Node Structure and Pointer Design in DSA Python - Build from Scratch

Node Structure and Pointer Design

📖 Scenario: Imagine you are building a simple linked list to keep track of tasks in a to-do list app. Each task is a node that stores the task name and a pointer to the next task.

🎯 Goal: You will create a basic Node class with a pointer to the next node, then link two nodes together, and finally print the linked tasks.

📋 What You'll Learn

Create a Node class with task and next attributes

Create two nodes with exact task names: 'Buy groceries' and 'Clean room'

Link the first node's next pointer to the second node

Print the tasks in order by following the next pointers

💡 Why This Matters

🌍 Real World

Linked lists are used in many apps to manage ordered data where items can be added or removed easily, like task lists, music playlists, or navigation paths.

💼 Career

Understanding node structures and pointers is fundamental for software developers working with data structures, memory management, and building efficient algorithms.

1

Create the Node class

Define a class called Node with an __init__ method that takes self and task as parameters. Inside __init__, set self.task to task and self.next to None.

DSA Python

# Define the Node class with __init__ method
# Your code here

Hint

Think of self.task as the content of the node and self.next as the pointer to the next node, which starts as None.

2

Create two nodes with tasks

Create two variables called node1 and node2. Assign node1 to a new Node with the task 'Buy groceries'. Assign node2 to a new Node with the task 'Clean room'.

DSA Python

class Node:
    def __init__(self, task):
        self.task = task
        self.next = None

# Create node1 and node2 with given tasks
# Your code here

Hint

Use the Node class to create each node with the exact task names.

3

Link the first node to the second node

Set the next attribute of node1 to point to node2.

DSA Python

class Node:
    def __init__(self, task):
        self.task = task
        self.next = None

node1 = Node('Buy groceries')
node2 = Node('Clean room')

# Link node1 to node2
# Your code here

Hint

Think of node1.next as the pointer that should now point to node2.

4

Print the tasks in order

Use a variable current set to node1. Use a while loop that runs while current is not None. Inside the loop, print current.task, then set current to current.next.

DSA Python

class Node:
    def __init__(self, task):
        self.task = task
        self.next = None

node1 = Node('Buy groceries')
node2 = Node('Clean room')

node1.next = node2

# Print tasks by following next pointers
# Your code here

Hint

Use a loop to move from one node to the next until you reach the end (None).