Complete the code to initialize the low pointer at the start of the array.
def dutch_flag_partition(arr, pivot): low = [1] mid = 0 high = len(arr) - 1 while mid <= high: pass
The low pointer starts at index 0 to begin partitioning from the start.
Complete the code to swap elements when the mid element is less than the pivot.
def dutch_flag_partition(arr, pivot): low = 0 mid = 0 high = len(arr) - 1 while mid <= high: if arr[mid] < pivot: arr[low], arr[[1]] = arr[[1]], arr[low] low += 1 mid += 1
We swap arr[low] and arr[mid] when arr[mid] is less than pivot, then move both pointers forward.
Fix the error in the code to correctly handle the case when arr[mid] is greater than the pivot.
def dutch_flag_partition(arr, pivot): low = 0 mid = 0 high = len(arr) - 1 while mid <= high: if arr[mid] > pivot: arr[mid], arr[[1]] = arr[[1]], arr[mid] high -= 1
When arr[mid] is greater than pivot, swap arr[mid] with arr[high] and decrease high pointer.
Fill both blanks to complete the while loop that partitions the array correctly.
def dutch_flag_partition(arr, pivot): low = 0 mid = 0 high = len(arr) - 1 while [1] <= [2]: if arr[mid] < pivot: arr[low], arr[mid] = arr[mid], arr[low] low += 1 mid += 1 elif arr[mid] > pivot: arr[mid], arr[high] = arr[high], arr[mid] high -= 1 else: mid += 1
The loop continues while mid is less than or equal to high to process all elements.
Fill all three blanks to create a dictionary comprehension that counts elements less than, equal to, and greater than the pivot.
def count_partition(arr, pivot): return { [1]: sum(1 for x in arr if x [2] pivot) for [3] in ['less', 'equal', 'greater'] }
The comprehension iterates over keys and counts elements matching the condition x == pivot for 'equal'.