Complete the code to check if the list is empty before deletion.
if self.head is [1]: return
We check if self.head is None to know if the list is empty.
Complete the code to move to the next node in the list during traversal.
current = current.[1]To traverse forward, we move to the next node.
Fix the error in updating the previous node's next pointer after deletion.
if current.prev is not None: current.prev.[1] = current.next
We update the next pointer of the previous node to skip the deleted node.
Fill both blanks to correctly update the next node's previous pointer and handle tail update.
if current.next is not None: current.next.[1] = current.prev else: self.[2] = current.prev
The next node's prev pointer should skip the deleted node. If there is no next node, update the tail.
Fill all three blanks to complete the delete by value method in a doubly linked list.
def delete_by_value(self, value): current = self.head while current is not None: if current.data == [1]: if current.prev is not None: current.prev.[2] = current.next else: self.head = current.next if current.next is not None: current.next.[3] = current.prev else: self.tail = current.prev return current = current.next
We compare current.data with value. Then update pointers: previous node's next and next node's prev.