Sliding Window on Arrays in DSA Python - Time & Space Complexity
We want to understand how the time taken by a sliding window approach changes as the input array grows.
Specifically, how many steps does it take to process all windows in the array?
Analyze the time complexity of the following code snippet.
def max_sum_subarray(arr, k):
max_sum = 0
window_sum = 0
for i in range(k):
window_sum += arr[i]
max_sum = window_sum
for i in range(k, len(arr)):
window_sum += arr[i] - arr[i - k]
max_sum = max(max_sum, window_sum)
return max_sum
This code finds the maximum sum of any subarray of size k using a sliding window.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Two loops that traverse parts of the array.
- How many times: First loop runs k times, second loop runs (n - k) times, where n is array length.
As the array size grows, the total steps grow roughly in a straight line with n.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | About 10 steps |
| 100 | About 100 steps |
| 1000 | About 1000 steps |
Pattern observation: The number of operations increases directly with input size.
Time Complexity: O(n)
This means the time to complete grows linearly as the array gets bigger.
[X] Wrong: "Sliding window always takes O(k) time because the window size is k."
[OK] Correct: The window moves across the entire array, so the total work depends on n, not just k.
Understanding sliding window time complexity helps you explain efficient solutions clearly and confidently.
"What if we used nested loops instead of sliding window? How would the time complexity change?"