Evaluate Postfix Expression Using Stack in DSA Python - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is a postfix expression?

A postfix expression is a way of writing math expressions where the operator comes after the numbers. For example, instead of writing 3 + 4, we write 3 4 +.

beginner

Why do we use a stack to evaluate postfix expressions?

We use a stack because it helps us keep track of numbers and apply operators in the right order. When we see a number, we push it on the stack. When we see an operator, we pop numbers, calculate, and push the result back.

beginner

What happens when an operator is encountered in a postfix expression during evaluation?

When an operator is found, we pop the top two numbers from the stack, apply the operator to these numbers (second popped number first), then push the result back onto the stack.

intermediate

Show the step-by-step stack changes when evaluating the postfix expression: 2 3 + 5 *

Start with empty stack: [] Push 2: [2] Push 3: [2, 3] Operator +: pop 3 and 2, add 2+3=5, push 5: [5] Push 5: [5, 5] Operator *: pop 5 and 5, multiply 5*5=25, push 25: [25] Final stack: [25]

beginner

What is the final result of evaluating a postfix expression using a stack?

After processing the whole expression, the stack will have exactly one number left. This number is the final result of the postfix expression.

What is the first step when you see a number in a postfix expression during evaluation?

A Apply an operator

B Push the number onto the stack

C Pop two numbers from the stack

D Ignore the number

Numbers are pushed onto the stack to be used later when an operator is found.

In postfix evaluation, when an operator is encountered, which numbers do you pop from the stack?

A No numbers are popped

B Only the top number

C All numbers in the stack

D The top two numbers, with the second popped as the left operand

You pop the top two numbers; the second popped is the left operand, the first popped is the right operand.

What will be the stack after evaluating the postfix expression '4 2 /'?

A [2]

B [0.5]

C [2, 4]

D [4, 2]

4 and 2 are pushed, then '/' operator divides 4 by 2, result 2 is pushed back.

What is the final step after processing all tokens in a postfix expression?

A The stack should have exactly one number, the result

B The stack should be empty

C The stack should have multiple numbers

D The stack should have only operators

The final result is the only number left on the stack after evaluation.

Which data structure is best suited for evaluating postfix expressions?

A Queue

B Linked List

C Stack

D Array

Stack allows easy push/pop operations needed for postfix evaluation.

Explain how to evaluate a postfix expression using a stack step-by-step.

Think about what you do when you see a number vs an operator.

Describe why a stack is the right data structure for postfix expression evaluation.

Consider how operators need the most recent numbers.

Practice

1. What does evaluating a postfix expression using a stack mainly involve?

easy

A. Using recursion to evaluate the expression

B. Converting the postfix expression to infix before evaluation

C. Pushing operands onto the stack and popping two operands for each operator to apply the operation

D. Ignoring operators and only summing operands

Solution

1. Step 1: Understand postfix evaluation process

   In postfix evaluation, operands are pushed onto a stack. When an operator is encountered, two operands are popped, the operation is applied, and the result is pushed back.

2. Step 2: Identify correct method

   Pushing operands onto the stack and popping two operands for each operator to apply the operation correctly describes this stack-based process. Other options describe unrelated or incorrect methods.

3. Final Answer:

   Pushing operands onto the stack and popping two operands for each operator to apply the operation -> Option C

4. Quick Check:

   Postfix evaluation uses stack push/pop [OK]

Hint: Remember: push operands, pop two for operator, push result [OK]

Common Mistakes:

• Thinking postfix needs conversion to infix first
• Trying to evaluate from left to right without stack
• Ignoring the order of operands when popping

2. Which of the following Python code snippets correctly pushes operands and evaluates a postfix expression using a stack?

easy

A. stack.append(int(char)) when char is digit; pop two, apply operator, push result

B. stack.push(char) for operands; pop one operand for operator

C. Use stack.pop() to push operands; stack.append() to pop

D. Directly evaluate expression without stack

Solution

1. Step 1: Check correct stack operations

   In Python, list's append() adds elements (push), pop() removes last element (pop). For postfix, push operands as integers, pop two for operator.

