Get Length of Linked List in DSA Python - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to initialize the length counter to zero.

DSA Python

def get_length(head):
    length = [1]
    current = head
    while current:
        length += 1
        current = current.next
    return length

Drag options to blanks, or click blank then click option'

A0

B1

Chead

DNone

Attempts:

3 left

💡 Hint

Common Mistakes

Starting length at 1 instead of 0

Setting length to None

Assigning length to head

We start counting from zero because the list might be empty.

2fill in blank

medium

Complete the code to move to the next node in the linked list.

DSA Python

def get_length(head):
    length = 0
    current = head
    while current:
        length += 1
        current = [1]
    return length

Drag options to blanks, or click blank then click option'

Ahead.next

Bcurrent

Ccurrent.next

Dlength.next

Attempts:

3 left

💡 Hint

Common Mistakes

Using head.next instead of current.next

Assigning current to itself causing infinite loop

Using length.next which is invalid

To move forward, we assign current to the next node.

3fill in blank

hard

Fix the error in the loop condition to correctly check if the current node exists.

DSA Python

def get_length(head):
    length = 0
    current = head
    while [1]:
        length += 1
        current = current.next
    return length

Drag options to blanks, or click blank then click option'

Acurrent == None

Bcurrent is not None

Chead

Dlength

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'current == None' which is less preferred

Using 'head' which does not change in the loop

Using 'length' which is an integer

The loop should continue while current is not None.

4fill in blank

hard

Fill both blanks to create a dictionary with word lengths for words longer than 3 characters.

DSA Python

words = ['apple', 'bat', 'carrot', 'dog']
lengths = {word: [1] for word in words if len(word) [2] 3}

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Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>'

Using 'word' instead of 'len(word)'

Not filtering words by length

We want the length of each word and only include words longer than 3 characters.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values greater than zero.

DSA Python

data = {'a': 1, 'b': 0, 'c': 3}
result = [1]: [2] for k, v in data.items() if v [3] 0}

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Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'k' instead of 'k.upper()' for keys

Using '<' instead of '>' for filtering

Including values equal to zero

Keys are converted to uppercase, values are included if greater than zero.