Hash Table Concept and Hash Functions in DSA Python - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create an empty hash table using a dictionary.

DSA Python

hash_table = [1]

Drag options to blanks, or click blank then click option'

A{}

B[]

C()

Dset()

Attempts:

3 left

💡 Hint

Common Mistakes

Using square brackets creates a list, not a dictionary.

Using parentheses creates a tuple, which is not a hash table.

In Python, an empty dictionary is created using curly braces {}. This is used to represent a hash table.

2fill in blank

medium

Complete the code to add a key-value pair to the hash table.

DSA Python

hash_table['apple'] = [1]

Drag options to blanks, or click blank then click option'

A1

BTrue

C'fruit'

DNone

Attempts:

3 left

💡 Hint

Common Mistakes

Using a number instead of a descriptive string.

Using None which means no value.

We assign the value 'fruit' to the key 'apple' in the hash table.

3fill in blank

hard

Fix the error in the hash function to return a valid index.

DSA Python

def hash_function(key, size):
    return sum(ord(char) for char in key) [1] size

Drag options to blanks, or click blank then click option'

A*

B%

C//

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using multiplication or addition changes the value incorrectly.

Using floor division (//) does not keep the index within range.

The modulo operator % ensures the hash value fits within the table size.

4fill in blank

hard

Fill both blanks to create a hash table with keys from a list and values as their lengths.

DSA Python

hash_table = {word: [1] for word in words if len(word) [2] 3}

Drag options to blanks, or click blank then click option'

Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as value instead of its length.

Using less than (<) instead of greater than (>) in the condition.

The dictionary comprehension assigns the length of each word as value only if the word length is greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys, values as word lengths, and filter words longer than 4.

DSA Python

result = [1]: [2] for word in words if len(word) [3] 4}

Drag options to blanks, or click blank then click option'

Aword.upper()

Blen(word)

C>

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase keys instead of uppercase.

Using less than (<) instead of greater than (>) in the condition.

Using the word itself as value instead of its length.

This comprehension creates keys as uppercase words, values as their lengths, and includes only words longer than 4 characters.

Practice

1. What is the main purpose of a hash function in a hash table?

easy

A. To encrypt the data stored in the table

B. To sort the keys in ascending order

C. To convert a key into an index for storing data

D. To count the number of elements in the table

Solution

1. Step 1: Understand the role of a hash function

   A hash function takes a key and converts it into a number that can be used as an index in the hash table.

2. Step 2: Compare with other options

   Sorting keys, encrypting data, or counting elements are not the main roles of a hash function in a hash table.

3. Final Answer:

   To convert a key into an index for storing data -> Option C

4. Quick Check:

   Hash function = key to index [OK]

Hint: Hash function maps keys to indexes fast [OK]

Common Mistakes:

• Thinking hash function sorts keys
• Confusing hash function with encryption
• Assuming hash function counts elements

2. Which of the following is the correct syntax to define a simple hash function in Python that returns the remainder of a key divided by 10?

easy

A. def hash_func(key): return key % 10

B. def hash_func(key): return key / 10

C. def hash_func(key): return key * 10

D. def hash_func(key): return key + 10

Solution

1. Step 1: Identify the correct modulus operation

   The hash function should return the remainder when key is divided by 10, which is done using the modulus operator '%'.

2. Step 2: Check syntax correctness

   def hash_func(key): return key % 10 uses 'return key % 10' which is correct syntax and logic. Other options use division, multiplication, or addition which do not produce the remainder.

3. Final Answer:

   def hash_func(key): return key % 10 -> Option A

4. Quick Check:

   Use % for remainder in hash function [OK]

Hint: Use % operator for remainder in hash functions [OK]

Common Mistakes:

• Using division instead of modulus
• Multiplying or adding instead of modulus
• Incorrect function syntax

3. What will be the output of the following code?

def simple_hash(key):
    return key % 5

hash_table = [None] * 5
keys = [12, 22, 17]
for key in keys:
    index = simple_hash(key)
    hash_table[index] = key
print(hash_table)

medium

A. [None, None, 12, 17, 22]

B. [None, None, 17, None, None]

C. [None, 22, 12, None, 17]

D. [None, 12, 22, 17, None]

Solution

1. Step 1: Calculate hash indexes for each key

   12 % 5 = 2, 22 % 5 = 2, 17 % 5 = 2. All three keys map to the same index 2.

2. Step 2: Trace the assignments

   The code assigns directly to hash_table[index] with no collision handling, so later keys overwrite earlier ones at index 2: 12 -> 22 -> 17. Final state: [None, None, 17, None, None].

3. Final Answer:

   [None, None, 17, None, None] -> Option B

4. Quick Check:

   All keys hash to index 2, last key stored [OK]

Hint: Check hash index for each key carefully [OK]

Common Mistakes:

• Assuming keys store at different indexes without collision
• Ignoring overwriting in hash table
• Miscomputing modulus

4. Identify the error in the following hash function code:

def hash_func(key):
    return key // 10

hash_table = [None] * 10
index = hash_func(25)
hash_table[index] = 25
print(hash_table)

medium

A. No error, code runs correctly

B. hash_table size is too small for keys

C. Function should return key * 10 instead

D. Using integer division instead of modulus causes wrong indexing

Solution

1. Step 1: Understand the hash function logic

   The function uses integer division '//' which divides key by 10 and returns the quotient, not the remainder.

2. Step 2: Check impact on indexing

   For key=25, 25 // 10 = 2, which is a valid index but this is not a typical hash function behavior. Usually, modulus '%' is used to get remainder for index within table size.

3. Step 3: Identify the error

   Using '//' can cause indexes outside the hash table size if keys are large. Modulus '%' should be used to ensure index is within table size.

4. Final Answer:

   Using integer division instead of modulus causes wrong indexing -> Option D

5. Quick Check:

   Use % for index, not // [OK]

Hint: Use % to keep index within table size [OK]

Common Mistakes:

• Confusing integer division with modulus
• Ignoring table size limits
• Assuming code runs without error

5. You want to design a hash function for strings that returns an index between 0 and 9 for a hash table of size 10. Which of the following functions correctly implements this?

hard

A. def hash_func(s): return sum(ord(c) for c in s) % 10

B. def hash_func(s): return len(s) * 10

C. def hash_func(s): return ord(s[0])

D. def hash_func(s): return s.count('a')

Solution

1. Step 1: Understand the requirement

   The hash function must return an integer index between 0 and 9 for any string input.

2. Step 2: Analyze each option

   def hash_func(s): return sum(ord(c) for c in s) % 10 sums ASCII values of all characters and uses modulus 10 to keep index in range 0-9. def hash_func(s): return len(s) * 10 multiplies length by 10, which can exceed 9. def hash_func(s): return ord(s[0]) returns ASCII of first char, which can be larger than 9. def hash_func(s): return s.count('a') counts 'a's, which can be any number, possibly larger than 9.

3. Step 3: Choose correct function

   Only def hash_func(s): return sum(ord(c) for c in s) % 10 guarantees index in 0-9 range for any string.

4. Final Answer:

   def hash_func(s): return sum(ord(c) for c in s) % 10 -> Option A

5. Quick Check:

   Sum ASCII % table size for string hash [OK]

Hint: Sum ASCII codes and mod by table size [OK]

Common Mistakes:

• Using string length times 10 as index
• Using ASCII code directly without modulus
• Using character count without range check