1
            self.stack[self.top] = val
            print(f'Pushed {val}')

s = ArrayStack()
s.push(10)
s.push(20)
s.push(30)
s.push(40)
A
Stack Overflow
Stack Overflow
Stack Overflow
Stack Overflow
B
Pushed 10
Pushed 20
Stack Overflow
Pushed 30
C
Pushed 10
Pushed 20
Pushed 30
Stack Overflow
D
Pushed 10
Pushed 20
Pushed 30
Pushed 40
Attempts:
2 left
💡 Hint
Check the condition that triggers overflow before pushing.
❓ Predict Output
advanced
2:00remaining
Linked List Stack Push and Pop
What is the printed output after executing this linked list stack code?
DSA Python
class Node:
    def __init__(self, val):
        self.val = val
        self.next = None

class LinkedListStack:
    def __init__(self):
        self.top = None
    def push(self, val):
        new_node = Node(val)
        new_node.next = self.top
        self.top = new_node
    def pop(self):
        if self.top is None:
            print('Stack Underflow')
            return
        print(f'Popped {self.top.val}')
        self.top = self.top.next

s = LinkedListStack()
s.push(5)
s.push(10)
s.pop()
s.pop()
s.pop()
A
Popped 10
Stack Underflow
Popped 5
B
Popped 10
Popped 5
Stack Underflow
C
Stack Underflow
Popped 10
Popped 5
D
Popped 5
Popped 10
Stack Underflow
Attempts:
2 left
💡 Hint
Remember that push adds to the top and pop removes from the top.
🧠 Conceptual
advanced
2:00remaining
Time Complexity Trade-offs
Which statement correctly compares the time complexity of push and pop operations in array stack vs linked list stack implementations?
ABoth array and linked list stacks have O(1) time complexity for push and pop in average cases.
BLinked list stack pop is O(n), array stack pop is O(1).
CArray stack push is O(n) due to resizing, linked list stack push is always O(1).
DArray stack push and pop are O(1), linked list stack push and pop are O(n).
Attempts:
2 left
💡 Hint
Consider typical implementations without resizing costs.
🚀 Application
expert
2:00remaining
Choosing Stack Implementation for Unknown Size
You need to implement a stack where the maximum number of elements is unknown and can grow very large. Which implementation is best and why?
ALinked list stack, because it uses less memory per element than array stack.
BArray stack with fixed size, because it uses less memory and is faster.
CArray stack with large fixed size, to avoid resizing during push operations.
DLinked list stack, because it can grow dynamically without resizing overhead.
Attempts:
2 left
💡 Hint
Think about memory allocation and resizing when size is unknown.