Complete the code to initialize the count variable to zero.
def count_set_bits(n): count = [1] while n > 0: n = n & (n - 1) count += 1 return count
We start counting from zero because initially no bits are counted.
Complete the code to update n by removing the rightmost set bit.
def count_set_bits(n): count = 0 while n > 0: n = n [1] (n - 1) count += 1 return count
Using bitwise AND with (n - 1) removes the rightmost set bit from n.
Fix the error in the loop condition to correctly count set bits.
def count_set_bits(n): count = 0 while n [1] 0: n = n & (n - 1) count += 1 return count
The loop should run while n is greater than zero to count all set bits.
Fill both blanks to create a dictionary comprehension that maps numbers to their set bit counts.
numbers = [3, 5, 7, 9] set_bits_count = { [1]: count_set_bits([2]) for [1] in numbers }
Use the same variable name 'num' for keys and as argument to count_set_bits.
Fill all three blanks to filter numbers with more than one set bit and create a dictionary of their counts.
numbers = [1, 2, 3, 4, 5] filtered_counts = { [1]: count_set_bits([2]) for [1] in numbers if count_set_bits([3]) > 1 }
Use 'num' consistently for iteration, function argument, and condition variable.