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DSA Pythonprogramming~10 mins

Merge Overlapping Intervals in DSA Python - Execution Trace

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Concept Flow - Merge Overlapping Intervals
Sort intervals by start
Initialize merged list empty
For each interval
If merged empty or no overlap
Add interval
Continue loop
Return merged
Sort intervals, then go through each. Add if no overlap, else merge with last. Return merged list.
Execution Sample
DSA Python
intervals = [[1,3],[2,6],[8,10],[15,18]]
intervals.sort(key=lambda x: x[0])
merged = []
for interval in intervals:
    if not merged or merged[-1][1] < interval[0]:
        merged.append(interval)
    else:
        merged[-1][1] = max(merged[-1][1], interval[1])
print(merged)
Merges overlapping intervals from a list and prints the merged intervals.
Execution Table
StepOperationCurrent IntervalMerged List BeforeActionMerged List AfterVisual State
1Sort intervals[1,3],[2,6],[8,10],[15,18][]Sort by start[][1,3] -> [2,6] -> [8,10] -> [15,18] -> null
2Check merged empty[1,3][]merged empty, append[[1,3]][1,3] -> null
3Check overlap[2,6][[1,3]]2 <= 3 overlap, merge[[1,6]][1,6] -> null
4Check overlap[8,10][[1,6]]8 > 6 no overlap, append[[1,6],[8,10]][1,6] -> [8,10] -> null
5Check overlap[15,18][[1,6],[8,10]]15 > 10 no overlap, append[[1,6],[8,10],[15,18]][1,6] -> [8,10] -> [15,18] -> null
6End loopN/A[[1,6],[8,10],[15,18]]Return merged[[1,6],[8,10],[15,18]][1,6] -> [8,10] -> [15,18] -> null
💡 All intervals processed, merged list returned
Variable Tracker
VariableStartAfter Step 2After Step 3After Step 4After Step 5Final
intervals[[1,3],[2,6],[8,10],[15,18]][[1,3],[2,6],[8,10],[15,18]][[1,3],[2,6],[8,10],[15,18]][[1,3],[2,6],[8,10],[15,18]][[1,3],[2,6],[8,10],[15,18]][[1,3],[2,6],[8,10],[15,18]]
merged[][[1,3]][[1,6]][[1,6],[8,10]][[1,6],[8,10],[15,18]][[1,6],[8,10],[15,18]]
interval (current)N/A[1,3][2,6][8,10][15,18]N/A
Key Moments - 3 Insights
Why do we merge intervals by updating the end of the last merged interval?
Because overlapping intervals share some range, we extend the last merged interval's end to cover the new interval's end if it's larger, as shown in step 3 where [1,3] and [2,6] merge to [1,6].
Why do we append the interval if merged is empty or no overlap?
If merged is empty, there's nothing to merge with, so we add the first interval (step 2). If the current interval starts after the last merged interval ends, they don't overlap, so we add it separately (steps 4 and 5).
Why must intervals be sorted before merging?
Sorting ensures intervals are in order by start time, so overlapping intervals come one after another. Without sorting, we might miss overlaps, as the algorithm relies on comparing current interval with last merged interval (step 1).
Visual Quiz - 3 Questions
Test your understanding
Look at the execution table at step 3, what is the merged list after merging?
A[[1,6]]
B[[1,3]]
C[[2,6]]
D[[1,3],[2,6]]
💡 Hint
Check the 'Merged List After' column at step 3 in the execution table.
At which step does the condition 'no overlap' cause the interval to be appended to merged?
AStep 2
BStep 4
CStep 3
DStep 6
💡 Hint
Look for steps where the action says 'append' due to no overlap in the execution table.
If the intervals were not sorted, how would the merged list after step 2 change?
AIt would be empty
BIt would contain all intervals merged
CIt would contain only the first interval unsorted
DIt would cause an error
💡 Hint
Refer to the variable_tracker and concept_flow about sorting before merging.
Concept Snapshot
Merge Overlapping Intervals:
1. Sort intervals by start time.
2. Initialize empty merged list.
3. For each interval:
   - If merged empty or no overlap, append.
   - Else merge by updating last interval's end.
4. Return merged list with no overlaps.
Full Transcript
To merge overlapping intervals, first sort the intervals by their start times. Then create an empty list called merged. Go through each interval in order. If merged is empty or the current interval does not overlap with the last interval in merged, add it to merged. If it overlaps, update the end of the last interval in merged to cover the current interval's end if it is larger. Continue until all intervals are processed. The result is a list of intervals with no overlaps.