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DSA Pythonprogramming~10 mins

Peek Front Element of Queue in DSA Python - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to peek the front element of the queue using list indexing.

DSA Python
queue = [10, 20, 30, 40]
front = queue[1]
print(front)
Drag options to blanks, or click blank then click option'
A[0]
B[-1]
C[1]
D[:1]
Attempts:
3 left
💡 Hint
Common Mistakes
Using negative index which gives the last element instead of the front.
Using slice notation which returns a list, not a single element.
2fill in blank
medium

Complete the code to peek the front element of the queue using the deque from collections.

DSA Python
from collections import deque
queue = deque([5, 15, 25])
front = queue[1]
print(front)
Drag options to blanks, or click blank then click option'
Apeek()
Bpopleft()
Cpop()
D[0]
Attempts:
3 left
💡 Hint
Common Mistakes
Using popleft() which removes the element instead of peeking.
Using pop() which removes the last element.
3fill in blank
hard

Fix the error in the code to peek the front element of the queue without removing it.

DSA Python
queue = [100, 200, 300]
front = queue.[1]()
print(front)
Drag options to blanks, or click blank then click option'
Apop
Bfront
Cpeek
Dpopleft
Attempts:
3 left
💡 Hint
Common Mistakes
Using pop() removes the element, not just peeks.
Using popleft() is not valid for lists.
4fill in blank
hard

Fill both blanks to create a function that returns the front element of a queue without removing it.

DSA Python
def peek_queue(queue):
    if len(queue) [1] 0:
        return queue[2]
    return None
Drag options to blanks, or click blank then click option'
A>
B==
C[0]
D[-1]
Attempts:
3 left
💡 Hint
Common Mistakes
Using '==' instead of '>' causes the function to fail for non-empty queues.
Using index -1 returns the last element, not the front.
5fill in blank
hard

Fill all three blanks to create a dictionary comprehension that maps each queue's name to its front element if not empty.

DSA Python
queues = {'q1': [1, 2], 'q2': [], 'q3': [3, 4]}
fronts = {name: queue[1] for name, queue in queues.items() if len(queue) [2] 0 and queue[3]
Drag options to blanks, or click blank then click option'
A[0]
B>
C!= []
D== []
Attempts:
3 left
💡 Hint
Common Mistakes
Using '==' instead of '!=' causes empty queues to be included incorrectly.
Using index -1 returns the last element, not the front.