2. Step 2: Match with options

   stack.append(int(char)) when char is digit; pop two, apply operator, push result correctly uses stack.append(int(char)) for digits and pops two operands for operators. Others misuse push/pop or skip stack.

3. Final Answer:

   stack.append(int(char)) when char is digit; pop two, apply operator, push result -> Option A

4. Quick Check:

   Use append to push, pop to remove [OK]

Hint: Use append() to push and pop() to remove from stack [OK]

Common Mistakes:

• Using stack.push() which is not a Python list method
• Popping only one operand for operator
• Not converting char to int before pushing

3. What is the output of the following Python code that evaluates the postfix expression '231*+9-'?

def evaluate_postfix(expr):
    stack = []
    for char in expr:
        if char.isdigit():
            stack.append(int(char))
        else:
            b = stack.pop()
            a = stack.pop()
            if char == '+':
                stack.append(a + b)
            elif char == '-':
                stack.append(a - b)
            elif char == '*':
                stack.append(a * b)
            elif char == '/':
                stack.append(a // b)
    return stack.pop()

print(evaluate_postfix('231*+9-'))

medium

A. -4

B. -2

C. -3

D. 4

Solution

1. Step 1: Evaluate expression step-by-step

   Expression: '2 3 1 * + 9 -' - Push 2, 3, 1 - '*' operator: pop 1 and 3, multiply 3*1=3, push 3 - '+' operator: pop 3 and 2, add 2+3=5, push 5 - Push 9 - '-' operator: pop 9 and 5, subtract 5-9=-4, push -4

2. Step 2: Final result

   Pop final value from stack: -4

3. Final Answer:

   -4 -> Option A

4. Quick Check:

   Postfix '231*+9-' = -4 [OK]

Hint: Evaluate stepwise: push digits, apply operators on last two [OK]

Common Mistakes:

• Mixing operand order when popping (a, b vs b, a)
• Using float division instead of integer division
• Misreading the expression order

4. The following code is intended to evaluate a postfix expression but throws an error. What is the error and how to fix it?

def eval_postfix(expr):
    stack = []
    for char in expr:
        if char.isdigit():
            stack.append(char)
        else:
            a = stack.pop()
            b = stack.pop()
            if char == '+':
                stack.append(a + b)
            elif char == '-':
                stack.append(a - b)
    return stack.pop()

print(eval_postfix('23+'))

medium

A. SyntaxError due to missing colon; fix by adding colon after if

B. TypeError due to adding strings; fix by converting char to int before pushing

C. IndexError due to popping from empty stack; fix by checking stack size

D. No error; output is '5'

Solution

1. Step 1: Identify error cause

   The code pushes characters as strings onto stack. When popping, it tries to add strings, causing TypeError.

2. Step 2: Fix by converting to int

   Convert char to int before pushing: stack.append(int(char)) to allow arithmetic operations.

3. Final Answer:

   TypeError due to adding strings; fix by converting char to int before pushing -> Option B

4. Quick Check:

   Push integers, not strings, to avoid TypeError [OK]

Hint: Always convert digit chars to int before pushing [OK]

Common Mistakes:

• Pushing strings instead of integers
• Swapping operand order when popping
• Ignoring operator cases other than '+' and '-'

5. Given the postfix expression '56+82/-', what is the result after evaluating it using a stack? Show the step-by-step evaluation.

hard

A. 5

B. 1

C. 9

D. 7

Solution

1. Step 1: Evaluate postfix expression stepwise

   Expression: '5 6 + 8 2 / -' - Push 5, 6 - '+' operator: pop 6 and 5, add 5+6=11, push 11 - Push 8, 2 - '/' operator: pop 2 and 8, integer divide 8//2=4, push 4 - '-' operator: pop 4 and 11, subtract 11-4=7, push 7

2. Step 2: Final result

   Pop final value from stack: 7

3. Final Answer:

   7 -> Option D

4. Quick Check:

   Postfix '56+82/-' = 7 [OK]

Hint: Process operators on last two stack values in order [OK]

Common Mistakes:

• Dividing operands in wrong order (2/8 instead of 8/2)
• Using float division instead of integer division
• Mixing operand order when subtracting