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DSA Pythonprogramming~10 mins

Search for a Value in Linked List in DSA Python - Execution Trace

Choose your learning style9 modes available
Concept Flow - Search for a Value in Linked List
Start at head node
Check if current node is None?
YesValue not found, stop
No
Compare current node value with target
Value found, stop
Back to check None
Start from the head node, check each node's value. If it matches the target, stop. If not, move to the next node until the end.
Execution Sample
DSA Python
class Node:
    def __init__(self, val):
        self.val = val
        self.next = None

def search(head, target):
    current = head
    while current:
        if current.val == target:
            return True
        current = current.next
    return False
This code searches for a target value in a linked list by checking each node from head to end.
Execution Table
StepOperationCurrent Node ValueComparison with TargetPointer ChangesVisual State
1Start at head33 == 5? Nocurrent -> Node(3)3 -> 7 -> 10 -> 5 -> None
2Move to next node77 == 5? Nocurrent -> Node(7)3 -> 7 -> 10 -> 5 -> None
3Move to next node1010 == 5? Nocurrent -> Node(10)3 -> 7 -> 10 -> 5 -> None
4Move to next node55 == 5? Yescurrent -> Node(5)3 -> 7 -> 10 -> 5 -> None
5Value found5Stop searchcurrent stays3 -> 7 -> 10 -> 5 -> None
💡 Value found at step 4, search stops.
Variable Tracker
VariableStartAfter Step 1After Step 2After Step 3After Step 4Final
currentNode(3)Node(3)Node(7)Node(10)Node(5)Node(5)
target555555
Key Moments - 3 Insights
Why do we check if current is None before comparing values?
Because if current is None, it means we've reached the end of the list and there are no more nodes to check. This is shown in execution_table step 1 where the loop condition is evaluated before comparison.
What happens if the target value is not in the list?
The loop moves through all nodes until current becomes None, then returns False. This is implied by the exit condition in the concept flow and would be shown if the target was not found.
Why do we move current to current.next after each comparison?
To check the next node in the list. Without moving current, the loop would check the same node repeatedly, causing an infinite loop. This is shown in execution_table steps 2 and 3.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution table, what is the value of current at step 3?
ANode with value 5
BNode with value 7
CNode with value 10
DNone
💡 Hint
Check the 'Current Node Value' column at step 3 in the execution_table.
At which step does the search stop because the value is found?
AStep 2
BStep 4
CStep 5
DStep 3
💡 Hint
Look for the row where 'Comparison with Target' is '5 == 5? Yes'.
If the target was 8 instead of 5, what would happen in the execution table?
ASearch would continue until current becomes None and then stop
BSearch would stop at step 4
CSearch would find value at step 3
DSearch would stop immediately at step 1
💡 Hint
Refer to the concept_flow and key_moments about what happens when value is not found.
Concept Snapshot
Search for a value in a linked list:
- Start at head node
- Check if current node is None (end)
- Compare current node's value with target
- If match, stop and return True
- Else move to next node
- If end reached without match, return False
Full Transcript
This visual trace shows how to search for a value in a linked list. We start at the head node and check if it is None to avoid errors. Then we compare the current node's value with the target. If they match, we stop and return True. If not, we move to the next node and repeat. If we reach the end of the list (current is None) without finding the target, we return False. The execution table tracks each step, showing the current node's value, comparisons, pointer moves, and the linked list's visual state. The variable tracker shows how the current pointer moves through the list. Key moments clarify why we check for None first, what happens if the value is not found, and why we move to the next node each time. The quiz tests understanding of these steps and outcomes.